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发表于 2010-5-11 13:19:52
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用list吧
0 e: \% V% W1 ?+ G' V* Epatches-own [wealth rank]2 }+ y n& r0 }1 K' V( t
to setup$ O$ ?" e8 w' B. }; T- V
ca6 d# N$ F) }3 J( s: Q
ask patches [set wealth random 100 set pcolor green ]: i" O% L) ~( x; m3 p# x/ {* s
end4 z/ H4 e' v4 D" b
1 Z7 B8 i8 i) M6 B; x* X0 p3 u0 Vto go
, u- C8 Z+ i5 u; z$ O$ ] let mylist1 []
1 V2 X" D8 i0 s2 P$ p/ H. i* _ set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches" J7 y7 K7 b" B2 L# T1 {/ a
let mylist2 []+ R' H' q2 `3 p8 I
set mylist2 n-values count patches [? + 1]
+ Y! H1 S% A( e/ |! x- q! W ' i4 E! B- I. y, m1 ?' Q
( foreach mylist1 mylist2
1 ?9 T0 Q/ i, O [
% |: P6 e. m, S2 H$ m) \# G0 ?8 K ask ?1[ set rank ?2]
- `) A1 z& Q- q show [rank] of ?1* w' A9 w9 q! A4 X X
1 o! b/ z Q0 e3 \1 K ]
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let mylist3 []9 w A' K( u" }
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches7 F9 ?7 _/ h9 l; U
show count patches
; ~" ?! A$ @& e; G show mylist1
x1 E: ? [, E6 n4 D& W show mylist3
: S; ~$ ]; \7 |; [) n, K3 ]end/ T4 e+ |. v+ h
! p6 W+ a; U3 r! e5 W这时的mylist1 和mylist3 应该是一样的 |
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