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发表于 2010-5-11 13:19:52
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用list吧 t: ~/ x. n+ X; w' F
patches-own [wealth rank]* i1 m+ ^6 \5 V4 g3 A
to setup# }8 P& n- k7 F. u9 A
ca
+ o4 y, L' i( y) `+ o ask patches [set wealth random 100 set pcolor green ]
2 a# X1 f: `$ Q+ H$ j' `: Fend
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$ }" D4 \$ a+ n9 k; U5 tto go
- @$ r9 p' G( q* {( J let mylist1 []
- z6 j! D$ P; ~7 y) M2 P set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
2 X, h/ D1 A- r8 e* g3 G let mylist2 []
5 a! \% R4 S% ~- k* S, X1 u! a set mylist2 n-values count patches [? + 1]
% C4 U7 t% H5 o0 W# Q" \
4 [# C' M6 w3 @, r5 J4 m1 K ( foreach mylist1 mylist23 E: N& y& M% S+ O+ g+ N. \4 E' T( h/ I
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ask ?1[ set rank ?2]% A9 Y( h7 _& S
show [rank] of ?1
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let mylist3 []
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5 k& F* t8 V& A3 Y set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches6 l9 ^) z+ s/ `* F! ?
show count patches+ j% D0 G2 V. K1 Z4 G
show mylist1 # H$ z: x) |) ~" A' Q. D: b- Q) A
show mylist3
9 @, F s. d. X; r4 }" hend
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3 ~/ m& A; g8 @8 M这时的mylist1 和mylist3 应该是一样的 |
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