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发表于 2010-5-11 13:19:52
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用list吧9 l: a5 I' |6 o$ c2 ]3 p
patches-own [wealth rank]9 k1 c6 w" X( d( {# U4 V. P @
to setup6 e) M+ q" |) p0 U! |& h
ca. r: U9 O4 a0 h6 Z
ask patches [set wealth random 100 set pcolor green ]
0 a. r1 X2 H8 Q. [7 bend
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to go% L, S$ {1 c M1 j; ?9 B2 G+ i
let mylist1 []! @1 k6 M* Z# X# ^) S1 s
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches, t1 q) u0 p% l1 d
let mylist2 []
; q: g% J2 z/ x; f D6 \ set mylist2 n-values count patches [? + 1]
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$ }4 o9 T. V8 y ( foreach mylist1 mylist2 H' y" E% @ m
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ask ?1[ set rank ?2]
+ ]- ?7 N( I' u, ^ show [rank] of ?16 I+ b& D5 d! g4 g6 r3 `3 o
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]
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let mylist3 []
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+ u) F" r9 M' G3 a set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches: f, P: |/ J/ r" i
show count patches% ?( S3 N1 L' M! k9 Q1 j
show mylist1 3 p2 W4 [" u8 {2 A2 E$ g
show mylist3; Q3 e/ t3 ?5 z$ \! u
end! z* b) E4 u) J) }) f5 p; s
1 B8 S+ H, l$ k' X: p6 M这时的mylist1 和mylist3 应该是一样的 |
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