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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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不好意思,打错了个字母,呵呵呵!
1 A6 g$ |0 M, r! ]: M大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
, c4 I l8 I; t( `“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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j,k,nstep,c, scheduleteps,mincomptime:integer;
4 z/ y- A) o( ~) J! F3 F M:string;
$ w) p5 D2 e8 M9 h selecTab:table[integer,integer,integer,string];0 j/ ^3 K: |/ R# r. e( z
do
& {8 C" y; M ]0 f% p initorders;) o' c# K2 g" b! ^3 B6 i" W: P. l1 z
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scheduledorders.delete;
/ T, l: g8 |, E0 s* W seletTab.create;
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" T W9 e2 {' s n' K orders.initialize({2,1}..{2,*},0);$ x3 p4 i. j+ u
orders.initialize({4,1}..{4,*},0);
1 P6 ]0 n7 @& V' n for j:=1 to numorders loop! w" w1 \' @ N8 s; U( M) K
orders[5,j]:=orders[1,j][2,1];
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occres.initialize({1,1}..{1,*},0);( N/ M8 j; l0 N! H! r
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--XUNHUAN
8 Z% @* Z) ~+ p @ for scheduledsteps:=1 to numsteps loop --
; l; _/ t3 P- k& U selectab.delete;
# T1 e5 i/ y, O k:=1;) T/ c" I$ p2 D- J$ v
for j:=1 to numorders loop" w) G; v3 e1 k, Z/ z3 V" v; @. H
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nstep:=orders[2,j]+1;
' U1 o( y( v3 L. c( q3 g if nstep<=orders[3,j] then
- v, d' G" y( j selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
9 ^$ U4 ~* `9 R n) R% r# U k:=k+1;
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end;
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mincomptime:=selecttab.min({3,1}..{3,*});
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from j:=1 until j>selectab.ydim loop
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if selectab[2,j]<mincomptime then/ y: j. L. P4 I. I. j a
j:=j+1;* ? U% Z6 O g" L- ^
else: ^1 c3 x4 [& A$ h
selecttab.cutrow(j);
( l" l, J9 @ y: _0 Q end;
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- r% ?) T$ i a- t6 ^# {0 ~ j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;
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m:=orders[1,j][1,nstep];/ W9 P. Z. _/ ~! R. P4 b8 y
c:=orders[5,j]
- {3 r/ f; u% Z9 t) c6 X5 D occres[1,m]:=c;, I6 w/ |- I9 [0 I. }- T
* X& `4 Q" Z# o7 m --jieguo:start,end,res,job,step
+ F- x/ _* H1 A/ G scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
/ P# e( y* [, N/ i* d# a for k:=1 to numorders loop
* P) U, ~& g+ D _ nstep:=orders[2,k]+1;% `6 o1 @6 [% F3 B7 n, B0 `8 d% @
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
5 J- G, N+ S6 s, L# m --
8 P2 r5 {8 t; c! o then
" ~! p0 c1 A4 n, g2 W8 S( m orders[4,k]:=max(c,orders[4,k]);) q5 l5 ~1 H% t3 c4 C; k- S) A
--
+ n; d) M6 F1 d& v orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];6 `- U4 w& A$ J( t) s+ w9 o
--4 R( {' q+ _5 i R
end;. I1 F; h( t6 V/ R8 P5 ]! @/ z( k
next;, c6 B; N! z9 F% D) G6 Y/ L+ c
nstep:=orders[2,j]+1:9 @- j4 c" \; V- x
if nstep<=orders[3,j]
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orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
. p; x+ E4 \% {) [ orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
) k0 u' r" L" o: e4 v end;
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" k" v4 k! y" h) \ print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
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