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发表于 2010-5-11 13:19:52
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用list吧
: A1 E" Y1 ? L0 {# Bpatches-own [wealth rank]' [, q& w5 H5 ?
to setup" r! J% o/ ~2 v& ]! b: f
ca
( l# v+ j/ g2 M. Y ask patches [set wealth random 100 set pcolor green ]
0 U6 R# q' C" W( h& ~; Q- B/ ]end
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to go
" B, M- `. g- N! Z let mylist1 []) u$ K( t6 }, E, h. |! i& a0 E& ~9 M. ]
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches& {/ a" O) K, G; _7 S% w4 f+ |
let mylist2 []
5 w w L/ n3 U( @$ { set mylist2 n-values count patches [? + 1]
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0 S& S. p# z/ @3 ^6 Z ( foreach mylist1 mylist2
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ask ?1[ set rank ?2]
' l' A3 H, H; {$ z' g% O6 J4 u: Q7 o: ] show [rank] of ?19 u5 y, `6 T% y* C) `+ N5 W2 K) Z
% P g5 d' U4 D. P( A* {
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let mylist3 []% U' i% w! v: J1 l5 i+ {4 Z
- u8 V, f" b2 j+ Q, C4 X set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches3 a* ?* l1 d& Y* I& Y8 G
show count patches
3 Q0 G7 A y8 Q3 e- V8 U) |$ a$ ]+ M show mylist1 . }! o. r. _4 N- x J0 j
show mylist3
! \' P) g0 {# G4 @% T, R0 h8 r8 r' Uend5 v6 i( U3 C& p, E3 F
% T3 N5 @1 h9 ~, _- g5 s
这时的mylist1 和mylist3 应该是一样的 |
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