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发表于 2010-5-11 13:19:52
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用list吧6 }/ h$ `3 |! B- ?0 H$ k5 D; o
patches-own [wealth rank]
7 n( j6 ?+ L* Dto setup
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ask patches [set wealth random 100 set pcolor green ]
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8 ]9 N; A* k! }to go
* c% _& S* U2 A6 d& P. Z/ N9 V, w, m( e3 ? let mylist1 []9 n; r! Q0 c7 e' |" K% \
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
6 G* \7 H) S( F1 @& A p* c let mylist2 [], {+ _* y7 i0 B6 L( V
set mylist2 n-values count patches [? + 1]* g9 K0 i2 q' g7 ^1 R! u
8 E& x: q [5 D' u9 J9 z ( foreach mylist1 mylist2! y; u3 u D$ e: _. A- `
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ask ?1[ set rank ?2]/ e+ n4 m B3 k
show [rank] of ?1
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let mylist3 []
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% {! H. Y' c' B' j# N. F6 y+ ~: E set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
. y3 S/ Y+ ^) Y! B3 J. D) V! h show count patches
H5 P9 O! i9 C' T `$ k; C show mylist1
, U( z) m4 E5 H- J, y' d3 P: W$ N _ show mylist3
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这时的mylist1 和mylist3 应该是一样的 |
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