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发表于 2010-5-11 13:19:52
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用list吧* ?, \" v+ m$ q8 X
patches-own [wealth rank]* ?% x! x. I" G8 |0 P6 ]
to setup2 _ a( {1 E) K2 Z0 B+ y/ ^
ca
8 d* Q' r# s0 P! I' y9 ` ask patches [set wealth random 100 set pcolor green ]7 ^$ X4 Y9 \2 L" i- `" n) f" Z% G; N# t
end
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let mylist1 []1 H6 U7 c% b3 Y
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches7 E- E. ]1 K1 ?
let mylist2 []$ d0 C# U I5 P7 Z- A! H2 {" a
set mylist2 n-values count patches [? + 1]% X$ J* I( Z/ K2 I4 `" }
. }, s5 M$ M5 k ( foreach mylist1 mylist2- u1 R# L' s4 D4 l% _1 ]
[( }" _# b2 [) U, W
ask ?1[ set rank ?2]
# R g" ~* D: r! ?4 M2 u( H show [rank] of ?1
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let mylist3 []! p# G; d5 D1 p' H2 P
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches( z) L. L, \. i S& R4 W. L* U L$ _; j
show count patches
9 l9 e5 W" P; V. Y$ { show mylist1 + V& G v0 r& S. R Y. s
show mylist3
! ]& S, Y$ ]1 a9 _end0 V1 R+ Y; v0 y: h6 w3 P
1 G1 x5 D4 M6 a# f5 `
这时的mylist1 和mylist3 应该是一样的 |
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