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发表于 2010-5-11 13:19:52
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用list吧0 x+ k" }4 @6 {0 g8 \$ V
patches-own [wealth rank], e( s" V6 N1 r1 }
to setup
% H3 G1 f, ^8 P: f( P( c$ | ca
k1 }1 Q: ?7 \( j& t1 I ask patches [set wealth random 100 set pcolor green ]
. B. K4 ~% H0 }/ qend D: ]& M/ T7 Z. Z. N% O
% w% E) _6 Q$ ]$ W5 H9 Jto go! \! q5 M f! k: i
let mylist1 []
% W: D) |5 Y3 \( A9 r set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches5 ~6 {+ M0 O8 a: L; F
let mylist2 [] c# [0 b' @2 t7 e/ P4 V& J' o4 ]7 l
set mylist2 n-values count patches [? + 1]; L' n: n% `1 l. ]
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( foreach mylist1 mylist24 y+ a% ]3 B$ z
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ask ?1[ set rank ?2]. t' g4 J9 @# q# E9 C H# T" O
show [rank] of ?1& T2 Q$ ?& g) w1 ^8 O! {
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let mylist3 []
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* f4 R* Y$ [+ }7 ~! l set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
/ i6 _6 c( b& H show count patches5 z* g* j6 c! S8 r& T
show mylist1 4 E- c/ {% K: d$ S* e( J7 W
show mylist3 G; X. `8 M. Q( l4 i9 B* c
end' r5 S/ R- B7 z0 @: f+ U% K
$ M1 i/ J, J8 z$ m9 J9 j这时的mylist1 和mylist3 应该是一样的 |
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