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发表于 2010-5-11 13:19:52
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用list吧/ t, P6 U' P$ a# t% ~ l
patches-own [wealth rank]& c) E( j/ K5 j! |" w
to setup9 L0 q4 T. F0 {; U
ca
& s5 [; x; l8 z7 U/ u1 n ask patches [set wealth random 100 set pcolor green ]
* P0 b& j: p; r* m0 f$ qend
1 r1 p* S8 ?2 a7 O+ D! X% y* @3 s% u
to go4 {3 t& l/ B' J: E2 T; B' j
let mylist1 []
$ J. b/ K$ m& V" Z; [$ U2 e set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches, m" J- `( t: b3 O3 X
let mylist2 []; B3 w# f% L$ Q+ N4 h9 s; I
set mylist2 n-values count patches [? + 1]. S% g' X4 s7 [5 O% \
9 w$ {6 @( g$ r! l2 Y4 ]' ^6 A ( foreach mylist1 mylist22 I7 o$ h* O9 x2 a
[
9 P: Q x: u9 X8 S: q ask ?1[ set rank ?2]
5 f3 p: m; }. O/ ^6 N show [rank] of ?1+ }- ^& J# @0 s4 ^+ W
7 D, m, _8 v) p, D ]
; F8 o! X# f' U )
0 D! \. v e/ u let mylist3 []5 a$ H& e% @3 a+ f4 x7 y
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches6 ^+ S0 |' |! n; ]8 T
show count patches3 k; l1 {- ~6 r: F2 L8 Y
show mylist1
' a+ s. ]4 a/ W show mylist3
5 O0 P) l# ^& K0 t! b1 A4 }8 pend
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% g# i3 E8 a* P5 t# e S; b4 r这时的mylist1 和mylist3 应该是一样的 |
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