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发表于 2010-5-11 13:19:52
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用list吧9 ^3 E8 E0 d* F- @) Q
patches-own [wealth rank]
d; t3 E3 h0 K3 nto setup
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. ]* {9 p" [! M0 I ask patches [set wealth random 100 set pcolor green ] ^0 t3 j9 j4 h5 P6 ~$ b
end
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to go
1 L8 ~& g. f: x% ~% D2 W) s8 }9 j let mylist1 []
a; d6 g- l& l( t/ y set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches! y- u) J; R1 d- Q& \
let mylist2 []5 v, c9 O- F- \& Z# a( N6 C( ?( {
set mylist2 n-values count patches [? + 1]
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( foreach mylist1 mylist2/ ~( s2 _$ @% ?; p
[
6 z3 \: r: w8 w3 w3 Y& b2 A' k ask ?1[ set rank ?2]
$ f* B$ i) G% |+ i show [rank] of ?1! D+ O: H( a/ s- H9 \. O
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let mylist3 []
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: A9 c% o" r0 X) {1 P set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches7 m3 F1 \+ M) |9 x2 E0 {
show count patches/ @1 x5 c4 R( H0 f; V8 |4 E. j
show mylist1
( A- e# r, A2 B9 S7 t2 r/ W show mylist3
* I: d4 i) H) w: O* cend
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这时的mylist1 和mylist3 应该是一样的 |
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