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发表于 2010-5-11 13:19:52
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用list吧9 g# r6 o& I, ?
patches-own [wealth rank]
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ca
4 `' O6 @' l- Y) i$ c ask patches [set wealth random 100 set pcolor green ]1 Z) d4 p0 D% x% g% d
end
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1 Q/ S) }- q5 I0 A1 hto go
0 q2 v: m) P l. V% w8 E let mylist1 [] u' ~; v, i. B# t/ U2 Z
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
9 o1 ^. S4 O! x9 ~3 X { let mylist2 []
! H$ z1 {( D" s1 o% R8 M! S4 f. c set mylist2 n-values count patches [? + 1]$ j' l2 O5 e, b
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( foreach mylist1 mylist2
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ask ?1[ set rank ?2]
0 j; [$ J* u+ H1 [/ E- c( W show [rank] of ?1; ^, ~: X+ z! i- x! D, u
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]
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5 r. |+ w$ H$ q8 |9 r9 E let mylist3 []. z* Z* Z9 W5 r. o0 h
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
6 k9 O) F T9 R% ^ show count patches
* F- @& ], n, e- O4 t3 Z( K) z show mylist1 , w Q, n8 c9 r. V, [/ X+ K' i
show mylist31 C; p) w' m! g! z
end0 ]. `! v* J. e
1 k6 o7 \) d. T4 T+ d; D" h这时的mylist1 和mylist3 应该是一样的 |
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