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发表于 2010-5-11 13:19:52
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用list吧2 R, Q3 j9 h7 z" _) ~( i' @
patches-own [wealth rank]
% p: b e. A: n! m# N* s) Eto setup. I% B6 S$ G: E' v& i
ca9 k, I& U5 H3 K4 b1 o9 i! D
ask patches [set wealth random 100 set pcolor green ]
1 e: \: o* O& \3 jend
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3 @2 l. [. O' kto go
/ M$ d. k" A3 S; b0 m let mylist1 []( Q* o0 d6 ?9 P( _
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
6 V! l- A- e) w( X let mylist2 []
6 ]: f, W( S, O1 c* f, d set mylist2 n-values count patches [? + 1]
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# [( h( G! b$ D ( foreach mylist1 mylist2
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) J3 G& x; P) S" m$ s1 i ask ?1[ set rank ?2]2 e" v' _9 q3 {0 E; b0 c
show [rank] of ?1
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let mylist3 []
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
' p- X8 Z. c) V3 R8 ~8 w' J' @ show count patches2 W* `! p3 Y; @5 x
show mylist1
7 B; E+ ^9 \0 z/ Z8 [ show mylist3
K( r) U L( G0 h% ]# |end
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这时的mylist1 和mylist3 应该是一样的 |
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