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发表于 2010-5-11 13:19:52
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用list吧% j: z* ` o3 q6 A7 p
patches-own [wealth rank]& X5 T! q3 ^3 R6 y2 F
to setup! o7 e3 U9 ?3 T! Z8 ~/ ~+ d
ca
$ a- t. @$ G$ l+ U ask patches [set wealth random 100 set pcolor green ]2 R. J) s) |; W
end% x( j% T- i3 ^' G: t
3 z, A i/ x7 f$ L8 y( fto go
' ~5 T9 q7 F8 Z7 G! l; z- i$ X- x) q6 M let mylist1 []
3 y3 b5 ^' F( ?0 C l1 |( C set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
( I0 u4 H& s7 L7 p let mylist2 []5 Y7 f! ]$ G: i$ _' z5 _7 b
set mylist2 n-values count patches [? + 1]
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( foreach mylist1 mylist2
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ask ?1[ set rank ?2]
4 X0 F0 Z4 Z ?6 E/ ?8 m5 j3 s show [rank] of ?11 P) u- k8 w3 J/ l8 A0 r
5 s5 f1 R" ^. y/ {
]
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let mylist3 []
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8 h& N& R* a N) w set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
D2 a8 a, N# Y: A6 u' Q" ? show count patches8 ^# u, N, E% K+ G9 q
show mylist1
' x" F0 Z1 I1 d* B$ M show mylist3
. d+ `6 F' N4 @( O S9 l7 w/ X5 Tend
& ]9 G5 o% y7 u% Y- P2 o p# `) ?- _ r8 }! G/ q
这时的mylist1 和mylist3 应该是一样的 |
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