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发表于 2010-5-11 13:19:52
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用list吧 Z# R( @% Q5 X
patches-own [wealth rank]" n! k1 M- y* Q! v; I/ ], ~
to setup* ?" ?4 \: G! @+ ~! s
ca
- z. c% Z0 x9 _ ask patches [set wealth random 100 set pcolor green ]! e h. c+ D t4 ]1 J
end2 Y, f! n- t. n9 E0 [9 Z
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to go# ]6 h& t$ u. j! M
let mylist1 []5 @. @0 P+ F1 g0 ~! n1 W7 S
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
0 E: A" V/ M0 z3 v let mylist2 []* `+ I" a/ \5 ^. a3 Z; w2 H
set mylist2 n-values count patches [? + 1]
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8 [2 P# |& U1 r/ b% v3 Z. d ( foreach mylist1 mylist26 h* t" p" [' d" ]" o2 p0 B
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ask ?1[ set rank ?2]& T. \# i. I7 H
show [rank] of ?1
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# s6 Q0 n3 U- `8 ^/ b' I let mylist3 []
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches2 i" V* u C$ H4 q, F& H( d- M
show count patches; M; Q# ]. ^6 h; t! n8 a2 V4 t0 M4 ]
show mylist1
' t( H& h6 d- ? b show mylist3
9 o5 W! h. _4 O. oend
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这时的mylist1 和mylist3 应该是一样的 |
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