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发表于 2010-5-11 13:19:52
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用list吧3 Z0 U' B( c8 u6 V$ H* c3 Q. U) H6 l
patches-own [wealth rank]
3 S9 L/ b: i gto setup4 X. {* S; ]$ C! ^2 k
ca
; {1 E( C" e6 K8 a6 K ask patches [set wealth random 100 set pcolor green ]
7 N0 n$ n. |( D# ?end
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to go
5 w, L+ ~6 q: O$ C% P let mylist1 []
/ g& N# L2 Z- O' i6 _ set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches1 Q6 \7 e! |$ p9 _1 O$ ]5 D& J; u7 T
let mylist2 []$ M9 {; m/ Z2 P7 o
set mylist2 n-values count patches [? + 1]: ~: h( ~0 p) @' m9 ]) b( `3 H
+ X, M: D. l% u# j% w9 k6 C* d! d ( foreach mylist1 mylist2
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ask ?1[ set rank ?2]
U5 L. g0 y( S' i2 c) E0 ?( h+ E show [rank] of ?1' S0 @6 K1 Y1 h7 E; B
7 I2 i) q4 K0 f, O& c. U N0 | ]
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5 y4 u; e( H7 ?" W: w let mylist3 []
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; D2 G* f$ k) R; M set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
8 f% C. D' U, F$ r7 Q! l" i show count patches
3 u% \* m! I( Y. k* `* I% }, f( F show mylist1
, f9 p( s" h( q. N W* ~ show mylist3
4 ]: k* _1 e) b* yend% U1 U8 O# C# w* Y* D3 e! Q4 _, d4 {: g
; m/ b, S1 L8 z" {这时的mylist1 和mylist3 应该是一样的 |
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