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发表于 2010-5-11 13:19:52
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用list吧
2 Y& v! Q; T& {& n9 Z3 qpatches-own [wealth rank]" G& B& F: R: |" z
to setup
T" t2 L0 h: E) g ca k* z2 a6 ]9 d. d# V G0 }8 ^
ask patches [set wealth random 100 set pcolor green ]
k) o9 m' H/ W0 U# Y: m: K* oend
% R0 m$ t- j( i, X; }' k& e" W" Y. m. {/ T* z- V6 e
to go2 |4 I# \1 h- W# M$ Q& a" p( }
let mylist1 []; W! l* h J2 U: K4 K
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches* o6 h% x8 x6 ?6 y8 O8 L }: V4 F
let mylist2 []0 k. q6 Q Z P% Q5 W) `
set mylist2 n-values count patches [? + 1]3 \" L6 d! H1 b/ M
0 e( x' |' s% y$ c0 H
( foreach mylist1 mylist2! z4 m2 ]8 w9 {4 T- X3 s* y
[% c7 g7 Z/ @6 Z1 K! I) a; X
ask ?1[ set rank ?2]" X q& o& W- T6 C8 C+ J* z
show [rank] of ?1
3 b. X' H4 \% Q8 h + C* x; H- c; p1 W/ g" ]' ^- R
]
* N, o8 v8 T$ K/ h )
" \2 @! `1 o9 B let mylist3 []5 Q& B) K8 Z1 {# c9 k) c
) \ T) w \: Q8 X set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches; c# D6 a' c% E* z( \' I+ g
show count patches
' ?2 I& r- t$ e' b+ c4 b# t* C3 z show mylist1
+ \, `. p8 d! [- d; W5 u show mylist3
$ v$ \7 i4 ?: a$ y1 }4 v- ]end t: N! D2 u7 P7 c
# k) I" @- R- T; X* J
这时的mylist1 和mylist3 应该是一样的 |
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