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发表于 2010-5-11 13:19:52
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用list吧8 R5 `" l3 t" A. P* S$ x* Y# M
patches-own [wealth rank]* D- q* x5 O: a& c" T6 D
to setup
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+ s! G# Q5 q2 |# N- q: Y" v ask patches [set wealth random 100 set pcolor green ]
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to go
5 @1 q! i2 q) B0 N" Q3 y+ i let mylist1 []
3 O3 m5 {' L4 ^' \, }. p" Z* X- A: @/ v" E set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches8 v1 B. h0 _! i; ^4 Y
let mylist2 [], Q) @6 K: _3 s, z7 @9 T
set mylist2 n-values count patches [? + 1]* x* C. k1 E1 t
: S5 j3 m$ u2 h6 @6 ~4 }8 S- g, c ( foreach mylist1 mylist2
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ask ?1[ set rank ?2]
R. C+ a8 X; e& S6 F& Z show [rank] of ?1
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]
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' c" l D: q6 M$ E let mylist3 []! k N1 V/ ?" m0 X% X
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
8 [% z" o$ F, \ show count patches6 V% c0 j h, {* K7 ^0 p: }9 S" @
show mylist1 $ |6 i. Z! D$ V5 U1 l( B4 k
show mylist3: D: h* M4 v4 Y1 W
end
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! g) n' N8 @( @: E) P# }3 o8 p7 D这时的mylist1 和mylist3 应该是一样的 |
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