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发表于 2010-5-11 13:19:52
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用list吧6 i' S& x2 c: M# p
patches-own [wealth rank]( P: L: V* q+ v9 n X
to setup+ Q7 r; ^( ^' }- [
ca
* ~" Z8 @( J% X1 ], h- Z# r ask patches [set wealth random 100 set pcolor green ]
4 E) p# d8 h; p$ [% Xend& z4 F9 O0 Y3 E+ Z
& M& }. i! M% T2 dto go
5 A/ U+ ]% o1 [& L let mylist1 []4 J/ C" D! f; h; V
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
0 |4 @, r E/ e: |) ? let mylist2 []
. ^2 @1 y8 Y& \' P4 E+ k3 W0 z set mylist2 n-values count patches [? + 1]
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( foreach mylist1 mylist2
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8 B" e6 L1 ?+ |1 h ask ?1[ set rank ?2]1 Y- G+ @0 h* X) j' C
show [rank] of ?10 n: k* x7 O. [7 h" }. X
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]
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. l$ W" p" a, S0 c+ z% p let mylist3 []
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# L9 \7 ~& t) j+ F set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
: _$ |5 e0 b0 K) T/ y9 L7 T3 V show count patches
" l* K8 ^5 o1 u, ^; Q, j, K, r show mylist1 / M3 X7 `1 X1 V
show mylist3+ G$ l. M7 R2 h: f u6 @7 T5 l
end
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1 i n) [6 _2 K' h* E# Q3 y这时的mylist1 和mylist3 应该是一样的 |
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