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发表于 2010-5-11 13:19:52
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用list吧# H3 j- l& T, ?4 Y- Y) ^
patches-own [wealth rank]
$ G a% |# R* t0 S- eto setup
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, B- q, X, _3 {! V8 }; I2 |5 w2 O8 | ask patches [set wealth random 100 set pcolor green ]
( H2 Y2 Y% u9 g0 i% k+ Cend
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to go* @" {9 G# g. b/ L7 l& {8 R
let mylist1 []
- T, a, d$ Q7 N1 Q. b9 R3 b) |8 T3 l set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
: p2 ^% p. d- c7 e let mylist2 []
' W; Z% c7 ~4 t& |5 h; J5 d set mylist2 n-values count patches [? + 1]/ N$ a6 P" ^" ~' @9 }: \5 @
' F# F" n: X9 h1 \1 U H6 J ( foreach mylist1 mylist23 D" Y7 z% z/ x2 p
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ask ?1[ set rank ?2]5 e& b- b9 N1 M8 |
show [rank] of ?1
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]
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! e' b( s$ l5 F5 ? let mylist3 []4 D0 V/ l! z$ r `, a
2 _8 j4 o0 H( R5 ]; D! l! s% J set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches7 l, ^" `( x- L2 a
show count patches
( Z4 K' _$ S1 d8 O* t! f show mylist1
6 n3 h: E+ d! A2 I1 p show mylist3( x$ W' `9 ]. `+ N8 p2 n" Q4 i
end( V( @2 r! D2 b. [) J& _
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这时的mylist1 和mylist3 应该是一样的 |
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