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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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M( t1 i; z" E% s' {% K$ f不好意思,打错了个字母,呵呵呵!4 j0 ?! m# F, D# x1 u- h
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
2 V: h) C3 ~3 l6 ~) x& [“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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j,k,nstep,c, scheduleteps,mincomptime:integer;: C% B8 q' o+ i
M:string;' R" {) C' N4 t1 c2 o. a
selecTab:table[integer,integer,integer,string];
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initorders;
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scheduledorders.delete;
, J c( v* ~. L- K( K& ~# }4 e seletTab.create;3 T7 C6 f, A. {
~0 P1 }. Z. ^ U: R |; f4 l orders.initialize({2,1}..{2,*},0);
' n7 P$ G6 O n9 P, Q orders.initialize({4,1}..{4,*},0);6 Z5 C) M) @1 A, `
for j:=1 to numorders loop
5 l7 U, w2 \, r- |4 k orders[5,j]:=orders[1,j][2,1];3 A- }; ~9 r& w/ D4 M6 E% B
next;
2 |9 h% h' l, S/ r1 i% @ occres.initialize({1,1}..{1,*},0);
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- R8 J% V$ `$ W4 l0 h( w7 a1 q --XUNHUAN
5 r2 J& {# M3 [/ P9 E; r8 } for scheduledsteps:=1 to numsteps loop --( S9 p/ `$ N7 ~7 L' F+ \8 U( }6 E# x
selectab.delete;$ V' Z, G5 ~$ G8 k* h: L6 |7 p
k:=1;# k$ o7 X) W5 G1 z* E
for j:=1 to numorders loop- J; S @1 G( p$ e ?$ X) Y
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nstep:=orders[2,j]+1;5 e* L9 R( m) e5 \. } V/ k9 `
if nstep<=orders[3,j] then
% L5 ~2 z: T; [2 y* b1 h1 x selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];% O) _1 Y. O7 Z7 L7 t
k:=k+1;9 ^( l0 a8 [3 j m) B" e
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end;
9 W1 k; U# ?# Q) n; D next;
- p" S$ G7 `3 x8 I9 F mincomptime:=selecttab.min({3,1}..{3,*});
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from j:=1 until j>selectab.ydim loop6 X8 j& O# |) w
* I4 C9 @; i) Z, t! R/ C5 n8 D if selectab[2,j]<mincomptime then* ?7 C9 j: R/ [% ]0 X) L
j:=j+1;; d8 l$ v5 r* D
else+ g; w4 U- z5 B: k
selecttab.cutrow(j);* j* P$ ^4 E/ A% Z/ o
end;
6 J6 b2 h7 n6 `- [) y end;; {/ L4 `$ a, n1 y$ }) n
4 Z2 e, [/ u/ x2 Z } j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;
2 N3 _5 E+ w# ~" \( f- z1 _0 P1 f orders[2,j]:=nstep;& I$ e( I6 J' }" n
m:=orders[1,j][1,nstep];
8 u% x% R& X _: C4 I c:=orders[5,j]" D( c! n5 K* T) H4 m0 t) r
occres[1,m]:=c;/ `; w, r4 C* B2 p) o( z: R
x4 C- n9 i. O9 f1 N8 d
--jieguo:start,end,res,job,step
% z* n% N8 E; L& P& m( T scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
+ R+ {1 M3 J4 \ for k:=1 to numorders loop
* f0 V8 S) c: p1 C9 } nstep:=orders[2,k]+1;5 N% `& o' J/ Y U
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
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then
$ K' ?4 O) ~( J7 j' W* k orders[4,k]:=max(c,orders[4,k]);
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orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
. U* W a+ D$ N, R9 o# x2 x3 Y --
. a3 Q4 G7 b; G& J/ Z end;
9 f0 @+ I1 r9 k0 c next;% Y8 w `+ O- y5 N
nstep:=orders[2,j]+1:
R6 O9 I1 ^& i( | if nstep<=orders[3,j]) K6 I, x8 @: [- a# ]
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then# g- H1 m f' Y' J" ?# ?& \
orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);: D# x6 t+ S1 `; B' O8 Z
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
' W/ a5 N0 d' e0 R6 a( o% I end;$ ?, j$ d3 L* |. t5 C
next;* Z$ X* z7 a9 m4 _
) e' V- u' G+ |6 C print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});9 ^! N/ F- |7 X! d3 g% j
mygantt;- r8 G) }3 A$ e7 R. N
ens;" x+ [4 s# ~+ W) o
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