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发表于 2010-5-11 13:19:52
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用list吧
0 H; N" Y8 h* ]8 i( e7 @patches-own [wealth rank]
* f9 {$ z# i) Ato setup" D% J( B" z- ^6 h" t- U6 J
ca
- B0 t5 v/ {) s( m! d- d! }3 _ ask patches [set wealth random 100 set pcolor green ]
3 i( K3 M+ T9 p) w2 Iend2 H& C0 o0 C* }
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to go
5 D3 W: M2 @* F/ Q let mylist1 []
5 O% Y$ v& E1 y set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
! A# {/ E# \/ z9 V+ C# x0 D1 g$ h let mylist2 []
9 I2 O5 a2 _5 D: H set mylist2 n-values count patches [? + 1]# A) m0 K, |: V; }7 m
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( foreach mylist1 mylist2
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ask ?1[ set rank ?2]& z+ ?! m f$ H$ x1 [9 q7 u7 Y& B9 s
show [rank] of ?1
) z& k+ ]. P+ B, Z' ]% m7 u
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)
$ F: S0 a: f" ^6 x- \% Z0 m let mylist3 []
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
9 M+ u' Q% t- u5 C) l0 | show count patches
8 u- m& U8 c3 J; w) U show mylist1
( h' _9 A# `8 k0 Z: A+ \ show mylist3
. i5 s, D! _+ T8 V, m, nend5 ?' n! v8 E5 [' w6 E7 U
/ Y5 P3 [2 P* o; o0 r1 m这时的mylist1 和mylist3 应该是一样的 |
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