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发表于 2010-5-11 13:19:52
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用list吧! f: s! c' P) Z1 E9 Y1 N
patches-own [wealth rank]
+ f$ C! a0 d8 @. \to setup
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ask patches [set wealth random 100 set pcolor green ]; v3 a, d' ]5 R6 B
end
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$ @# |# _7 D! P1 E6 w3 Y5 Q& Eto go
" ~! j8 g5 Z( B6 E3 n# V let mylist1 []3 f2 `' a0 h* m% c# O4 Z
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
. q, z/ k/ J9 _ let mylist2 []
1 h6 T5 R2 y5 @ set mylist2 n-values count patches [? + 1]5 v0 R; v( V+ v# S# i/ ?
% w1 H# O* \; y: S+ ~1 f
( foreach mylist1 mylist2( l5 f% L3 Z9 o( p
[3 z+ X/ u, `' c
ask ?1[ set rank ?2]2 ]4 g; Q/ n6 n$ X( H: V p
show [rank] of ?1
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let mylist3 []
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
; @ ^9 F4 b- I8 m1 G- m" H" M show count patches
6 |# m$ _( E. G* N, t2 Y. g show mylist1 8 r( F ^+ x( {! G! T
show mylist3- Q4 T9 Z. }" {/ U* E
end" i/ {; O/ `6 D+ A) f7 U! X
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这时的mylist1 和mylist3 应该是一样的 |
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