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发表于 2010-5-11 13:19:52
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用list吧* Y" b1 y$ H/ R- b7 E( o9 K
patches-own [wealth rank]8 Z+ H! S( y0 `6 X
to setup9 K% ^$ z$ j4 @$ \$ w* l, q( f
ca* K' V% Q" K m& V2 r. i0 W( w4 M
ask patches [set wealth random 100 set pcolor green ]
% w3 L) t0 l1 \# Y9 @: @0 Rend% r; [. n" N* Z+ k& Q% p. w2 x4 Q3 i
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let mylist1 []
$ s/ w: m `; c; c( t set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches; S6 L3 t" @+ Y% l+ o5 W2 n/ I
let mylist2 []
. ^6 Y" ?( U6 S$ G% w set mylist2 n-values count patches [? + 1]$ D* N5 Z$ v4 W8 B: p) O
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( foreach mylist1 mylist2
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9 K) u7 v$ j1 |' K0 q ask ?1[ set rank ?2]
- `* B# Y) K9 z6 ?% ^' E show [rank] of ?1
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]
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2 Y# J( z$ m" y4 \1 A2 j* S let mylist3 []
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, g& u" K/ ]- r0 C5 I5 H" G4 U set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches1 C$ e5 S; { F1 ?7 p$ d0 s0 g
show count patches8 P/ D5 p( b$ N1 P/ J
show mylist1 3 B, J1 `7 J: h r3 A
show mylist34 a3 ]) N) C/ z( _0 F# ?' w2 C' x
end
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1 g! l5 A# Z9 P+ n这时的mylist1 和mylist3 应该是一样的 |
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