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发表于 2010-5-11 13:19:52
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用list吧8 ?* F' \4 X. J0 M% N' i% d' T1 ^
patches-own [wealth rank]
# f0 D. l: o. r( o' g( ~to setup
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ask patches [set wealth random 100 set pcolor green ]! T+ j& Z) W% J! c* h0 S
end8 Z* c, D+ l$ b& ~9 S
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let mylist1 []; F8 \* y' d1 J9 |0 G
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches. L/ _8 J0 j% T: I& Z8 d
let mylist2 []' K# p7 C/ \; J* z' l8 H& {
set mylist2 n-values count patches [? + 1]
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6 n2 d" x9 i7 Y/ a+ v; N8 z ( foreach mylist1 mylist2& r, l C+ s M8 A2 I* S* h, w+ {
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ask ?1[ set rank ?2]: ^2 l# v# D! n5 Y8 G& b2 W
show [rank] of ?15 T7 y' N7 s0 ?4 M% _. _
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let mylist3 []
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches' @0 q5 K# N! n: K+ S; _
show count patches
5 s# y7 |; \4 w+ M9 B show mylist1
. N. E* @' _ h1 V show mylist3
' B, T/ G0 x$ h1 r5 \- Iend
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3 v6 F3 X, ^) p4 i/ O& I- [" r3 d$ h这时的mylist1 和mylist3 应该是一样的 |
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