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发表于 2010-5-11 13:19:52
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用list吧
8 f/ l* W4 G/ X5 Epatches-own [wealth rank]
% T5 f5 Y) A7 tto setup4 F) c( E% L# f; T
ca
, x+ m7 p- g9 V) w6 [% s ask patches [set wealth random 100 set pcolor green ]
# g: H- V0 D% c0 ^# Z0 iend4 [0 g) h6 F5 ]* V$ R
2 Y, D2 H' k1 i# u4 e2 Dto go
9 s, U2 O. X- p/ Y# [0 k% Y; V6 E: T8 a let mylist1 []
' ?' _ U* d: q6 R- @/ s set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
: L5 J; A; U: n9 k let mylist2 []& r# g) t( f. _$ u3 [3 V
set mylist2 n-values count patches [? + 1]# C; f! Q. O' J8 F
$ j0 l( p. X9 R- ~9 p) G8 \/ R( }
( foreach mylist1 mylist2
4 }- h6 x- M0 P4 C3 x) F. S6 F, G [
. C' j3 M" I7 [& v' [& }2 m7 O ask ?1[ set rank ?2]
, K& T; o5 b! O- H- X& J1 k show [rank] of ?1
- D7 n1 g5 D4 D7 R* l; i : [0 s, S% X3 G- t
]
" I) F% e$ g( m% k( z7 h )# ^" z5 w- M9 X8 D) D5 {+ L* E
let mylist3 []
) M# t7 u8 N4 x% j$ U0 m0 A- x9 M 3 I4 c. e% q6 z5 v2 \
set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
* ~3 W& u2 C0 t show count patches& S. e9 q6 n; _2 n% C
show mylist1
% J$ G* L1 m" j6 b, q' w" } show mylist33 }! a1 F! o/ \8 a8 Z4 |
end
2 ` g" f# S. i! a7 r( [# ?! ]7 ]
: U4 K$ O% P# t这时的mylist1 和mylist3 应该是一样的 |
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