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发表于 2010-5-11 13:19:52
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用list吧0 q* L" H9 W& R, k
patches-own [wealth rank]
( @" x/ v# _# \2 q1 i! ]. W5 hto setup; R3 I$ p* r0 N7 K
ca1 p4 \# R5 F8 b6 d! G5 I- ~
ask patches [set wealth random 100 set pcolor green ]
7 \# z1 E. ~$ C9 x5 xend
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to go
. q! D0 C7 `: C/ x let mylist1 []
( A- W4 X6 E! N" n! \/ z set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches ?8 L4 s m+ k6 m( m' K/ H
let mylist2 []
4 B+ \5 v1 X. T& a r set mylist2 n-values count patches [? + 1]7 i" D6 `. b6 j$ p9 M+ `
, |* `# S( Y( F k$ D2 k
( foreach mylist1 mylist26 g2 j) v5 o2 ~8 h& A3 J
[
& A( a: x! k$ |7 T6 ^: |1 y ask ?1[ set rank ?2]7 k, }1 w6 w4 f9 b' H
show [rank] of ?1
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let mylist3 []1 D' s P( ]4 {7 L
1 P, L/ t9 {$ i set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
) d4 q0 n) m% }9 h6 U. F2 h show count patches/ a o V% k$ T" [! v* T) _
show mylist1
. z( ^% F- ^& R; U+ E+ m$ E# A" K show mylist31 V& T' W& f* b8 o' y
end
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这时的mylist1 和mylist3 应该是一样的 |
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