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发表于 2010-5-11 13:19:52
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用list吧4 A7 ~: q& j1 G0 i6 h: W
patches-own [wealth rank]+ b8 |( y& b, c0 \& E' |
to setup
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ask patches [set wealth random 100 set pcolor green ]
9 F7 s: m @: q# A8 X( G: Yend
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, l! T4 Q8 w; A8 {to go
: O& E4 c. }: U/ e, {- S" D. x let mylist1 []3 v' r2 j* [2 I9 g* u+ m) G8 |' Q
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches0 }+ V I6 _$ a6 q+ C
let mylist2 []# k" E# G$ Q2 N$ x# U" S! f$ Z
set mylist2 n-values count patches [? + 1]# N+ c) E. G% I4 M
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( foreach mylist1 mylist2
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ask ?1[ set rank ?2]
) g" e& m/ A9 @* ~# |7 ]9 r show [rank] of ?1( C" F) N- K' }. y
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)
( L+ K$ w$ S. c& Q8 f& R let mylist3 []
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9 N; q% J8 E) Q7 r set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
" s1 M# u: |' V6 s5 \: L! F; r show count patches; h! S- R6 S1 R6 G+ p
show mylist1
! I2 c2 r* Y. [( H show mylist3$ z5 U" m# w0 Q. C; T
end, y$ g/ P# G7 M8 W: a
; N' B# b0 b6 a* a) @# l7 k. K' N这时的mylist1 和mylist3 应该是一样的 |
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