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发表于 2010-5-11 13:19:52
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用list吧
& C4 R, Z: j: b6 upatches-own [wealth rank]
4 c/ k5 x" Q( q( \+ Rto setup6 K2 [3 I e0 @) \3 b% ~& d
ca6 W$ h% Y% x: `/ V2 p
ask patches [set wealth random 100 set pcolor green ]
' j6 o- H' B. l4 G$ ]end1 o& T' o! K/ D! J7 o- ]" Z
4 Y: q* [2 U' N. R0 O8 n/ ^1 Yto go
+ T) \, f3 t U- _ let mylist1 []
1 t4 z: @+ n5 N4 Y4 p set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches5 ]3 B, Q- l. D+ j
let mylist2 []
- v0 e, a) `. v# Z set mylist2 n-values count patches [? + 1]4 Y/ c' u! D, ~; l1 q
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( foreach mylist1 mylist2
9 P1 k2 U% W* D2 L( ^2 u [
. u" l; d$ D) }& J7 U ask ?1[ set rank ?2]
, m e/ i+ c! h- B2 a, z show [rank] of ?1
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]
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let mylist3 []/ I, l/ Y2 X+ o! r
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches' Y9 o: A1 J+ e* y. b
show count patches+ D8 H% Z# U5 i0 Z9 m
show mylist1 : Y, i8 K% w7 x( c; t
show mylist3
2 ]. J* L& s9 e( G4 y8 j9 Mend
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: @2 `8 g, q T0 X% Y. p1 F& T; ?' Q这时的mylist1 和mylist3 应该是一样的 |
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