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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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) J4 t% b, I+ B- m X不好意思,打错了个字母,呵呵呵!9 A/ g" e9 V/ r' C& H9 J, J
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示% d1 V9 b" ]( e$ c }* x* k7 l x
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!3 i( r9 k1 S$ w6 {) ?6 J
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j,k,nstep,c, scheduleteps,mincomptime:integer;# S; _6 k8 r& K+ p+ X
M:string;
0 u# K' P6 P4 S: P; v selecTab:table[integer,integer,integer,string];
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initorders;
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scheduledorders.delete;
6 H# A7 P: x1 M+ E/ R" g seletTab.create;) p9 v( |; G- d* f
6 ?5 s, [) x( w! h3 F orders.initialize({2,1}..{2,*},0);% K, o$ ^4 ~9 k, D! g
orders.initialize({4,1}..{4,*},0);
( g' d) i9 n) y8 L0 W$ w& p% s5 t+ V for j:=1 to numorders loop P* Q3 T+ M1 l$ k- w4 E
orders[5,j]:=orders[1,j][2,1];
" V9 U% v4 y+ Y0 k7 t next;
, }' m F' K( T0 C" r1 V0 X1 ? occres.initialize({1,1}..{1,*},0);
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--XUNHUAN7 @4 C: ?; z) s- j
for scheduledsteps:=1 to numsteps loop --
8 Z$ Z0 T' a( V9 \9 x: g8 S( [: N2 V selectab.delete; ?% Z) I6 t- `" h5 I/ X$ i6 F+ o
k:=1;+ x4 O" @0 A0 N/ H3 P* j
for j:=1 to numorders loop: Z6 o( V0 p% `* `
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nstep:=orders[2,j]+1;0 E% B, \2 Z% S" O& }2 D
if nstep<=orders[3,j] then
" Y' A& W9 a& J* H% Y selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
2 [; H& ?' B2 T' ]/ k; \! [$ ^ k:=k+1;
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end;
7 g# G3 D1 ^5 G y; _ next;
% X* m9 J; L4 A3 s4 \" b mincomptime:=selecttab.min({3,1}..{3,*});
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from j:=1 until j>selectab.ydim loop
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( p3 S3 S5 H4 R& }3 E if selectab[2,j]<mincomptime then
- G$ A( Q: Q o% R5 u. M j:=j+1;
2 V$ |+ A+ i+ T2 k/ ^* B else
; d: E! m: j1 _( V+ H+ V9 F selecttab.cutrow(j);7 }6 ^+ a5 I( k: B
end;6 N+ w% H0 S# z
end;
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j:=selectionrule(selecttab); L9 s( M9 ^, T$ c" k2 a. o
) P h$ t- p3 \% O nstep;+orders[2.j]+1;: {" q/ V. ?1 e {* N, T7 ~
orders[2,j]:=nstep;" E$ u* }/ w0 n/ S& Q3 W# N
m:=orders[1,j][1,nstep];, }7 J! O- a9 Q
c:=orders[5,j]
( C3 S+ E1 `' K% @, d; b# R occres[1,m]:=c;
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9 S+ w: y- V1 ]; }1 `8 A --jieguo:start,end,res,job,step. f4 F: ?. A9 x
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);0 z$ J# o2 L* a4 P x2 L. f4 } R
for k:=1 to numorders loop& c5 _6 I; e8 D7 P! D) [$ ~* h
nstep:=orders[2,k]+1;6 r6 H& [' i) A$ x" q* P/ y
- e& k# R2 g- C, m9 v! t, p1 L if nstep<=orders[3,k] and orders[1,k][1,nstep]=m8 ~( a% S5 E) a" w
--, U( N. E+ k5 Z L5 `" b
then
1 z8 t* i, r8 F4 v: G/ }4 m1 y* ] orders[4,k]:=max(c,orders[4,k]); z* m! ~ h0 n6 d
--
& b2 v1 c; K$ K4 C" Z orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
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end; t$ p3 Y5 n X4 |- m6 |
next;& w. t3 F# a: N8 T
nstep:=orders[2,j]+1:
E! s) M0 \& }" b: W6 T9 l if nstep<=orders[3,j]2 r: j8 W; ]' h6 I, m+ C. T! f7 g
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then0 D0 a5 s% O1 i4 ^1 }
orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
, D- q, d) e! A( M! k* o orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
( F# j8 P2 [' K- X" {3 M end;% L: l1 z* H2 [4 x- Q$ g+ s1 {
next; l# ?" n6 ?5 W% M# b
# o; c: ], h7 A5 ^: k* T2 P3 k print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});( @: @, L; B" u# W+ Z
mygantt;9 h- c4 a4 T/ L% G. X7 v' T
ens;; q; J( I, ~" J
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