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发表于 2010-5-11 13:19:52
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用list吧
! b8 ~6 E4 B& Fpatches-own [wealth rank]3 D. C1 |% w0 a- a3 [7 A
to setup( s% n2 n' l' ]- `4 Z
ca
) r- y& v, `+ t: L1 I0 B4 l ask patches [set wealth random 100 set pcolor green ]# o3 v* D' E' w7 T4 i0 O4 z
end" W$ f; [6 M" @4 D
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to go
. f5 i) }( o( `1 R0 H5 F let mylist1 []& @7 W5 z$ g5 t
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches' K: ]3 Z8 U/ l0 X
let mylist2 []
1 u* b8 `9 B5 T8 R set mylist2 n-values count patches [? + 1]5 u9 o* v* f0 x2 `2 A; H
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( foreach mylist1 mylist2& j# K v# c, h# [/ c
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ask ?1[ set rank ?2]
1 }7 X1 U- J1 {% J8 T" m show [rank] of ?1
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let mylist3 []+ T; |2 n: H* w
% J0 m( G* w/ @5 ] set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
( v9 l" J8 \6 O3 V, K6 n r$ ^ show count patches
* V$ a! v2 q1 Q4 v show mylist1 0 ^/ a. R) \- ?
show mylist3
( t5 o3 [" K9 p& d H9 c, p Wend
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这时的mylist1 和mylist3 应该是一样的 |
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