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发表于 2010-5-11 13:19:52
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用list吧8 h. T) n' D' q
patches-own [wealth rank]
2 z) H _6 t$ v. C9 bto setup
$ G% K# B/ w+ h% l) D ca/ }# p N7 P5 A# V/ K1 R
ask patches [set wealth random 100 set pcolor green ]0 w& p7 P# m& v) h7 V+ Z7 z" z6 p" l
end @0 q8 X4 G8 @* k' c) H
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to go; C$ x; g0 Q4 }
let mylist1 []( I' z: ? ^' R; ?0 D
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches0 I6 ~5 o4 Z/ Z8 ?/ f4 l5 _' c
let mylist2 []
K: f. |/ b* B9 N set mylist2 n-values count patches [? + 1]
# ~% K' ~7 J1 o0 Q4 s # j' v- y; I' B
( foreach mylist1 mylist2
# S/ J9 ^3 g3 I' ~ [6 Q+ z1 |4 q: J9 V$ u j$ E: U# X
ask ?1[ set rank ?2]
$ J3 _; A8 Z2 e show [rank] of ?1
7 ~- D+ f. T' r7 B0 \, ^* g l6 e- Q3 z$ O' K- W8 H
]0 C" z }) p' F1 O5 ~9 F3 C
)
% t4 q- H* \4 _2 H% l6 H7 a let mylist3 []
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% N8 K9 S2 z( o! d) q' { set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches9 k0 q3 W3 {- C; l6 r
show count patches
7 b& B6 C0 o% G# P1 ^0 y+ q7 ^ show mylist1
, X; ?8 Y2 w+ |' O# Y. b show mylist3% g8 }7 ^' `- B' H
end$ O! @$ v! G( G9 {, K# U# O: R
, L* R- ^" ?7 X: o" ^这时的mylist1 和mylist3 应该是一样的 |
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