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发表于 2010-5-11 13:19:52
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用list吧
0 s) l4 R0 \: V6 Lpatches-own [wealth rank]- E' U- J6 u( U* d- S. E$ b
to setup
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ask patches [set wealth random 100 set pcolor green ]% r1 L% H3 j) R- L8 e
end, G" B' _4 E$ u4 q; c% b* M/ j
% [& X2 ?/ i9 H2 R: @to go, P; f! z: m( @, i
let mylist1 []
0 x: X" d4 f3 S {9 r set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches9 |) P- [, A" O- y/ q
let mylist2 []
6 H. L1 B# ?& Q( z( k3 m set mylist2 n-values count patches [? + 1]
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( foreach mylist1 mylist2! t8 N; P! u' E8 r# s: P6 _6 T
[
. z2 E U; f' b) ? ask ?1[ set rank ?2] a3 ?1 a) p( b. p
show [rank] of ?1. _) m! \, J$ G
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]
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let mylist3 []2 z6 S7 d! e5 x U/ ?) M/ X. x
- Y* B, R, B8 ?. E' G# G" r set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches8 T a! S/ H( L/ m \7 Y
show count patches
. \0 c' X8 B: A1 C0 R3 q9 s show mylist1 * p, N+ y" k& w" B
show mylist30 W# Q" x+ M1 p4 E" P6 P& h1 f1 ^2 a
end/ _$ m O/ s/ ^" A7 O
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这时的mylist1 和mylist3 应该是一样的 |
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