我在试着编程，很简单的取随机数，可就这样也不对，我不知道哪里错了，编译时没问题，而且在Eclipse环境下运行JSimpleBug的例程也没出错，可为什么我这个简单的试验程序却出错了呢？帮帮忙吧。在Eclipse环境下。
; w* N/ {( s- wimport swarm.Globals;
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" ^. f! x/ \- U6 d# U) Lpublic class test {5 m9 ?& T0 T# I B" w0 S, o
/**
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public static void main(String[] args) {2 T4 r! k6 M/ P6 G* m
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int y=(int)(10*Math.random());8 E+ W. W4 r7 L0 D( X
System.out.println("result is "+y);3 A$ Y$ ?9 G' ]* \! e
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double z=Globals.env.uniformDblRand.getDoubleWithMin$withMax(0.0, 1.0);
- S& F# J. M& D# @. W5 n System.out.print(z+" re");
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}
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结果是：2 K" `6 E1 G2 ]
result is 2
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# An unexpected error has been detected by Java Runtime Environment:8 Z6 {; A6 y( d5 O4 Z
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# EXCEPTION_ACCESS_VIOLATION (0xc0000005) at pc=0x100b8305, pid=1064, tid=10686 r3 H7 R3 c0 P: G. j
#
7 \+ }2 y P; Z s' z0 h3 v# Java VM: Java HotSpot(TM) Client VM (1.6.0_01-b06 mixed mode, sharing)) s y+ O6 k" `) a7 @5 j
# Problematic frame:& i) Y9 u( D% |# I1 }6 X* b
# C [javaswarm.dll+0xb8305]$ C C$ d$ j0 Q, _+ L6 b
#! i3 ?9 S! X1 J) |6 h
# An error report file with more information is saved as hs_err_pid1064.log |
发表于 2010-1-27 11:16:30
楼主