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本帖最后由 soso001 于 2014-12-17 14:53 编辑 8 Z5 _3 \# k$ |
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不好意思,打错了个字母,呵呵呵!! S8 M9 K$ h! s
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
7 }& B8 v5 E9 [1 _2 O$ o7 V; ^* \2 c“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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0 {# {' w( W& q! [ j,k,nstep,c, scheduleteps,mincomptime:integer;# a8 s1 V# N1 v
M:string;
* t4 e& G/ X4 A# L5 A4 y selecTab:table[integer,integer,integer,string];
# k( a0 I& @5 V- I) O2 }do
2 ?; i2 G5 Q! x' } @ initorders;
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scheduledorders.delete;
$ z) B9 N; J# @' H7 C seletTab.create;
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' ?# L T3 Z( }8 u# ~ ` orders.initialize({2,1}..{2,*},0);
/ w2 v. b0 q0 J# D" {# V orders.initialize({4,1}..{4,*},0);
7 X2 h- x6 I% N: }) \) O6 z6 ^; b for j:=1 to numorders loop6 S' V5 K$ w& r' A& I/ ]$ p# V& }5 \
orders[5,j]:=orders[1,j][2,1];
8 {! ^' |! `' E! M; w# m1 \ next;
& l' c) c, m1 m# ?$ N2 ~0 ] occres.initialize({1,1}..{1,*},0);% J0 ~3 a9 P: q5 ?: i8 k0 z, z3 @4 v4 @
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--XUNHUAN9 }, G" V; D0 B$ d2 }0 N* \ M2 o% O
for scheduledsteps:=1 to numsteps loop --
! R$ C( g+ P% @ \ selectab.delete;
5 u* R& W9 M/ B k:=1;
0 q2 Z6 B9 o: C2 u, ~ for j:=1 to numorders loop
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nstep:=orders[2,j]+1;
3 v; y C4 c+ {, _. c if nstep<=orders[3,j] then
7 f7 u: u% {3 K* r* l0 ^ selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
7 l+ Y, z+ n X k:=k+1;
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end;% d2 R' t3 }, c4 |7 c
next;: \1 y! O1 C9 w5 |! U
mincomptime:=selecttab.min({3,1}..{3,*});$ N- u& |7 M d( _% t/ U1 r; Q. c
' d' M. _9 p9 Y+ f, w from j:=1 until j>selectab.ydim loop
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if selectab[2,j]<mincomptime then. b2 y5 `0 d7 C1 `# T% G, d. N% T
j:=j+1;5 E2 o! V" [+ M) d: g
else
% @( X4 Z' m+ P" f' H0 l( ~, B* U selecttab.cutrow(j);
" S" V7 T3 i& \& a3 l end;
! c( J) @4 n% o) W1 w end;
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j:=selectionrule(selecttab);7 e8 P {. j3 V
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nstep;+orders[2.j]+1;
* R$ C: S8 t, z orders[2,j]:=nstep; f2 Y- K4 A3 I7 p; n
m:=orders[1,j][1,nstep];1 G9 N; U9 K4 v: |4 x8 B
c:=orders[5,j]
* v2 x' `5 B& l* }+ } occres[1,m]:=c;
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+ `% @% G( B3 d1 J6 r$ m' K* D --jieguo:start,end,res,job,step
, i7 N& }7 v) S0 |5 w scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
) P% J+ o, B. h6 b @/ I: @- d for k:=1 to numorders loop
* r0 Z0 S7 P! W nstep:=orders[2,k]+1;
, _1 j1 B: c k - ?0 _0 U- s3 q6 y$ }
if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
( M( \( L) B; N9 O/ j( \ --
$ w' m+ c6 ?! ^4 i% n5 ?: _1 n then
% R/ R+ x ^: |; B( c7 L+ S* R orders[4,k]:=max(c,orders[4,k]);' T4 }: @" e, C; F/ p* A
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orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];* q' w9 {5 d ?; ?6 h- i* Q% d
--& |; f) H) u8 I0 Q
end;
% }0 |- i0 q! a1 C next;
- B; \5 g+ N5 J" Q5 _! ^. |6 [ nstep:=orders[2,j]+1:
' M2 z& D# L( d( F: p( k4 \ if nstep<=orders[3,j]
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orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
# s) X) {. ?6 b3 j0 v! t orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
) u! m( \. Q1 }$ X# ~6 G end;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
$ P/ p8 u% n! W; M5 H mygantt;
7 [8 G! K7 `9 C6 [' v) v. c ens;
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