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发表于 2010-5-11 13:19:52
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用list吧
, r# G) e1 v1 t3 Npatches-own [wealth rank]
, y0 |* P1 z1 x+ y7 Nto setup
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: @7 b+ w. u# k% W& P } ask patches [set wealth random 100 set pcolor green ]$ e! R4 ?; C' R. O
end
b* n- P7 Z0 O5 s) n* O9 T) a
- n, B$ x8 d( g* g) O* Yto go
2 i( e+ B2 E& k1 y let mylist1 []5 b1 H6 M7 o5 I/ l0 v3 r
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
) D- z3 }$ m- H6 S: J* a3 [; b let mylist2 []% z4 }9 t$ k4 J/ s
set mylist2 n-values count patches [? + 1]
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( foreach mylist1 mylist2# a' w0 w- v$ {6 F3 F6 M
[/ f0 Z/ z Q1 A& n6 L/ K
ask ?1[ set rank ?2]6 O) d4 J6 B6 {% Z- p7 `
show [rank] of ?1
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7 A- w3 f: t6 Y) w! v let mylist3 []$ p5 S" s) q1 D) h: @ o
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
3 [. i2 O/ o4 E+ U' v$ Z show count patches
* B0 M' R2 Q! r) m show mylist1
+ \! n! h. R, |# z show mylist3
1 y8 A6 R( \' n! @end- K" S7 R% m& ?: Z
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这时的mylist1 和mylist3 应该是一样的 |
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