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发表于 2010-5-11 13:19:52
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用list吧0 T9 {3 r* L- }6 @/ e
patches-own [wealth rank]4 G# X% s1 V8 H8 \. A& ?
to setup
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" x6 p7 U* Q7 | ask patches [set wealth random 100 set pcolor green ]
7 c' C1 B0 p/ s' tend
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+ W5 L* h. V8 l5 X( W% o) Tto go
& P6 x% O W, p& G% q$ P6 N7 ^! j let mylist1 []' X6 ]0 m7 J: k
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches6 s) i6 a1 o8 `( m. L' w
let mylist2 []8 C$ k& h1 Z! n3 t/ Z/ C
set mylist2 n-values count patches [? + 1]# X5 }' f0 O! z! }. U
/ [9 P6 ^! S' k( R& l) Y ( foreach mylist1 mylist2
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4 A0 }5 _8 d' @( b2 P. c ask ?1[ set rank ?2]1 `5 o: E- K9 X! @' w8 h3 L
show [rank] of ?15 o a* m9 O9 |9 T+ b
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]
9 [5 `1 N5 t4 X0 w n/ r, g )5 i. k% m. H b U
let mylist3 []
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches: \! J9 {; L3 S) F
show count patches9 D5 M4 b. T4 l# ]; g
show mylist1 1 u( E7 Q, A9 K5 Q- g7 ~
show mylist3
. Y" m0 r5 \) q7 D. y7 `end3 X2 ^5 t* K* j, K. L
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这时的mylist1 和mylist3 应该是一样的 |
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