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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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1 R5 o9 l8 u" v2 |( \5 g: t5 s不好意思,打错了个字母,呵呵呵!: p/ Z+ p0 G" s- s
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
5 [% _8 a! G& b4 Y7 [9 B1 I“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!. I: d n2 Q) _1 u% \
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j,k,nstep,c, scheduleteps,mincomptime:integer;
) z* W: x1 A4 C6 o M:string;2 j X, l" O6 J E+ l
selecTab:table[integer,integer,integer,string];
5 Z$ i4 [6 J2 J. c& ?, L, `4 ]do
0 L! O' J0 Z9 P& m) h) Q initorders;
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1 e3 o d0 m2 Z! M6 f% n scheduledorders.delete;9 s# }5 a( P- g7 G+ u
seletTab.create;# E% b& [6 Z( s* H
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orders.initialize({2,1}..{2,*},0);
6 T" Z' |) k. |$ t; [- L1 m( R6 r orders.initialize({4,1}..{4,*},0);% p2 {! ]0 \. q
for j:=1 to numorders loop5 v9 {& t9 |" g. N# ~& v- d9 f
orders[5,j]:=orders[1,j][2,1];
1 M+ w }% k( d2 O+ { next;
' |$ ~: P D, X( m occres.initialize({1,1}..{1,*},0);
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( r! p3 X8 k0 m3 W0 Z+ i( |# B --XUNHUAN! |' L( B: Q5 {) c) `
for scheduledsteps:=1 to numsteps loop --2 e# M( T2 e: I. J' I% y$ q2 ]
selectab.delete;
0 c: ?0 |. q. O1 V0 e& S k:=1;/ Y7 b1 p3 ^ w- k$ P1 C
for j:=1 to numorders loop
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7 |6 T; r. V( ?8 v8 r, S# F3 j2 K nstep:=orders[2,j]+1;
% b* c( G; Y& e if nstep<=orders[3,j] then. k l8 R1 ]3 _* ^+ h0 j, i1 \! V
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];6 m7 q$ {. ^( {$ e
k:=k+1;$ y3 |- ~9 \$ h( ^. \
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end;
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mincomptime:=selecttab.min({3,1}..{3,*});# ^2 u4 \ J8 S9 z; d/ j
; a/ _: x" i9 S0 y4 D7 g1 @5 |" q from j:=1 until j>selectab.ydim loop& o$ k* V! @1 D9 Q, ^" [/ }
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if selectab[2,j]<mincomptime then
4 \/ ?4 S. T1 I+ N8 V j:=j+1;3 M/ w5 o: K# q7 r+ K/ g6 E% p
else
) x- X [" _) m6 e) ?; r9 H selecttab.cutrow(j);% U& H. D( \7 A- i$ A& I
end;2 p5 n6 ]6 |2 @! |4 V8 @+ P5 s7 e
end;# U5 d, y- N8 T! s( L% ^& J
! p7 }# k/ U( I5 A j:=selectionrule(selecttab);
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: c" ^: K9 E- U7 m6 A! ` nstep;+orders[2.j]+1;7 r) {! ^, E3 M- s3 u3 q
orders[2,j]:=nstep;
1 W9 H' c, D* k1 d K _+ a m:=orders[1,j][1,nstep];" l {5 a2 D: s$ l
c:=orders[5,j]
4 F |7 i4 f8 `, f2 _$ E2 g2 L occres[1,m]:=c;
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--jieguo:start,end,res,job,step% D/ B- T3 u) H
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);/ M+ ?. j/ j2 a& z, J I9 q+ F4 u
for k:=1 to numorders loop
) F _$ S7 T7 _. ~! a9 w( D2 P nstep:=orders[2,k]+1;( S. I0 c4 f( D; W
8 b& m4 H1 C5 H+ H if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
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then' ^+ s# N# F. G/ A1 C5 _0 q
orders[4,k]:=max(c,orders[4,k]);
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orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
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end;1 d% d; Y( ` u0 \
next;( X* A# C- o2 W4 Z$ Y& K
nstep:=orders[2,j]+1:
. E, E& d7 Q+ t, \3 \ if nstep<=orders[3,j]
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then3 ?: [& [/ u8 R, L" N, G
orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
. L5 h+ t* g p' ?' v, L' i6 d orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];3 z- C0 \! W6 v2 o4 O
end;
0 @, L2 D1 t) X" L next;# W. r4 I- `% F o
$ W3 j# q8 d7 c x print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});% c' F% _2 N( c7 m4 I
mygantt;7 B; o8 P5 G' N8 O6 x
ens;4 ]5 r8 @4 H: }
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