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本帖最后由 soso001 于 2014-12-17 14:53 编辑 9 v4 T' z: N) [( B: o4 ?$ ?; R0 {
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不好意思,打错了个字母,呵呵呵!' v1 y8 d( n |; `
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示6 t, k$ {: L9 ^8 B3 Z
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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j,k,nstep,c, scheduleteps,mincomptime:integer;
; B# ^, D5 ?: y: R M:string;
3 |2 a* x3 \2 c9 ^3 y selecTab:table[integer,integer,integer,string];
: e! s) N3 e& o6 ~do
6 z# `2 D& ]5 P initorders;
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scheduledorders.delete;, }% }2 R* f5 X0 P# r
seletTab.create;
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/ `- s% w! c9 d$ U0 j6 ` orders.initialize({2,1}..{2,*},0);
" G& ~ A- ~3 e9 p% L orders.initialize({4,1}..{4,*},0);
2 D5 \ C+ C3 U7 h' W! i/ C for j:=1 to numorders loop
% i: K6 q- o$ M& O orders[5,j]:=orders[1,j][2,1];: }' Y' e: e& N( A. L: B) {. }) A
next;/ l" Y: e$ l3 [" w4 ~6 B8 Z- R
occres.initialize({1,1}..{1,*},0);0 G4 Q6 h: ?' J
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--XUNHUAN
9 s$ \. c2 m% p+ H for scheduledsteps:=1 to numsteps loop --5 s6 N, ^7 q1 X6 X: |# \1 O
selectab.delete;
7 h: u ^3 f5 G# {* n" b k:=1;
; D; D$ R8 x* A for j:=1 to numorders loop& H/ O. x C' a' ^5 W
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nstep:=orders[2,j]+1;. [# A8 H; Q: n4 q, x
if nstep<=orders[3,j] then- C! |+ q' `8 C1 y7 S# R( a2 M
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
0 L4 v8 q/ Q, x( ~* ]0 v2 _ k:=k+1;7 \+ R; a) M2 L F
% l9 b9 P* [' g9 B end;/ ?. I5 ]7 D; p5 ~
next;+ T, \, C3 g' N5 S2 K/ G
mincomptime:=selecttab.min({3,1}..{3,*});* |4 a, o- n/ Z- `
2 j( S i. K/ C from j:=1 until j>selectab.ydim loop
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if selectab[2,j]<mincomptime then
3 m& Q9 N. |" n, x& x$ x5 X3 J. T j:=j+1;% @6 ^. H- {- ~" K! y
else# a9 \: C4 D9 E. M
selecttab.cutrow(j);
: [. M5 I( Y% t3 o& [ end;
/ _( x+ R7 a& H; `8 l( C' Y" `7 o end;0 E; ^) t6 P, i7 v
7 ~ V. H" ?4 q j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;
1 g8 j0 j4 |3 C- `+ w M1 J orders[2,j]:=nstep;
" @& y/ ^0 r2 W4 p: |9 s4 S6 x A" Z m:=orders[1,j][1,nstep];; F% q8 h8 {) G0 i2 n1 Q& x
c:=orders[5,j]' J6 J ]3 J: F& l9 ~1 j+ J3 J
occres[1,m]:=c;
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/ K* k) V! ~2 J$ Z- j --jieguo:start,end,res,job,step! D6 h/ Z. G7 m: e9 N
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);4 e& } U. V, T, h! z y3 p
for k:=1 to numorders loop7 F2 k7 }9 ^) K& V% c
nstep:=orders[2,k]+1;# G8 ~- z: I% T; C+ ]4 [3 N
# ^: U! q/ _* W" u2 A- f) Y- K F6 E( g if nstep<=orders[3,k] and orders[1,k][1,nstep]=m& Y% T6 Z0 m0 H# v/ _6 h- o N
--& K& k) j/ n( {1 {. k. L
then; |/ X o( i7 E5 f
orders[4,k]:=max(c,orders[4,k]);/ E8 N: T8 c; c6 ^
--6 _- _: N. y! J6 b4 g
orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
8 t; S# z# }' p --
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next; c$ h% h, b$ L8 Q# j& _. O
nstep:=orders[2,j]+1:% P+ ~3 h9 V% L0 d/ ^
if nstep<=orders[3,j]
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then
7 h% j$ p" R# z1 e orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
8 y! }8 k+ n! G1 F5 x4 y$ l orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
& \( {. s( r" a8 W end;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
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ens;; O- p% u6 d. G) ^
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