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发表于 2010-5-11 13:19:52
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用list吧" Z. A5 I2 `! j; E, o( @ `6 g/ t& e
patches-own [wealth rank]
& n6 w: R9 C& l5 j o- Sto setup
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ask patches [set wealth random 100 set pcolor green ]& `' [5 w9 d3 s
end
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to go, ]7 c' l6 l/ C9 e$ z6 G
let mylist1 []
% q2 b9 s$ W3 Y% L) g" I2 y2 F set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
; |0 q Y8 O6 N* A let mylist2 []) ^$ U+ y& k7 Z' q' Y
set mylist2 n-values count patches [? + 1]* x% B" C1 x% J: b, a3 x4 n. s
) M! f3 B' O- ?( c" C% R$ ? ( foreach mylist1 mylist2
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ask ?1[ set rank ?2]5 ^! |! \$ V( O! ?7 u% [% q
show [rank] of ?1
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]
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2 d- @0 c8 g3 [$ D" V let mylist3 []$ m, G! z0 i5 z6 Z" h! D
' s0 {( s- o5 g* j6 i set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches6 j. O- h+ ]5 b) c( W& {
show count patches! z5 w6 U D# M. A, a
show mylist1
2 v7 y* O7 e$ \! s7 u show mylist3
6 d# o+ z% d* c- A+ aend8 }, _" {$ q6 v; f1 X
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这时的mylist1 和mylist3 应该是一样的 |
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