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发表于 2010-5-11 13:19:52
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用list吧
0 z3 `$ c. Q2 xpatches-own [wealth rank]: u% v2 W, X4 O" _& q
to setup
. w& ~ Q$ e) m; L ca) D/ M4 r2 ^+ q. S, W
ask patches [set wealth random 100 set pcolor green ]# {. @1 [: D/ _: ?* A/ X5 d' J; l" @
end. x+ n" Z, ?# b( q$ G2 @- ]9 c* E! o2 y* X
- E7 f5 k4 O* i# n/ |0 f" G
to go
' g: ^1 w% L; M* _1 h7 Q0 \' Z P2 r let mylist1 []* F6 N6 k& h8 D1 `# L2 P
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches: \5 M. l& h3 Y( @' O8 B
let mylist2 []9 [. f# P7 m8 u/ a% @' E
set mylist2 n-values count patches [? + 1], o' C# N$ o! W8 ?5 t
5 V2 x# Z8 y- k* L1 E ( foreach mylist1 mylist21 w$ i1 P1 a# Z, g i7 a
[
5 ^) a, [4 Y' P. L% K+ c ask ?1[ set rank ?2]' \8 y, u: r, M5 a$ q
show [rank] of ?1
$ z" Z+ v `( }# h6 Z! \
d* E) _' U+ o' V: E3 F: C ]
. }' [6 o& \; y7 r. H2 {- h) }( {. R9 s )
: y; X" ~! A# o+ i1 x let mylist3 []
" @8 f9 k( m. [7 J" F 7 O' e4 Y, `( G! k
set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
, A: t& g: g1 l& {3 s( S0 M show count patches
& L n8 d5 B+ S! E. t3 j% Q show mylist1 7 ]$ Q: U: o1 M0 J+ Q2 V) U
show mylist3
9 u: p& r$ ]" R8 K% J( z* @ kend
2 o: q: h8 X; h e+ a/ p |* [9 x- X. J) [7 C6 n$ y2 i' b
这时的mylist1 和mylist3 应该是一样的 |
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