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发表于 2010-5-11 13:19:52
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用list吧5 N, p1 q9 n: G8 L; l
patches-own [wealth rank]4 m$ o6 b8 d& x& x x
to setup
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ask patches [set wealth random 100 set pcolor green ]! ^" v- o/ u. n6 B' d$ k- U
end3 i7 l9 J! X1 x
2 j1 O0 J0 W( D8 A. }to go5 j5 n- W2 q5 T- b8 m U/ f
let mylist1 []
: S5 g( i* |* A+ _8 O set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches! t5 Z4 m' g4 C; {
let mylist2 []9 t. p1 b% Y$ S% b$ P. |$ K2 ]
set mylist2 n-values count patches [? + 1]$ ?3 ?# o5 Z5 w8 R
7 E& Y+ N) X/ u: |( K ( foreach mylist1 mylist2
' h. Z: |& k1 x: @ [
- `) |/ J' j- _) l6 v: d3 L9 W ask ?1[ set rank ?2]
+ V" v7 C5 s8 `+ U show [rank] of ?1
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]
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?& Y0 _- r4 \- J& Z6 V _5 u* _ let mylist3 []1 b3 f; \1 Z( [- H6 Z
7 Y f2 I* K9 }# }
set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
' x8 Z2 s9 C: U. S% [! I$ B. B show count patches" z+ W- z: B( i8 e5 P
show mylist1 $ h+ V; z$ q2 x
show mylist3 Y/ ^: M$ H% ~; h& s% k
end
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这时的mylist1 和mylist3 应该是一样的 |
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