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发表于 2010-5-11 13:19:52
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用list吧5 W0 q7 w& U" L" X( A
patches-own [wealth rank]
9 c8 v; l2 @% G, Hto setup3 Z0 j) F( A# `* a2 l$ J) u; d# v
ca6 p- _: J! d$ }, G3 v
ask patches [set wealth random 100 set pcolor green ]
- `4 H% ~5 v+ aend
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( s N, t, [ j0 M3 Yto go( K6 o& @7 `1 t
let mylist1 []
: x2 Z7 X( r1 v- J S; { set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches3 N4 a0 n0 u, t2 W( ]. {
let mylist2 []
0 h0 g/ F6 H2 L, X6 ?+ Q2 S, W set mylist2 n-values count patches [? + 1]
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8 j5 P' z$ O. e( Y" [ ( foreach mylist1 mylist2( B4 y1 z0 c# | C4 b1 y
[
7 e* M$ |: U [. K( v* _* q ask ?1[ set rank ?2]4 ~" f) o& z9 q7 Q/ `
show [rank] of ?15 f6 l: D/ j' P! x. b0 S" _6 o
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let mylist3 []% o' @* A9 D* \ P6 u
; ?( i$ U- p( n7 V1 E! X
set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches" C9 R j6 ?% J' y
show count patches
J$ i& \& R% z; n$ c3 B( H show mylist1
# }- y9 n/ d! U! i( D show mylist3
4 U+ p( m& z- ~% f- D. oend! W" f( O% O# n k% V- @
7 w' g) o& x2 K' z这时的mylist1 和mylist3 应该是一样的 |
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