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发表于 2010-5-11 13:19:52
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用list吧
8 I+ p. B7 Y2 R$ X4 jpatches-own [wealth rank]
6 G7 Z6 y1 m: b1 fto setup
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ask patches [set wealth random 100 set pcolor green ]
) K8 y- K# s, s0 J# \, T9 Lend
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to go) _. N7 g5 ^1 t+ C f) \
let mylist1 []
, l& ?7 K; @$ x0 y/ y/ X' P set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches7 P# \+ H. l1 _7 s! q8 V
let mylist2 []1 W9 p: m1 w0 e/ k" @6 `
set mylist2 n-values count patches [? + 1]/ s1 c* Y7 N0 H
: y5 e7 e, ]! `0 ] ]2 s, ^, f' O ( foreach mylist1 mylist2- i" Q3 [9 V7 U3 W
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ask ?1[ set rank ?2]6 o# ]& a2 J2 j6 N; {% F
show [rank] of ?1$ o+ N' {3 ~% @) N) l9 `, q. T
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]
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' t% N" ^" G5 f. ]( e let mylist3 []- s( U# H: ]% \0 a
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
7 M7 c( l/ S1 T8 B- k |3 R" t) J" w show count patches. `: K) s% H; a* M# i8 ^; {
show mylist1 7 G+ S; Y( P5 \
show mylist3
' |/ x& a6 g9 }end K i& I0 Y3 Q, x
6 y6 L j" a6 h, V, T这时的mylist1 和mylist3 应该是一样的 |
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