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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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不好意思,打错了个字母,呵呵呵!
# G" P' ^5 b! C2 K8 P大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示. ?5 A5 Z* H. L$ s
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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j,k,nstep,c, scheduleteps,mincomptime:integer;
8 ~) J0 u) r5 O& ~! N M:string;5 c: F/ O5 T3 E; I7 D
selecTab:table[integer,integer,integer,string];# A% U- N& i. W3 a- L
do0 P/ N6 t1 `" |% h
initorders;
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scheduledorders.delete;0 E# r5 Q' Y1 D( j- Q ?2 x9 o! V
seletTab.create;& C+ c9 a0 @+ n% H8 Q
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orders.initialize({2,1}..{2,*},0);
c: d: D+ \* m3 R- _/ s3 {6 | orders.initialize({4,1}..{4,*},0);
! b$ M2 q9 G6 C# }& R for j:=1 to numorders loop
7 L& @8 y+ x" a5 S) ]2 o orders[5,j]:=orders[1,j][2,1];! M: P( \' q) t* U+ p9 f" I& c! f
next;0 u% p3 K1 z M: {
occres.initialize({1,1}..{1,*},0);
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--XUNHUAN2 \) |4 X- F" p, X' t
for scheduledsteps:=1 to numsteps loop --
' ?: ?& }$ Z9 [. m, j/ { selectab.delete;$ U4 n% K# F; Y& A: k0 o) r
k:=1;% G9 b) `) k& w% |
for j:=1 to numorders loop( v/ M# c4 `- r
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nstep:=orders[2,j]+1;
. o/ g; O# K9 ?0 n/ s6 X if nstep<=orders[3,j] then
3 k) e# R5 C" b7 g1 b$ F: y selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
8 i, k# @6 d) q" S4 i1 p/ a k:=k+1;
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next;1 g# A7 Z% R5 W; }5 k! O; z
mincomptime:=selecttab.min({3,1}..{3,*});
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2 I- @9 |1 h6 p7 s from j:=1 until j>selectab.ydim loop
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& h% C/ \# R; t/ Y9 }# h9 S if selectab[2,j]<mincomptime then0 m% N( }* M) N2 r6 ~2 j: e- V
j:=j+1;
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selecttab.cutrow(j);8 k) I* ]/ }# H" m
end;
- k2 E% j/ l6 g. P, {' R7 T7 W end;
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j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;6 W' j( e9 R% h, |& Q
orders[2,j]:=nstep;
! f# J# k5 B. C- n% S7 ^ m:=orders[1,j][1,nstep];
* J0 v3 W# Z" m3 E c:=orders[5,j] G" S8 o; N' |* D! H2 ]5 I
occres[1,m]:=c;
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--jieguo:start,end,res,job,step3 k0 h+ g6 b+ J! j
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
8 u; x u w9 z2 Z+ x for k:=1 to numorders loop
P# Q' {# s+ q Q nstep:=orders[2,k]+1;
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1 X- e- l1 L- p9 J. S if nstep<=orders[3,k] and orders[1,k][1,nstep]=m m; B. x" d6 L
--/ @# }+ |" ^6 y0 p& T
then/ P+ f* W2 ] m' l& m; h- ]
orders[4,k]:=max(c,orders[4,k]);
/ g: I) |3 v+ z3 A3 { --
% r- V) h* j! s7 l7 o orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
* g# |) U3 Q% w( {0 Q --
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next;4 ~/ |1 ]! [+ O2 s$ w$ ^
nstep:=orders[2,j]+1:
' e- T9 w/ B+ m" |' D if nstep<=orders[3,j]
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then8 `/ d; X: ]$ o2 L* e: S! U
orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
; J! w2 s+ C' A; g6 T0 D orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
8 P& }2 s4 v4 G9 s* [ end;% c) A3 K) \7 h( b7 v/ E. ]$ @. Y$ _
next;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});1 S$ }+ J5 [1 |8 _ S; B( X4 V- P
mygantt;8 w+ V$ b. p/ {2 U' n% S) V6 k* |
ens;
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