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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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不好意思,打错了个字母,呵呵呵!3 m% `$ r3 X2 J2 c/ f7 J g, c* r
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
: y* c S3 H0 C# ^“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!6 Q+ G: [* I- q! P% X2 d5 u. c
is
4 i; I4 y- D" j& M j,k,nstep,c, scheduleteps,mincomptime:integer;
' T- n" A3 G6 c7 C( D' D+ y M:string;" U, r+ @# n- {* |' n' M6 Y* P3 w9 b
selecTab:table[integer,integer,integer,string];
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. s& t' }9 j: L1 y initorders;, g3 a* x$ j: @
! Y8 {, X- d$ L7 R5 r, Z scheduledorders.delete;6 |0 g( B" M3 Z% f) V: z- x8 @
seletTab.create; Z* s5 h2 D% a0 H8 w
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orders.initialize({2,1}..{2,*},0);: e3 H# o' l! T+ u: d
orders.initialize({4,1}..{4,*},0);$ u* p% ?& ^. k5 ?/ _
for j:=1 to numorders loop( L- L/ `* z8 t- B1 s; }
orders[5,j]:=orders[1,j][2,1];$ G) n* ^- e7 [7 c2 Y9 V
next;
$ g3 I7 r S. k/ l% N occres.initialize({1,1}..{1,*},0);
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3 C: X Z8 _6 q/ ~. H. J --XUNHUAN
. g9 a9 G' H! R* r, f F/ { for scheduledsteps:=1 to numsteps loop --
5 p, }2 n+ J( D. E) v$ Z$ w selectab.delete;: F" ?" { T, t8 ?
k:=1;
3 Y, [3 o0 d% T( {4 ]7 G. _$ j! k for j:=1 to numorders loop
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1 v" A; s* m2 b: M# v8 D2 N8 t nstep:=orders[2,j]+1;; m# B: v7 T, @% U
if nstep<=orders[3,j] then1 D5 G- w" ]6 m& T. [/ m! {9 Z/ P
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];% f& _, r4 L6 R9 j; O' v, j
k:=k+1;
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. M' r `$ L1 V/ @ end;
% r" V7 f/ r2 s' n7 h3 f next;1 N( l+ r- q4 L. d) H
mincomptime:=selecttab.min({3,1}..{3,*});: r( S4 _% ^# O
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from j:=1 until j>selectab.ydim loop
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if selectab[2,j]<mincomptime then
9 W& j8 V& X' @1 Y' t! p/ E5 i j:=j+1;" G9 a+ P4 R( D) U* Q
else
8 O1 M, z+ \3 Y selecttab.cutrow(j);
0 f' p) C7 v; M# t+ q4 t end;% h; J4 I& k- L' z
end;
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j:=selectionrule(selecttab); R" z/ ?( P1 W1 _' s
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nstep;+orders[2.j]+1;. C% I O3 x9 a( s
orders[2,j]:=nstep;1 C% n" k/ l, R3 x# |9 N9 y. g
m:=orders[1,j][1,nstep];. p) W1 d2 `( C. ]- L1 T" |
c:=orders[5,j]6 o% S5 K/ A" |! X5 @" H- A
occres[1,m]:=c;
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--jieguo:start,end,res,job,step
5 B2 _! | e& M8 L$ n3 q+ _) @# K scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);8 B/ d6 ] m0 v
for k:=1 to numorders loop% T! |; v8 S" i
nstep:=orders[2,k]+1;
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m+ n5 w% L2 D, i5 F! V5 R
--, `3 |) J+ _) b' i6 G6 y
then
6 b0 m" A. z. I orders[4,k]:=max(c,orders[4,k]);
) g B: h4 V. `7 o& T ] --
! X) l! M( s+ C7 g4 [/ s orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];/ O# X4 H8 b. _/ X' g" H
--
4 X- @% \+ I8 h! h/ b end;2 i/ R1 b: e6 K7 E' v
next;4 F5 P1 m, j7 z$ ]% l# |
nstep:=orders[2,j]+1:
' X8 I' v# l% {. F if nstep<=orders[3,j]' `9 y) N* L& }& a( e$ [! ]6 \
2 {/ d. G- @" }: @ b9 n then
3 S/ i8 y- {/ y6 g& z orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
* y# ?+ c: `" D* z orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];. H ?& {% ?+ O" d- i
end;
; e6 R' ~4 o/ n9 v next;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});9 v- `0 H1 i0 A6 z# R
mygantt;, a n9 B; o: X# G
ens;
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