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发表于 2010-5-11 13:19:52
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用list吧( ]+ B3 d6 v) q+ S
patches-own [wealth rank]
+ _: e- R0 b% ^' B1 ?* Pto setup
" {' g; n9 D: P7 a0 e( f ca
9 {5 k$ Q+ W( C ask patches [set wealth random 100 set pcolor green ]
4 w9 l9 G( ^) S2 Y) |end
% {4 y m1 y" @* V! b1 M9 d3 t2 i6 \: Z% n n! w9 \6 R
to go* I& P9 |- B+ u3 d# ]+ d
let mylist1 []
- a# i0 ?/ ]0 c9 l5 [ set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
4 ~ U& T/ m, [0 R8 p let mylist2 []
# s' W4 x9 G0 c1 {) S) f set mylist2 n-values count patches [? + 1] d5 A. M; G, ]
7 Y) Q( O( y2 d5 G. z+ W ( foreach mylist1 mylist2
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ask ?1[ set rank ?2]
& c* G8 U" i$ n) ]" F5 e show [rank] of ?1$ }2 r, q2 r% K3 u) G: u2 c4 c
0 w& a) V% S/ D# o ]
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let mylist3 []
3 n7 q+ h% t, A% \
! G4 \) F- w& e( q5 Z4 a( \9 E1 f set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
" ?8 e4 n) y0 x; n) ^% e show count patches
/ L; U X+ Q5 D; c; N J0 T show mylist1
" P+ p3 h5 C( {4 r4 y show mylist3
5 c0 C" y* \$ bend
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这时的mylist1 和mylist3 应该是一样的 |
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