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发表于 2010-5-11 13:19:52
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用list吧$ c7 T' S" S- h0 f1 n/ f) b
patches-own [wealth rank]
3 U, {+ p Y, p7 ~ p, x- {to setup( Q! ?# j; Q$ F
ca$ w- j# s O: |4 @7 s8 Z
ask patches [set wealth random 100 set pcolor green ]1 j+ }/ ]+ V/ e* O- e
end' f6 c; t. n& J4 `/ E4 N4 ?
( k) ?; v* z, P& Q, wto go
. D1 T, p4 \! S, T2 g let mylist1 []
F, H+ e7 z8 ?* \$ b. g( [ set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
0 w; n, v4 P6 b' {# n9 V let mylist2 []' B @) m5 `" G/ w: X
set mylist2 n-values count patches [? + 1]) A8 e* l: h: O% F5 A
) O7 _: e+ O3 R ( foreach mylist1 mylist2
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ask ?1[ set rank ?2]
% g$ N* y1 W4 J) F! E8 k show [rank] of ?1
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: S8 x( k7 a$ N6 N: g ]
# w# `# y7 _( l8 N. k )
" c2 \% n( D* H8 L* M( A* d let mylist3 []" O( d$ Q8 B: {0 | j
# z0 v" O4 D' y- Z
set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches5 E/ h' F3 O0 M
show count patches
4 _# y- P) D! x( C% d$ l! ~' C$ i4 V/ } show mylist1 a; _0 l, Z. s
show mylist3; z* o, B1 D3 z0 c' A5 {7 o, w4 P
end5 {9 X, N8 u* f4 [* q; w* x
3 z2 l7 F1 ~7 E& q. Q1 x这时的mylist1 和mylist3 应该是一样的 |
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