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发表于 2010-5-11 13:19:52
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用list吧
. q4 n; i' ^; y6 u2 i7 upatches-own [wealth rank]
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ask patches [set wealth random 100 set pcolor green ]2 y. } K5 a3 Y: u
end
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to go
& l8 B' [4 d- n/ o let mylist1 []2 }* E- [5 e+ _, o7 Y5 _. F; t
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
, x& \. Z8 i. Y- V9 g5 { let mylist2 []
; G n* b8 I6 r) H% F( u" V5 C set mylist2 n-values count patches [? + 1]* w n a' L" Z" x4 d l
: w$ H( \+ ~ @. A* }" L( M# z1 Z ( foreach mylist1 mylist2
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, ?: e. u! r% R5 L, r ask ?1[ set rank ?2]
1 L- G$ z) }$ f; j+ ] show [rank] of ?1
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let mylist3 []1 k5 i" w0 h9 L# R/ R2 ]6 W
; T' ^1 \& ]2 k# Y set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches. p) |6 n; `. c4 z2 L3 F9 W
show count patches
( f* p+ a E/ H% p% X show mylist1 , L' t' V" }7 ?% B
show mylist3
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0 h, P$ P, F3 ]. v这时的mylist1 和mylist3 应该是一样的 |
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