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发表于 2010-5-11 13:19:52
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用list吧2 M- ^, G8 {0 _2 q, ~3 W3 R
patches-own [wealth rank]
2 c" s; x4 V, C; N! gto setup: |7 Z! k" F, a4 T& ?
ca, w% \3 \* r5 \, J0 q: B. h% y
ask patches [set wealth random 100 set pcolor green ]
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to go' w; M# T9 Z8 \
let mylist1 []. p& b7 w. m! n; A
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches- x" [* e# O! I( J
let mylist2 []" V5 \3 q: C) i* h, ^/ F
set mylist2 n-values count patches [? + 1]
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# x+ M0 g) b- H' T6 ^; A ( foreach mylist1 mylist26 U* ?0 b% t# q
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ask ?1[ set rank ?2]- ]4 Q8 P* M. R9 b+ p: p
show [rank] of ?1
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)
" n" B2 u) K" {; F let mylist3 []0 V9 v" ?) U1 F2 G5 F7 h
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches$ Q/ ^( E7 l! @7 Z
show count patches
u) ]8 O- Y# P8 I show mylist1
" [/ G$ O' y4 ? show mylist3: a3 v M% h/ `! o9 e* N: s U( k
end. Y$ L# F6 E, ]8 r. y( Y
0 _3 t7 I& M1 n# C4 `! t这时的mylist1 和mylist3 应该是一样的 |
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