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发表于 2010-5-11 13:19:52
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用list吧
( s1 M- ~% {5 _4 n8 zpatches-own [wealth rank]
2 _2 k# L) f: @1 I) w( ]to setup
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ask patches [set wealth random 100 set pcolor green ]
9 v) s8 Q1 Z# S ]+ G# pend
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to go
' u/ ^1 ~/ R; Z. u# I& }' h$ P let mylist1 []
, W0 T9 p0 O: M; z/ L* Y set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches$ c# V" O1 I; p' F* R: [
let mylist2 []: |0 D: x' h9 n- i" d9 T6 X+ c' C3 _
set mylist2 n-values count patches [? + 1]
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9 J+ o r5 l8 \' z, A. b ( foreach mylist1 mylist2
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ask ?1[ set rank ?2], I, [+ k5 u v" ^3 h+ D, p
show [rank] of ?11 _+ J( L: X2 @2 ?# k0 X: W# P
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]
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+ f; r7 m( e* f, e: x let mylist3 []
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- }- E$ [- J4 h set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
4 L5 p% O0 c5 H9 _/ F6 g& B show count patches% _7 ]) {2 m% b* {3 V/ O
show mylist1 # X4 D* g9 ? H7 R. u7 [
show mylist3 Z. f& N+ j7 r* E5 |7 }
end
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7 Y8 B; U+ C+ x这时的mylist1 和mylist3 应该是一样的 |
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