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发表于 2010-5-11 13:19:52
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用list吧" u7 h/ i: A% x+ z" |
patches-own [wealth rank]
, L' r- x0 D2 Sto setup
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3 ^/ ^2 T: X; A ask patches [set wealth random 100 set pcolor green ]
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let mylist1 []
2 b( ?1 K% }% x8 D% h! ?4 h set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches. g @" ~+ \5 X/ q. ?/ s* d( n5 V
let mylist2 []' X# h$ w [, C9 r$ w+ I2 X; L
set mylist2 n-values count patches [? + 1]
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' l1 O0 ]0 A0 y5 X: D) F. d ( foreach mylist1 mylist25 l) C' [% @/ j
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ask ?1[ set rank ?2]
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let mylist3 []
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. r: H: j; _3 g0 r' w3 ? set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches* u: m0 r! N4 [0 |1 U; c* K
show count patches; \* _! H1 B' J8 n0 [( {* ?
show mylist1
% r1 A2 Q: h3 A A show mylist3 Z, X. O& d: q' ?4 [
end
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. r: U! f) E5 v) u' I: _. p" Z. b这时的mylist1 和mylist3 应该是一样的 |
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