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发表于 2010-5-11 13:19:52
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用list吧. r) R2 d$ Z3 B6 W
patches-own [wealth rank]
7 g" m5 |( l' b0 i qto setup
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ask patches [set wealth random 100 set pcolor green ]" S) y% N3 ^$ }( S' b
end- ]% n, B6 a6 ?& }& P) h& B+ _
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to go; v' Q) j3 _* n. _ X- f
let mylist1 []8 M9 R4 M# O/ f/ i- q% F
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
+ L# Z5 R O: j- I6 M+ f ]( a let mylist2 []
8 u- }5 Z7 ]( p# b set mylist2 n-values count patches [? + 1]
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, Q, g+ `( t3 a! q1 [& f1 D ( foreach mylist1 mylist29 F& b- o! K* n8 ~7 J
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ask ?1[ set rank ?2]- M5 a5 F/ F4 n3 @ |- Q
show [rank] of ?1; k3 r8 h7 W I, J1 V# `3 `" ?
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, [# U. O, b% F0 m let mylist3 []% [: U- O3 b3 I3 S; s1 V
: z4 a& T' r2 z2 R6 q6 K set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches6 M+ t& w; N: a. ]* f. m0 j
show count patches7 H2 T4 _: q* _: {3 t6 a
show mylist1 ( d6 q8 f* `; E8 r- ]/ i. K8 `
show mylist3
& n; E2 N) L. {end
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N2 E3 F+ u& x3 m4 |5 L这时的mylist1 和mylist3 应该是一样的 |
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