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发表于 2010-5-11 13:19:52
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用list吧0 o0 c: a' `. v# [
patches-own [wealth rank]
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ca
! U2 ^1 M: J+ Y* Q ask patches [set wealth random 100 set pcolor green ]. W5 H, [% y8 E' n4 @: b
end
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to go( A) F7 r" Q2 M8 \( G- \; ]3 m( G
let mylist1 []
! j1 R0 i* d v$ ~8 {$ R9 O |5 V set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
/ U3 y0 g0 a- y' f6 _" | let mylist2 []
' X9 P0 ~) Y! x6 g2 o' Q9 u( }! _ set mylist2 n-values count patches [? + 1]
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$ v5 b# i' Y3 U, H p; a ( foreach mylist1 mylist2( Z0 h* r( j/ w/ ]( J9 I
[3 X2 ^' T' p+ H9 J% M% F
ask ?1[ set rank ?2]/ ^- H, b$ j& F
show [rank] of ?11 E$ D |. v; S% \
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k4 Y& Y# s& ~$ D' d let mylist3 []" {* ^# ?8 @5 F: F; ?# e0 F
' \4 ]* i/ z4 K8 e4 p& w9 ^ set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches. a3 z% c1 F& w5 _! t
show count patches
1 X3 z1 |6 F: ~ show mylist1
1 k O9 B0 g9 ^5 K5 s show mylist3
: b/ [/ i. E6 iend
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这时的mylist1 和mylist3 应该是一样的 |
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