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发表于 2010-5-11 13:19:52
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用list吧
- e4 C. [) \- T( C, }* S4 Ipatches-own [wealth rank]
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ca& G' e0 ^# d& T( D; X2 r u3 P0 O
ask patches [set wealth random 100 set pcolor green ]/ ~5 \! d2 E; n& a; C9 W5 M- E0 p% z
end! K2 N+ o6 a: \" k7 ?
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to go' X7 q% I6 }5 H4 V
let mylist1 []+ v h) s4 z8 ] [: P1 H9 C. Q
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches2 D [. y$ I5 i! U4 ~& B
let mylist2 []
/ H# Z5 G. i" c6 S/ v set mylist2 n-values count patches [? + 1]
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" e( N; d9 g/ f% e6 U+ t( e0 ` ( foreach mylist1 mylist2
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ask ?1[ set rank ?2]
" f6 b6 q$ `: {7 K2 p( t5 i show [rank] of ?1+ o& a* ^# {( z+ o3 G: m
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let mylist3 [], d; I# }" P7 @
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches* s- ^( z2 Z* O; V' F) J8 r# _
show count patches' s- \! p, M4 z1 `! D% X
show mylist1 / M, q; t) G# d8 ?
show mylist3
5 B4 O0 K5 }( M3 d& h8 Aend, E4 L Q7 [* g/ Y0 J( K1 E
1 G7 w" |" J3 @: u: ~7 V# G3 r# ?这时的mylist1 和mylist3 应该是一样的 |
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