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发表于 2010-5-11 13:19:52
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用list吧- g5 O9 P" ~1 ^# d/ ~
patches-own [wealth rank]
& i: Q! @5 u- I! U6 R& I) ^to setup
# x/ \5 W6 `* ]- a' h- M0 s) e' A ca4 f, P: v. y B( C6 s- ]9 `# V
ask patches [set wealth random 100 set pcolor green ]
% l3 \5 M8 Y+ |8 t. iend
* k4 c% I$ d# K" c, N0 L; j i1 P0 K d7 w8 Z$ O6 g3 t ~' J. g* z3 T
to go
: q. S# Q; D( w% B& g* i" ` let mylist1 []$ o' X6 @3 s; J1 b( a3 A
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
2 E- }5 }$ R/ \" A) b( }1 V1 I' | let mylist2 [] w* f* X! \" L; O8 o/ g' |# @; ]
set mylist2 n-values count patches [? + 1]
- z' A7 i0 m# g6 u
, @1 A( ]6 Z: }; Q; s3 z ( foreach mylist1 mylist23 d$ `8 }) t @ ]6 r3 P/ f1 c
[
$ @# X; Y1 U7 y6 d8 w ask ?1[ set rank ?2]
0 _8 X: j' x: h W0 c V I. G show [rank] of ?1
+ ?- i. r5 v( Q( C+ r % d* C0 h. W2 Z$ \/ @4 [ G) N
]
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let mylist3 []3 P" i. q) T4 ~6 k. |
! b' o; \7 A4 |1 ? set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches+ z; t2 x* Y1 x& v
show count patches2 B: o5 [ H& y3 l( t- m: W& E* T
show mylist1 % L- Y: a) s {8 t7 m i3 Z
show mylist3
0 n! H1 f: y- G9 {) T" {: ~end& C$ s1 L' \* G# ~* J5 n7 Z- v
+ ^5 `9 c/ I& l7 v$ b; P2 H
这时的mylist1 和mylist3 应该是一样的 |
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