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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 0 C9 B! l* X( ]
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我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：3 r0 U5 a) L0 K$ L. ?2 ^% E
begin P_in arriving( b: `- r+ w6 B& }: a7 E! O
move into Q_in0 ? p; d$ F2 F4 |5 U; o9 L
use oper for 2 min
% _& M( P6 \: ^5 j: _! [, h \2 v( [ send to oneof(0.95:P_in1,0.05:die)
# [1 a) w8 ?0 F: r, k/ Mend5 g1 c+ E% x/ G% r0 P7 s4 _4 K7 H
begin P_in1 arriving
5 [- v) E+ @6 W* D8 H" w if load type = load1 then, Q: U r2 D6 H# d% K/ |5 H
begin8 E; ?+ Y, w! g
move into Q_m18 U: k; Y7 \7 R" N6 p& c
use M1 for u 5,1 min0 K3 f/ _8 @/ B
move into Q_out1+ O$ I0 T# g) z' E# X3 O
wait to be ordered on orderlist OL_1# r, }* L0 J7 U# s0 k( O
end8 P) u. k0 U2 L+ ]& ]
if load type = load2 then
6 P+ R( T- W" |! F3 c: G" ~6 \ A begin
& R2 |: B% @. B; Z7 X' q) V move into Q_m2
: r5 y' s2 v0 i5 X+ m use M2 for n 8,1 min
# X+ J% ~( M/ j2 b move into Q_out2
# C$ A5 `) L5 g wait to be ordered on orderlist OL_2; O# P5 k j' f- E0 ~. {
end
4 _: r5 F' j- n* A' b: N7 _end
0 ?& r$ C: d/ l4 _8 `$ Q/ qbegin P_dunmy arriving9 Q8 f) J8 e+ P1 M
set i = 1
6 ?- J3 ^' w# N, F4 D& P while i > 0 do
( s$ ], B' J6 f! z" Z0 A. t begin
2 Q! L" x) {5 U$ Q2 S9 U8 o order 1 loads from OL_1 to die0 b! \$ I0 ?& X7 _
in case order not filled backorder on OL_1
$ X4 E) d4 g0 E order 1 loads from OL_2 to continue% _6 K- R. [% M4 T$ h4 s; E- B
in case order not filled backorder on OL_2, ?9 E( M/ Z1 o% ]7 P+ M* S
move into Q_1$ j8 K2 J0 H1 N7 j/ d K2 l+ n
use Massm for n 5,1 min, \9 j! p5 R2 ?9 s- ?% \! ^* l
send to die
1 W5 }- ^) ?( e7 a, ~) {( U end5 T8 h3 U0 z! y7 P+ ?# p9 F
end0 z4 d' \5 `1 Y5 a2 u
这是我的报告
2 P v8 c2 o" I+ U4 l+ u* u*** AutoMod 11.1 ***/ p5 b2 q, S" f. p" ~
Model q$ A; B; s9 \; H2 Q: ]7 @2 k
Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00# E; F# ~, I- f+ l; L. A
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec
! I; M- r) A7 Q4 G: O7 uStatistics for Process System "q"
3 j" _9 Z/ F2 G+ b6 oProcess Statistics1 y/ x) P! N7 K
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait; A- m. L: X: P/ g m2 t; {2 g- b
========================================================================================
) A( D9 i0 D0 k7 s9 P: B3 Y) kP_in 222 1 0.32 -- 2 0 -- 126.04 --# z( I' W* G8 E; M
P_in1 212 210 102.38 -- 210 0 -- 41725.92 --- }, G6 N( _; O' q2 n
P_in3 0 0 0.00 -- 0 0 -- 0.00 --7 R' B- d8 a9 ~5 S8 Y
P_in4 0 0 0.00 -- 0 0 -- 0.00 --9 \& n! X% e; H' o3 b
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
5 f3 j9 X1 O z' p1 d8 I2 ^Process Traffic Limit Statistics: T# v$ b0 M; E' I
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait0 Z# `# _) _! E# Z8 d4 N
========================================================================================
. Y* v- N! `/ `, U, RP_in 222 1 0.32 Infinite 2 0 -- 126.04 --$ o" i( g* W7 x" \ c
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --
& ^% W) S# _0 i% EP_in3 0 0 0.00 Infinite 0 0 -- 0.00 --! E0 s2 M1 X- }$ v- ]( A
P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
# v/ v3 }5 X2 a# }8 k! E( \& U9 k' OP_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
: p8 n& j6 @1 U7 e# hQueue Statistics0 v7 {$ r7 n8 s2 C2 c
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
1 N9 ?4 j1 ?9 S/ n! ]; j========================================================================================* q+ z# F- B9 q
Space 223 0 0.00 Infinite 1 0 -- 0.00 --
4 n8 i* b% S/ J5 d1 b JQ_in 222 1 0.32 Infinite 2 0 -- 126.04 --
8 J( @( L+ G7 |0 J' Z' ]Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --( q. N7 W1 ~+ Z
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
, H2 \3 d1 `* YQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --' I: u5 {( u) D A
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --
. s( Z/ n; b) r* |' w. mQ_1 1 0 0.00 1 1 0 0.003 277.31 0.00
9 ]/ P( ~$ J4 y9 |8 _Order List Statistics* m. Y8 d8 ^# F
Name Total Cur Average Max Min Av_Time Tot_Back_Ordered( u; x) U8 o& s
================================================================================# Q! c r$ u5 ?: d
OL_1 139 139 67.23 139 0 41789.43 18 [. z3 ?: r- N) W
OL_2 71 71 34.26 71 0 41693.20 1
; W2 O# d2 Y" k/ P3 `. U. MResource Statistics
( e3 _7 t: h& {! |0 KName Total Cur Average Capacity Max Min Util Av_Time Av_Wait State + `$ L$ Z9 ~7 F( M( U; H
====================================================================================================
( w' I7 K1 j! e$ [: u% I! h9 dM1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ----
+ C2 W& o5 ?, h: T h, n0 GM2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- - J I; [( d2 d9 I& y& b
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ---- : {7 }- P% t, f5 s u
oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- . x" |9 f0 `! O
Random Number Streams: ^; t% t0 E! f: h8 s% k
Name Total 8 n: v, o8 r+ S$ i
============================0 ^- g) o7 v f& {2 B9 y
stream0 455, q( l( A( j _% r' Y
stream_M1_1 0; r$ p/ Y' b1 ?4 `( N
stream_M2_1 0
8 P4 Z5 ]5 R- f9 F+ ?7 n& Istream_Massm_1 0
" H0 B2 X' L3 |stream_oper_1 0& u- b- @/ L$ X, \/ Y
stream_load1_1 184
7 Q' G- W {( @: v/ A& gstream_load2_1 76
' }3 x0 K6 u1 I* ` H! _) Xstream_dummy_1 0/ g7 ]$ H% l" M X
) @5 C6 f/ @6 K请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
