我在试着编程，很简单的取随机数，可就这样也不对，我不知道哪里错了，编译时没问题，而且在Eclipse环境下运行JSimpleBug的例程也没出错，可为什么我这个简单的试验程序却出错了呢？帮帮忙吧。在Eclipse环境下。/ A4 e$ k: F9 K: O. g
import swarm.Globals;
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% D# p" U3 S+ b0 m5 i' Wpublic class test {4 i' R+ G3 r- q* z
/*** T; O8 U! [# N
* @param args. B" ~" X3 g- g
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public static void main(String[] args) {
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, E1 ?" m& Y* } int y=(int)(10*Math.random());
- ~: h/ C( g- G) o3 m9 d; K: X System.out.println("result is "+y);
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" d9 _; R4 Y# \/ ]7 b double z=Globals.env.uniformDblRand.getDoubleWithMin$withMax(0.0, 1.0);
& Q' G2 c! n% z8 a7 d5 n System.out.print(z+" re");8 k0 I8 T5 D1 v3 B; O9 s/ e
}
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结果是：
+ B0 B) g+ C) P% ?6 Hresult is 2
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3 Z9 a" Y5 }7 d) Z) z# An unexpected error has been detected by Java Runtime Environment:
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# EXCEPTION_ACCESS_VIOLATION (0xc0000005) at pc=0x100b8305, pid=1064, tid=10685 o2 W8 V- S3 Y4 w; p }
#
0 _9 e# y0 j; ]( R# Java VM: Java HotSpot(TM) Client VM (1.6.0_01-b06 mixed mode, sharing)
2 ~; d- b( q" U3 }( q# Problematic frame:
8 X. L6 P6 c2 E/ `, F! L# C [javaswarm.dll+0xb8305]! X* o6 s- @3 ?
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# An error report file with more information is saved as hs_err_pid1064.log |
发表于 2010-1-27 11:16:30
楼主