编程遇到困难 请帮助

ding1617

to meet-wolf;; wolf procedure
  if count wolves-here >  0           
; A; b; J* A" U% t) w2 }6 \+ D; F  [let otherwolf one-of other wolves-here                     
    if abs ([k1] of self - [k1] of otherwolf ) > value-k1
   ]
   [ set  [k1] of self [k1] of self + [k1] of otherwolf
1 X, V" L: P4 d; L   ]
     end
  R8 g: [0 b5 p# ?% o显示otherwolf没有被定义，请各路大神帮忙调整通顺

SsendasX

应该是other wolf，，，吧