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发表于 2010-5-11 13:19:52
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用list吧
3 J$ J- K G8 [: }2 g2 a Rpatches-own [wealth rank]
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ask patches [set wealth random 100 set pcolor green ]4 b+ ~2 y2 O1 j Q
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let mylist1 []
$ Y. y/ I& ^0 b set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
; \5 V/ ^+ j _2 E7 F$ A let mylist2 []; @/ b) o p7 m( F
set mylist2 n-values count patches [? + 1]) ]% U: b: |. d% @
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( foreach mylist1 mylist2
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( o/ _+ x" @, _- B ask ?1[ set rank ?2]* I q( _5 T# H
show [rank] of ?1
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" _& j# O" Q2 x2 T4 H let mylist3 []
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6 Z- O2 A( v. ?) P3 u4 v2 p set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches. q" F: h2 o2 X! N( [$ G
show count patches
& }8 S( ]4 }) A3 M. X show mylist1
2 F1 h2 ?" H2 `. f( L( m show mylist3: r5 r! Y/ Y8 A a F
end
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这时的mylist1 和mylist3 应该是一样的 |
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