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发表于 2010-5-11 13:19:52
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用list吧8 V5 S+ K+ a! {" h; M' J
patches-own [wealth rank]
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ask patches [set wealth random 100 set pcolor green ]
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6 ~1 |5 Y# f: S( H" T# lto go
. I% h7 x" X2 v let mylist1 []
3 {- K' b: @' G4 M set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
8 e+ ]0 [: h. ]7 }9 ^ Z let mylist2 []: m5 T/ o+ O9 f$ _ i
set mylist2 n-values count patches [? + 1]
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( foreach mylist1 mylist2
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ask ?1[ set rank ?2]$ e3 N) S0 u+ t$ \6 _
show [rank] of ?1- G8 F' t: L/ T5 Z8 P
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]
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let mylist3 []
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; K1 d3 x o2 H6 z set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches' ^$ m) `# L/ H4 G1 Z
show count patches7 i8 {+ G) j1 m% A; |* a7 j, c
show mylist1
. ]/ v+ [1 i# I$ ?" \ show mylist3
4 I2 H! c$ b& x6 X6 Nend O4 i- }" i0 Q3 X. q- Y, Z8 P
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这时的mylist1 和mylist3 应该是一样的 |
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