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发表于 2010-5-11 13:19:52
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用list吧$ {: U5 t+ [( W" V8 Z! s
patches-own [wealth rank]
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ask patches [set wealth random 100 set pcolor green ]
) x9 Y1 [! ^4 j! [: mend. v( q: c# b, n' e
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to go
# b3 T+ P) `2 o, H, |6 |) @ let mylist1 []
% O7 x& W- l# p8 f+ c5 k3 w* ~ set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
2 A1 {! S/ [ J6 @9 d9 S6 t- a8 _" \ let mylist2 []
" L# O/ _* @/ |( N# X. r8 I set mylist2 n-values count patches [? + 1]
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( foreach mylist1 mylist2% C* R# J: Z; n/ T
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ask ?1[ set rank ?2]
5 T5 [. s$ ^ u4 p l2 V5 Y0 U% c3 } show [rank] of ?1
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let mylist3 []8 Q. ?) d2 A) w+ p7 v
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
/ S# e% b1 z; x; \. L5 j! o2 y+ j9 ^ show count patches
) x6 u7 ` N K% b+ j. ^/ h show mylist1
& O; j1 k, G4 z) R! Z$ g: Z! f show mylist3
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这时的mylist1 和mylist3 应该是一样的 |
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