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发表于 2010-5-11 13:19:52
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用list吧( K8 r. A0 s' Q) ]" H
patches-own [wealth rank]
9 E3 @# C& c/ R& b: i. l4 j& @to setup
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$ {( K* y7 y3 H4 U' }' t8 H ask patches [set wealth random 100 set pcolor green ]
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to go' I9 {% b, h% }- a
let mylist1 []
; U6 ~2 b7 [! V& P set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches, [( q# O4 E7 ]( X: ?1 z) {
let mylist2 []
, j; @. B& Z8 v3 H% \ set mylist2 n-values count patches [? + 1]4 v3 R8 ]6 N9 B& {8 s
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( foreach mylist1 mylist2
) x1 u- Z6 G1 k0 F1 s4 b+ t* Q [7 M# S& Y$ P: B; Z- L% B+ I6 S
ask ?1[ set rank ?2]
+ ^1 C2 P! G& R# L4 j show [rank] of ?1$ o" U, P6 A0 T
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]
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let mylist3 []
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% L1 c: {6 Z& b7 ]+ e1 i, F7 |. e set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
- W4 y' ?6 F+ r2 u' W show count patches
* c( b- Y* c; q$ X show mylist1 % j6 u4 i* v* O1 i: f
show mylist3
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6 E8 a) t& h4 w& Q& _$ B这时的mylist1 和mylist3 应该是一样的 |
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