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发表于 2010-5-11 13:19:52
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用list吧
4 m! V0 C r4 v5 {$ y" q/ epatches-own [wealth rank]
2 {" z* Y+ I& y' Pto setup
% Q# p1 h: ^7 C: ^4 |" H$ W ca
- E, v; h, B3 M: n1 u ask patches [set wealth random 100 set pcolor green ]
, j$ [7 w q+ J cend+ p5 O4 B3 _3 @" L T* g9 b
8 n, P* Q$ M4 V/ E" ~" Mto go) C+ x4 G; @; ]
let mylist1 []1 z: h1 J/ y% _' G
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches6 Z' v3 R; w# h7 j3 N
let mylist2 []
2 y8 \% |' S% T) j. o3 l3 i set mylist2 n-values count patches [? + 1]
# x* m2 w/ \9 j: W " J6 ?4 n9 w C
( foreach mylist1 mylist2
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ask ?1[ set rank ?2]; k5 a, s5 r9 F: Y% [, j% C
show [rank] of ?1
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]
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9 z" X8 V; @. X0 p6 x let mylist3 []
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
' K, _1 p# c8 n2 C' g4 a' ~/ s: ~ show count patches1 v3 P5 d. z0 ^) d/ G
show mylist1
0 H! l: n0 T6 z! z, k E0 } show mylist3
5 p7 Z* ~, P1 r1 v& W/ Pend
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这时的mylist1 和mylist3 应该是一样的 |
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