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发表于 2010-5-11 13:19:52
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用list吧
0 p! _7 g* U# |' _2 Mpatches-own [wealth rank]. C" I& e- N/ @/ }1 x/ Z
to setup
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}6 d- @2 L! f9 i$ |: ] ask patches [set wealth random 100 set pcolor green ]/ ~5 o& J+ ~+ q
end( u" P6 B( x: r
& G. C7 ~+ q/ d& Nto go
( m: X: Z2 j5 }8 g let mylist1 []
) r. t8 @* f4 W" r9 m; @ set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
: T7 H7 `$ [0 G$ l let mylist2 []
& E/ ]1 C' t3 o. a set mylist2 n-values count patches [? + 1]
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( foreach mylist1 mylist2
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@/ a) [* M$ `& {" n+ B; S* { ask ?1[ set rank ?2]
& }. P; h( I- z, [: X* y* S! D show [rank] of ?1
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]0 }; m8 M `' v6 z8 o4 H8 q! S
)
% Q; k4 |- F# F let mylist3 []
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches' ?: O( v5 {/ r" t9 F
show count patches1 j$ N( Y, x9 a# ?: f7 j
show mylist1
: ?% y: V& g. X6 q$ m9 E2 | show mylist34 U: I7 _* g0 M8 B
end. |9 e/ m' t& ?- m @$ t9 a( e: @
1 N' Q' p @) H这时的mylist1 和mylist3 应该是一样的 |
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