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发表于 2010-5-11 13:19:52
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用list吧1 X* S+ c' U# L9 X4 p
patches-own [wealth rank]1 r6 s+ ]* w' F
to setup G0 V: v3 e2 J& u: m
ca
2 Z$ a; _# o# u, g8 h# o5 _ ask patches [set wealth random 100 set pcolor green ], W: T+ F* Z) Q" Y, R* P
end" X. g( ]2 k# f' t f+ t
& G. b4 f3 X5 _/ E; N! M! N u$ ]to go
* |4 t3 w2 t5 K* _, Y; g( R let mylist1 []
) U+ r& W& i+ V* x$ _3 R; o, v set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
4 e Z' |. x1 x( m( T let mylist2 []* K& I) I$ g8 D$ f1 \2 `6 g/ k
set mylist2 n-values count patches [? + 1]1 z" H7 Y# [, O# d- b1 W
8 s7 j+ y. k7 I, O. A
( foreach mylist1 mylist2
' A" R4 p+ n$ A7 W f$ \* O" U [
9 L9 j% R! I2 ~ ask ?1[ set rank ?2]- j1 p/ Y9 R: N* F1 p& U
show [rank] of ?1
8 a5 d, }, J$ G) ~" h- u . p, Q# n6 E+ I b# @) Q3 i
]
, ]! Q& r9 @- B) j/ f )/ U# o& j0 ^! i8 {* \& H
let mylist3 []5 k* B# Q4 h! y% B
, @( B( [ X* W. A, x' G+ b0 m J# x set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches, f2 r: p& E/ u% u, o0 S
show count patches
0 c- m# K# d% t; R0 j* E% O& k show mylist1 + w' f4 C/ T% Y9 m3 D
show mylist3
2 p$ d: e" {/ B* c" t# i& _" qend
' f$ t/ e* ~4 _' g5 b& g+ l' z# R. z
: n& n" b7 b o2 `+ D( H这时的mylist1 和mylist3 应该是一样的 |
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