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发表于 2010-5-11 13:19:52
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用list吧9 n" W- e( u8 A5 q
patches-own [wealth rank]0 V5 z5 d7 m4 G; b) h" d
to setup5 ^5 e3 w' {4 x' J1 G2 h
ca
, H/ O- Q) g5 n ask patches [set wealth random 100 set pcolor green ]* |) N3 u, {8 E; p" f" s
end
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to go
7 f6 i& F. @0 @# i6 _ let mylist1 []
# [1 _3 f, D: @8 _ set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
9 Z6 \* b/ F4 Z let mylist2 []! j8 t+ ?! |$ e* c
set mylist2 n-values count patches [? + 1]
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( foreach mylist1 mylist2
( \* r. O$ J4 o [
$ g0 W' g. o9 r- }- X s" b ask ?1[ set rank ?2]
3 x& l; E8 F( } show [rank] of ?1
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let mylist3 []% F3 v' @' q1 e3 z d9 g: p
9 z& L, L; C$ T. z% N; E( e set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
' V. V8 T% K/ N1 C show count patches% @ m- N9 _9 O. S/ } ^ `2 D
show mylist1
1 {) X3 u# r. A& s show mylist3
3 c$ r; O G5 _; ? z( d; send
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5 o9 }' e! o* G: X这时的mylist1 和mylist3 应该是一样的 |
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