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发表于 2010-5-11 13:19:52
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用list吧 f5 r* q2 A0 B7 T6 e1 r, a
patches-own [wealth rank]
+ V! p g0 O5 n: Vto setup
s2 o; Z5 b( e8 X+ C ca u5 a7 B2 p8 O
ask patches [set wealth random 100 set pcolor green ]
/ I! J$ [& w4 d9 ^end
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to go
, x L9 @, R( C, q6 s let mylist1 []
. s6 H# r2 h- T; w' b: y set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches; [# q' t5 A6 y: O% G
let mylist2 []. k3 m5 {! W6 A" D" ?& H4 Z. c5 G
set mylist2 n-values count patches [? + 1]# a# _) ]9 A& A& j' u, u% ^
. y: e; Y, y. G) d* m5 A ( foreach mylist1 mylist2
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ask ?1[ set rank ?2]
0 W! K( p* X& J J0 k, t; o6 S show [rank] of ?1- N) S3 g+ b, v$ Y. q( }! C
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let mylist3 []" m1 P0 t# X3 g+ T7 \
6 _9 y% x' c5 ^( ~$ c, |+ P& J2 V set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches) b' c7 h- m! q+ ?7 N; m
show count patches9 ?8 ]7 m& l0 s) r% U4 k+ ?6 j
show mylist1 7 L2 T4 @2 ~6 G3 G6 L+ w
show mylist3
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7 p& M. M$ I* y$ ]这时的mylist1 和mylist3 应该是一样的 |
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