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发表于 2010-5-11 13:19:52
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用list吧2 H/ h1 ~% d% s4 t
patches-own [wealth rank]
4 ?( r# u, v$ w: b# tto setup
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ask patches [set wealth random 100 set pcolor green ]- w7 E4 ?8 O5 w* l
end7 @! a3 q6 D, c/ ^& g
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to go
. Q) A% b9 u, ?5 a: ] let mylist1 []
0 l/ \2 g q& A- P% y set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
4 |7 k0 R0 A8 A- u1 r7 i9 C) d9 e let mylist2 []4 `$ R4 U5 h0 `: w4 @5 |- b
set mylist2 n-values count patches [? + 1]
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) \ O y2 w# Y& K: { ( foreach mylist1 mylist22 D- h/ x' v' ?! |7 {) `
[
7 J4 c% Z9 J8 n& v* P ask ?1[ set rank ?2]5 g: Z- V' T/ {2 c2 \2 h) v, B
show [rank] of ?1
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6 _# i8 t* @1 w9 E/ w o let mylist3 []
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7 D0 W% G1 d, p8 ]& v2 w set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
. H! j, N8 ~, ~" ], j show count patches9 i2 \& s9 d" ^) e
show mylist1 - f0 u6 T' b$ @' S
show mylist3
) `( C. x6 Y% Z$ \end
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这时的mylist1 和mylist3 应该是一样的 |
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