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发表于 2010-5-11 13:19:52
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用list吧* F; `2 i6 {2 E# ?; ^4 {
patches-own [wealth rank]
: d- f8 g) @6 Q6 Jto setup
8 X3 Y/ S4 T5 l. O6 G Q8 i* E ca7 ~1 a* Y6 ]1 B, `, S1 v1 l+ y
ask patches [set wealth random 100 set pcolor green ]! \2 C: L! j( j! H6 n: {* O
end# }: L* \' {8 b5 g
+ O5 M- v! O1 N5 T+ b1 G4 G* n
to go5 @' P8 |" S1 O$ C8 w% i- O
let mylist1 []$ a6 j' C) J" f* U
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
; K5 D1 J6 ~$ Z6 Y! T* R4 p let mylist2 []
: |8 j. T9 b6 W4 a3 n, z set mylist2 n-values count patches [? + 1]
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( foreach mylist1 mylist2 q3 {0 W2 Z/ ^6 S" [6 P! s
[
+ z2 K+ F7 n# W2 Y, O ask ?1[ set rank ?2]4 s) p) }) {6 ]
show [rank] of ?1) V6 J: F; ~! A; B i5 R8 q
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8 @ W. F. r$ ~' E; T* h9 T let mylist3 []
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# s& C; G5 a+ z set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches) g! l& W) t1 M# z! X
show count patches
; l4 o6 h; Y$ p5 x1 y show mylist1 . i) f# I/ L3 O+ Z+ W
show mylist3
3 S1 W" K0 W Y- m. K- I1 hend
+ X9 z3 l$ K9 ?- ~
. M' a* k$ t% Y9 A! n( |2 d这时的mylist1 和mylist3 应该是一样的 |
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