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发表于 2010-5-11 13:19:52
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用list吧: e. y. c3 _1 o c( |. G; V: K
patches-own [wealth rank]
5 d8 J' j1 A& K5 C! B; K. Fto setup
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ask patches [set wealth random 100 set pcolor green ]. f1 t( q5 E& G$ u1 H( ^4 U P
end
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let mylist1 []1 U3 o; P' j7 F" ?6 x' V
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches3 u0 Q2 t* h2 N6 W
let mylist2 []) Y1 n9 h0 E% j7 F2 O [# w
set mylist2 n-values count patches [? + 1]
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( foreach mylist1 mylist2
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ask ?1[ set rank ?2]
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let mylist3 []! M4 z! H( V1 _& l5 J
, g1 e. H! r- W3 t' I set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
1 {6 l9 Y9 D8 ?" V. r+ ]+ I show count patches
$ X f, L2 Y0 ~$ r show mylist1 . N4 Q" ^. W, L }# r2 J
show mylist3
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3 t; n4 P% Q* F/ k2 }8 m) p. z8 Q这时的mylist1 和mylist3 应该是一样的 |
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