我在试着编程，很简单的取随机数，可就这样也不对，我不知道哪里错了，编译时没问题，而且在Eclipse环境下运行JSimpleBug的例程也没出错，可为什么我这个简单的试验程序却出错了呢？帮帮忙吧。在Eclipse环境下。5 d. B& Z& G( ^' u3 m0 M
import swarm.Globals;6 ^6 Y5 l$ u- l9 Q& D5 ~
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public class test {2 n" t8 e& A0 D1 |2 A6 z
/**& }% ?9 a) p2 y+ R
* @param args" U( F; m0 } A5 A
*/! v: b Z- v8 {
public static void main(String[] args) {* P& a5 V% ~2 N- N& C. g- }# o
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int y=(int)(10*Math.random());# b( Z# f$ ^- b4 q
System.out.println("result is "+y);
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double z=Globals.env.uniformDblRand.getDoubleWithMin$withMax(0.0, 1.0);
6 p# i' X# V3 T System.out.print(z+" re");
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8 {8 _, k- v# T# O结果是：$ M' Y& d- i( b9 L" D% }# K! ]! N
result is 2
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|3 I6 S- \1 z, o$ e1 p* P# s# An unexpected error has been detected by Java Runtime Environment:
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2 _ s+ |7 I& @+ T4 T c# EXCEPTION_ACCESS_VIOLATION (0xc0000005) at pc=0x100b8305, pid=1064, tid=1068
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1 m& Q7 ~1 ^& j# Java VM: Java HotSpot(TM) Client VM (1.6.0_01-b06 mixed mode, sharing)
" d9 W0 s2 D4 \3 d# Problematic frame:
8 C3 k: F9 E) l+ `# C [javaswarm.dll+0xb8305]
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# An error report file with more information is saved as hs_err_pid1064.log |
发表于 2010-1-27 11:16:30
楼主