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发表于 2010-5-11 13:19:52
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用list吧
( d0 A8 U" H" |. u/ |( f0 l- upatches-own [wealth rank]
3 u; g/ U0 y fto setup
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5 l9 T6 E5 V; L( H/ z3 D# ~ ask patches [set wealth random 100 set pcolor green ]. k' b Z" d J! A- O
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* @, V/ f+ _1 ?& bto go0 ^5 W/ \3 n, j
let mylist1 []
1 V) @+ b9 `2 b, x. M" E set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches3 a% @' }% S% u: p/ B7 `! h+ {. P
let mylist2 []
" i0 i1 a9 }' D0 n' S- W set mylist2 n-values count patches [? + 1]
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( foreach mylist1 mylist2
3 E) r3 U% Z6 W [
/ }% }6 r2 l2 C4 t ask ?1[ set rank ?2]
, `3 `8 U* j, j/ v# B5 K show [rank] of ?11 A( J9 k7 u7 x, r
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let mylist3 []
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0 f' f- N7 _( t, X' d1 j- j set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches4 v+ l3 b" s: H2 ?# ~+ J
show count patches
; U. n/ s: q7 c. w" p1 _ show mylist1 9 c2 |9 C% N% l
show mylist3
4 u D$ y/ j5 kend1 s' R' l4 ~5 [$ I( |- X; p5 }2 k
9 J2 k% o0 _" P$ H这时的mylist1 和mylist3 应该是一样的 |
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