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发表于 2010-5-11 13:19:52
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用list吧' F' c3 d! { s2 H0 W) Q! E
patches-own [wealth rank]
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ca
3 x6 b, X9 O$ [8 v ask patches [set wealth random 100 set pcolor green ]
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to go) B a8 q6 u) r: W. Y4 L, \3 y
let mylist1 []5 @( x: J& A" K8 u
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches% P8 u" N" v- H/ j; K
let mylist2 []
+ |$ s4 `+ h9 R2 G8 l set mylist2 n-values count patches [? + 1]6 X( C/ i. I& h' C9 z3 j. \' _. a
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( foreach mylist1 mylist2- k1 ?2 H2 g4 c) T
[
6 R; L& Q9 U0 O% P* {& r ask ?1[ set rank ?2]
% @! U& a7 l1 Y) @/ W" A; Z8 d! p* { show [rank] of ?18 Y( y# k7 a" l7 d" x j
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let mylist3 []
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# ^) x" @# X) h# n, L set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
( o$ w% q6 g) z) w2 o8 C show count patches: g& R- y5 T% t4 G, E- Y2 D
show mylist1
& z4 m2 d. w A show mylist33 T* n, [$ C3 H. X+ c' q
end+ s; v: D% ~ B! A" G) s9 [
: f; X* a* z/ j7 H0 p1 y这时的mylist1 和mylist3 应该是一样的 |
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