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发表于 2010-5-11 13:19:52
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用list吧
! j- L" ~$ G* Qpatches-own [wealth rank]
' X0 @% F/ S6 x/ o" y1 ]. |to setup$ [3 W9 Y+ j5 D
ca
: X6 j% {+ Y/ L' m. S. D ask patches [set wealth random 100 set pcolor green ]
+ i0 M' ?; Z: {$ @) j4 Q5 x6 N5 E7 V& hend
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to go
/ m, @2 s! C& u3 ^' w3 q; b* p8 C let mylist1 []
5 i( `( q, T: | set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches6 \' h0 Q4 W+ `5 h
let mylist2 []8 }8 B- y7 V( O1 i3 i
set mylist2 n-values count patches [? + 1]
5 y8 k3 R" |' Q 5 x5 k0 p: ^/ |' u, N6 }
( foreach mylist1 mylist20 \! n# A* G8 y
[- E2 c6 W3 R) }5 n
ask ?1[ set rank ?2]
& x. E$ v' A/ `% V show [rank] of ?1: L) p! h4 j1 U, B
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* h% u/ F, z6 x- @9 I' ~ let mylist3 []
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
$ h+ x3 p {# {8 P( Y) S; X* u show count patches" U" E% g- T2 I7 @
show mylist1
+ c9 X* G# x. H! @ show mylist3
3 F# f2 J: H, i5 D/ aend% k; f' {( `/ I5 X8 T( }) D
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这时的mylist1 和mylist3 应该是一样的 |
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