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发表于 2010-5-11 13:19:52
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用list吧1 S2 `' R: r# ^: Q$ ?( V) I
patches-own [wealth rank]
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ca
4 Z1 Q x5 ]5 g ask patches [set wealth random 100 set pcolor green ]
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let mylist1 []
' ?6 s& f- d' B- |7 y# z c/ r2 w set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
# s- {) \0 j; H( ]* J" E! ]1 W let mylist2 []
, }$ H- D: k- B4 T set mylist2 n-values count patches [? + 1]2 p! b0 I( u( h) ]
* ?5 W/ H4 t8 r' J% E# B+ u; E ( foreach mylist1 mylist22 c3 `5 z: _; @& }
[
, B$ m6 `+ r0 T6 o$ x) r ask ?1[ set rank ?2]7 q+ L4 \/ @0 H/ r7 {% W+ q$ c
show [rank] of ?1
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let mylist3 []* }9 Y% ]7 [. p c b) J
. h( {- u6 C9 c2 H, I K set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches. Q% C: s- P) @2 I! Y
show count patches
% U( `% p+ g- i& j( A; U0 R0 Z show mylist1
5 b3 @, Y+ ]3 p0 a9 a) x show mylist3
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& h+ s) E! \3 \$ t0 {; b这时的mylist1 和mylist3 应该是一样的 |
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