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本帖最后由 soso001 于 2014-12-17 14:53 编辑 2 J7 l+ \+ H0 m9 y8 W! N
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不好意思,打错了个字母,呵呵呵!
, v' `/ Y! m5 Q r( T大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
) a) H- H# a2 p8 ?8 z5 w“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!" k5 q R, z5 _- I7 f U) u/ w
is
; H7 G3 y M" S. `' q1 m" } j,k,nstep,c, scheduleteps,mincomptime:integer;
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selecTab:table[integer,integer,integer,string];) V5 ^& Q8 w7 K" r
do8 M' U- b# g. x- I5 b
initorders;
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scheduledorders.delete;
- c% {$ f4 K3 {- v% a seletTab.create;
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orders.initialize({2,1}..{2,*},0);
# w$ I3 E. D. h" h, c orders.initialize({4,1}..{4,*},0);5 {) X. t) R2 M* F0 ^9 S. j
for j:=1 to numorders loop% P4 G: {$ S P. @* s
orders[5,j]:=orders[1,j][2,1];
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occres.initialize({1,1}..{1,*},0);
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3 }( `: f1 E/ [4 z --XUNHUAN
0 N0 H& m& k+ `8 m for scheduledsteps:=1 to numsteps loop --3 P4 F+ B" r! E- [
selectab.delete;4 b8 Q1 _$ D- H& s, R+ _
k:=1;
& |4 |/ F8 y! t l7 j) R for j:=1 to numorders loop
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nstep:=orders[2,j]+1;
* v' w- h9 I$ L; }7 b+ }0 p7 g if nstep<=orders[3,j] then. @: [1 ]: s% S8 @- o. t3 g
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];3 `$ P% ]4 R) t; W. `9 K$ [
k:=k+1;4 c; C; t& _# x
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end;
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mincomptime:=selecttab.min({3,1}..{3,*});- T# S$ y+ T. p& J! o" l+ j) s% z
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from j:=1 until j>selectab.ydim loop
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t1 W" a u7 }' }* s# M% W if selectab[2,j]<mincomptime then
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else
2 z" R9 B% ]' Q5 v5 Y# z2 A7 i selecttab.cutrow(j);
/ ^+ z* v# k& K end;
, w- T. G4 n7 V2 r end;
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, E/ M6 W1 y' Y* D7 W" v; J j:=selectionrule(selecttab);, O: ^; R5 h+ B$ k5 ^
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nstep;+orders[2.j]+1;
' Z) d7 t1 ^4 L* B9 |" J orders[2,j]:=nstep;: c: j0 K; N, ^# ?
m:=orders[1,j][1,nstep];
: u }( G- E( t* H) U2 C) h& ] c:=orders[5,j]( `( W: j+ O/ Y
occres[1,m]:=c;% S; I( E" O7 X6 o# b
& N1 ?, ^; P, \3 c4 P- C& q --jieguo:start,end,res,job,step
1 j$ I3 S$ B4 ^1 c. y# S' S scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
/ Z! ?$ u: M2 \! ]# q$ H. H for k:=1 to numorders loop7 A- o# R3 K4 P) _
nstep:=orders[2,k]+1;
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8 b9 Z2 ]' a: C% C2 n if nstep<=orders[3,k] and orders[1,k][1,nstep]=m3 V) s. h% |7 O3 f8 v6 J
--
: T0 V+ [7 @$ ?/ { then
! K5 m4 c: P5 Y: t orders[4,k]:=max(c,orders[4,k]); g+ m% r, j: r% R W2 O
--2 @( J+ C$ n( v2 ]" ^3 k
orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];+ N6 R C. O4 {+ \
--
# U5 u' b! R8 T1 p0 q. j0 W end;
- u; t/ ?+ ? W. f$ M& c9 [: M9 F9 F next;
5 c& F9 O/ `% a* M% @9 F2 d nstep:=orders[2,j]+1:$ O8 d0 v3 H# w. x, Q
if nstep<=orders[3,j]" H6 V4 q: i- Y7 e @
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orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]); U# g0 }* V! t d7 U0 W
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
2 z1 p G- {. `0 ? end;& F1 C1 Q9 a7 ^+ m
next;
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1 |) v9 {$ B# @/ Y! a print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});0 ~4 b9 w0 {/ z( {5 ?
mygantt;" d5 S ]* v! U
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