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发表于 2010-5-11 13:19:52
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用list吧
5 x4 L1 a) \ L" Q- ~- C: m) l7 t# ^patches-own [wealth rank]
0 x: x l4 t( A* X' Lto setup
O1 A1 z5 S4 Z2 E W, e/ v ca
( j5 V$ C& Z# G+ {8 d5 L9 o ask patches [set wealth random 100 set pcolor green ]
& g) J9 i9 W5 f9 f9 U" xend4 }" E0 Q2 R, T" S3 h6 `
# @4 h6 U+ Z. t& ]. i8 cto go' i" ?6 A5 N8 ~) @5 O
let mylist1 []1 \6 ?/ K1 m$ j. l. E# r9 X
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches+ U) s$ [8 q# Y( w: m/ r3 [' h
let mylist2 []+ [0 ?1 h9 ^+ @1 X' B8 V
set mylist2 n-values count patches [? + 1]1 m F m, q( G$ z7 E2 N9 `
, }4 B) k6 }3 c }- g* R' p5 l4 C ( foreach mylist1 mylist2
$ n) c) s1 C3 N3 I4 I" w4 V/ k( I, o [/ w. }2 C' p4 s4 Q* V, ~' w
ask ?1[ set rank ?2]
1 q3 {% B0 A8 f+ N% N- V1 o show [rank] of ?1
" f: J j% h* n. S/ K6 \/ j, M, e ) C+ L" Y3 F& I1 L }0 @0 k
]! B# g E$ B3 w! v- v
)
. A4 V9 c/ k1 h1 y let mylist3 []
% q4 B q" ]# ^" w 4 b# O" Z- ]# F& F2 j; E- g8 ]0 R! s
set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches* y. b+ M0 _2 i- t) c! |# d$ s5 i
show count patches: y0 V; H' F0 S! L3 z) j
show mylist1 1 w6 s& ~, y4 i% C7 H, a9 p
show mylist3. _( T2 M1 B- z& }: J# _
end# M! F# t! y* a6 M `. C% D
: e: ^" `- t! T) O8 T( T
这时的mylist1 和mylist3 应该是一样的 |
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