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发表于 2010-5-11 13:19:52
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用list吧" \9 q# D% G1 f
patches-own [wealth rank]1 O: |# b9 ]( t( f& |, ?
to setup+ Y/ C4 `+ A+ X0 ~" g
ca
# P, v) v2 z- R6 S* d D ask patches [set wealth random 100 set pcolor green ]) h5 X" A0 ]- z$ `8 X
end7 c5 p5 o5 [5 ^1 r) G/ d
0 H3 d; y1 Q& T' k& qto go
5 f. Y& l. k1 g' `. J* h& V let mylist1 []
. Z. `# |( V. { Q set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
, s V" X/ G8 H7 f2 O let mylist2 []* i# \, e4 S- q1 \
set mylist2 n-values count patches [? + 1]6 p( \; Y& w8 G' [, H+ S6 \
( k5 q0 J; O6 \/ ?
( foreach mylist1 mylist2
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ask ?1[ set rank ?2]" s, n% i6 e+ D" B3 Y$ @
show [rank] of ?1% d6 Y3 U0 e/ U) [" E" f
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]
: y1 |8 R4 N n9 B0 P$ @. y )
1 H% y2 M" T$ R8 J3 y( L+ M( B: \ let mylist3 []
& |3 u9 p, k& I" d. \# ~. k+ [ 4 K- D, Y5 @. b% y. U
set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
; @2 R- X, @. @; e show count patches
4 h2 x6 y5 Z: q. _" T& V show mylist1 5 B; _ T e) Z0 G
show mylist3; | V& `! D. k l- [+ _" `
end
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0 V* t; C6 `: o( r/ X) Q这时的mylist1 和mylist3 应该是一样的 |
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