编程遇到困难 请帮助

ding1617

to meet-wolf;; wolf procedure
  if count wolves-here >  0           
1 s6 M$ u0 V  w6 ^7 u' F% B  [let otherwolf one-of other wolves-here                     
    if abs ([k1] of self - [k1] of otherwolf ) > value-k1
  ?' r; l3 b  D3 E3 ~# ]- _   ]
   [ set  [k1] of self [k1] of self + [k1] of otherwolf
   ]
8 @6 k, b, P; h     end
显示otherwolf没有被定义，请各路大神帮忙调整通顺

SsendasX

应该是other wolf，，，吧