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发表于 2010-5-11 13:19:52
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用list吧) I# z( Z! Z/ I/ D- a1 D
patches-own [wealth rank]6 ]8 {1 m3 S# g8 C* I' m
to setup4 ^6 V H4 l _3 D" }, x+ C
ca6 F+ x8 t' v/ d* U+ I
ask patches [set wealth random 100 set pcolor green ]3 E! \& z+ F+ |2 U
end; m% ^' u- r% C [ h6 F
9 H' G( z5 X M6 bto go. n! ^: L& `3 b* X: h
let mylist1 []
- `: J! t% E5 L6 n set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
" v3 T! w: W, C let mylist2 []
: u/ b! l, j2 Z1 ?/ h4 G% N set mylist2 n-values count patches [? + 1]9 Y5 \$ K3 O& R5 h' t" Q
0 p- }0 Q. W; b, Y% O
( foreach mylist1 mylist2
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* D2 N8 l9 ~6 n0 a, ~' K6 ~# e& f ask ?1[ set rank ?2]/ e8 X4 ]2 |; f
show [rank] of ?10 v# G( u9 Q3 B
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]
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let mylist3 []8 {7 u0 {$ {4 e5 j3 _# R
% Z: c$ @! s1 G4 [ z! m set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
% F# A+ f* L" p* D+ V1 R% c! ^ show count patches
4 w- m& e: `' B. O0 u( S0 @3 H F show mylist1 ( ] u6 u) ~! w! `& n
show mylist3
8 z( r. V8 F( ]. M! N+ Tend
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1 l2 G/ E/ ~$ Q这时的mylist1 和mylist3 应该是一样的 |
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