编程遇到困难 请帮助

ding1617

to meet-wolf;; wolf procedure
6 z- i: S1 v  \  if count wolves-here >  0           
- V1 ]/ U. |! q: S: V& o  [let otherwolf one-of other wolves-here                     
    if abs ([k1] of self - [k1] of otherwolf ) > value-k1
' f+ n4 R; m% ?! u1 J' g" v   ]
   [ set  [k1] of self [k1] of self + [k1] of otherwolf
   ]
7 l3 V5 h: W. U3 q7 I0 X; A& |     end
2 k9 E+ a; ^% A# \显示otherwolf没有被定义，请各路大神帮忙调整通顺

SsendasX

应该是other wolf，，，吧