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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 9 w3 ~- q8 N b+ k6 s" f
$ b; u" H) T x8 G5 J我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：
# b r; g: i9 [9 I7 a) g0 @3 D ]begin P_in arriving8 O' k( G/ b" ?0 p. B
move into Q_in
; E: l! |* B7 o0 j0 y use oper for 2 min
5 g, ^7 W* j7 d/ C4 p send to oneof(0.95:P_in1,0.05:die)
: }4 j# k q$ R; _+ _0 ?" f/ W5 hend1 [0 \9 v7 s) }6 z% e7 f! P
begin P_in1 arriving
! P0 u5 Z* X2 c6 R+ e$ N* ~2 ^' v if load type = load1 then
& z& _ a* ?2 } begin
$ W# ^4 o4 U A move into Q_m1( p! I B+ w) [' k+ g& D
use M1 for u 5,1 min5 K1 h, A" x2 V5 r" B6 z6 }
move into Q_out1
p' M0 H( f! V wait to be ordered on orderlist OL_1
% i5 z. I( E6 t end
/ ^7 n9 ]' x' T/ m' O% J$ E if load type = load2 then, b' L$ ~5 `: c+ R
begin
3 m. |7 f% A2 }0 D& A, J/ | move into Q_m2
7 E, ?% ^6 n' a/ _* }8 N use M2 for n 8,1 min
$ r9 k2 I( k- T* V6 ] move into Q_out2) E& \# X) x4 N4 C8 V
wait to be ordered on orderlist OL_2# Q0 F o5 [, Q
end% n6 ?" V4 M- X$ l: Z* j0 V9 G! C
end
; s+ a0 {1 V) R _begin P_dunmy arriving: ~' B2 i( Y; T" H5 g1 a' a$ l
set i = 10 c" H2 R3 J$ n% V
while i > 0 do
2 [6 ?# Q7 x7 ]3 E begin ( |5 R7 _+ {$ Y: j& B. Y& D- Q7 ^# f+ N
order 1 loads from OL_1 to die7 M. P* Z, R3 D8 S& M! R& J4 E
in case order not filled backorder on OL_1
# e7 Q. |' m3 I' N7 W" S0 P order 1 loads from OL_2 to continue
8 P4 w) I0 |3 [- l in case order not filled backorder on OL_2
& ?: T4 M/ G# m/ x move into Q_1
K, Q0 F \ D$ u use Massm for n 5,1 min
$ J8 `* c2 C2 |+ s, r0 x4 R0 A& h5 ` send to die
$ `. M' S- _+ R& O$ D) S! n: F end B1 M6 `, d/ j5 _
end9 F0 _& e" a3 [' I; F
这是我的报告
# t. m/ v9 ]4 n) t) `*** AutoMod 11.1 ***
; w7 @1 F2 e5 L+ p7 v& bModel q
l d3 c" X# W& C5 ]Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00# x* L4 A$ q2 {* G2 j B" D
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec* f2 b1 G9 ^ F8 u3 r7 `6 o
Statistics for Process System "q"
* d+ Y/ M, L4 o- v+ U- u, mProcess Statistics- a9 |, f# n- ]- E5 v
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
% j7 \- d% } U! c========================================================================================
, m/ {5 z7 O- eP_in 222 1 0.32 -- 2 0 -- 126.04 --
( k& ^$ W+ |( h# a5 sP_in1 212 210 102.38 -- 210 0 -- 41725.92 --
" h, b% e* E! y3 b4 ?+ T' ], X, bP_in3 0 0 0.00 -- 0 0 -- 0.00 --
8 ?0 i# J2 d$ n2 `4 E ~ RP_in4 0 0 0.00 -- 0 0 -- 0.00 --7 T8 I2 e. E& X9 {! V' p8 g: ]
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
! w# B( y9 M% W8 RProcess Traffic Limit Statistics
/ t, O3 o1 k4 Z6 k+ w; X# UName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
& X( a; s/ U. C! ~ _========================================================================================+ V, R n: P" K1 F8 s4 X2 u1 G
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --! h% }5 o) q1 C. F! P7 b
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --
+ u, P, I7 G' i5 l6 V/ O' SP_in3 0 0 0.00 Infinite 0 0 -- 0.00 --6 E2 N; U0 ^1 h, k2 f( o! m
P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --/ J. u+ Z2 k8 [# h1 U' c3 c; @
P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --1 e' M0 b$ z! [/ I9 M; B
Queue Statistics) \& t u# r" r. G( `) c
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
9 d5 P% p9 [3 `========================================================================================
: B& s% b& X( c- nSpace 223 0 0.00 Infinite 1 0 -- 0.00 --6 P6 V8 ]. I4 v. u4 \1 g
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --
' q( T+ r" n% ~( ]- T& S4 sQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --( s. z& {' \& N. y5 X
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --! x3 B# v! X/ [' m8 {
Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
' W. T/ K, e% A* |7 u2 wQ_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --
' \( }/ W1 ~9 H0 e1 L- iQ_1 1 0 0.00 1 1 0 0.003 277.31 0.00
1 a0 q& G2 s1 i7 a, a) Q3 S# c& kOrder List Statistics
1 B: [8 y; P5 Q# QName Total Cur Average Max Min Av_Time Tot_Back_Ordered8 Q" g+ V$ T8 I# N/ G% R+ A) Y
================================================================================# ~' n. L" S$ t! c
OL_1 139 139 67.23 139 0 41789.43 1% ?2 s( h0 r) [# I
OL_2 71 71 34.26 71 0 41693.20 10 D/ R: v: x5 G2 I
Resource Statistics
$ h4 a, U& _+ z$ _/ BName Total Cur Average Capacity Max Min Util Av_Time Av_Wait State ; G/ r! e/ }: y! c1 a. W7 P# A
====================================================================================================. w! r! y1 x; o% F8 x
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ----
2 i; i( a, ^) WM2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- 3 N) _6 U! w6 F v g
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
+ k+ j e2 |) Q* W& q* i9 Woper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
+ }1 Q4 W: {6 A, o4 ]4 ~Random Number Streams* W4 v4 `' ]5 m3 j
Name Total
* `/ r# I! E+ V6 X5 N* E& L. {============================
. a5 u4 L! n6 w- Z4 K) a2 f' e/ estream0 455
0 x' ~% S( D: I7 `4 J4 a$ Mstream_M1_1 0
" Y; v& w' v) v6 {- \- s1 estream_M2_1 0
, o9 k' T0 F/ W ]3 W, T$ [+ dstream_Massm_1 0
6 ?, n9 `# [- M' Zstream_oper_1 00 e6 d6 G% Q" {3 U
stream_load1_1 184
7 P) h: H# X7 s! F8 bstream_load2_1 76
1 i$ G# y* }& y) hstream_dummy_1 0 L" ] h0 r8 {3 p; h
, @% H4 i. C3 @1 T8 v \
请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
