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发表于 2010-5-11 13:19:52
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用list吧
4 i3 O2 d! l( ?. n; D3 T6 }$ xpatches-own [wealth rank]
; k2 z& l' [5 h1 }2 hto setup
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ask patches [set wealth random 100 set pcolor green ]/ h2 |2 K' A. o/ e
end
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let mylist1 []6 s8 i) @, x6 l! p7 v/ [" c% D
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
; S! {( {6 ]7 ?* w: \ let mylist2 []; B% z. R- a, {* k
set mylist2 n-values count patches [? + 1]% B4 w0 P3 g; y. R) d4 ~" X% V
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( foreach mylist1 mylist2
/ f n! b1 u. F4 }' }, ? [
) C( w9 u1 q& V3 [ ask ?1[ set rank ?2]
; P2 C7 v9 {$ B4 q s3 @0 V show [rank] of ?1# y1 E, ]* A$ Y- M
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)
) ~5 @5 c' @4 I# G. E, Y let mylist3 []0 \ `- I. z5 d8 B# ]" C
/ ~; T0 ?$ K5 R g2 E* H4 | set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches( U+ [, L) N. r
show count patches
0 F( _: @" `1 \; d) z2 g show mylist1 $ W; U* Q0 k( g
show mylist35 o; [2 U4 W6 r) d
end4 v5 l+ x) I* T8 \
2 J' u: p1 b5 V& a$ J, W4 E4 E8 M* K这时的mylist1 和mylist3 应该是一样的 |
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