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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 $ e+ Y$ a6 r- D
( q( u: v; F" r5 ]我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：
( A: Q/ L+ L" `# ?begin P_in arriving; g% j! I- i( P$ n: i8 F* Z
move into Q_in
, V7 p& ~0 z: g6 X/ z$ o) R. z9 W use oper for 2 min
& h% Y) ^8 V2 X# Z send to oneof(0.95:P_in1,0.05:die)
/ @6 ^/ T0 j3 v/ t. x. [9 _$ oend) N5 D' A) z, G' v
begin P_in1 arriving
) y3 u- E; d9 k9 W if load type = load1 then
, J- V- R7 V3 t3 _* t begin
' j) \& I4 u% k8 {& X9 ], n% e move into Q_m1, A$ t: _7 M' T2 J
use M1 for u 5,1 min, O$ G u7 b8 i" V8 b" y0 g& i+ r
move into Q_out1
& x8 o$ |4 [% D' v# C$ y0 ^: d& w, i wait to be ordered on orderlist OL_1
$ v9 W% B$ ^* \( q! Y5 [& C end
6 K& v& e/ F" T( J' s5 K( N6 r if load type = load2 then
+ M. e5 t) X7 u5 ` begin
2 Z) o o3 N. w8 Z move into Q_m2' u2 T/ w/ z: Q
use M2 for n 8,1 min
4 s0 V; m2 H+ R. z. k! o, ?0 a move into Q_out2
9 X; V3 q2 i0 D8 \' F$ ?* Y S2 J wait to be ordered on orderlist OL_2
/ V2 }$ M3 E7 T6 \ end3 t D7 n9 E- X* Z. j
end
1 P* Q% D, `7 k8 A# b; F$ Sbegin P_dunmy arriving T( V8 o( ?" j K9 ]
set i = 19 D4 z4 Y9 z& O# G
while i > 0 do' @3 V, i5 A- n
begin O' ?& D/ y! ^3 p- U
order 1 loads from OL_1 to die5 q, f" }1 a: \' [4 Q5 B
in case order not filled backorder on OL_1
7 C) Q+ G. I( ~) q$ T: | order 1 loads from OL_2 to continue
% c& F% D- ?6 X% G in case order not filled backorder on OL_2
, X. ?6 D6 y9 _+ B! n8 q move into Q_1
! e* p1 |% e) j: q! m7 Z ? use Massm for n 5,1 min
. q/ N: m% S. G' O3 s send to die
& D& V5 q% T; N* ?. q+ Y end
& m J n8 N) O e6 o2 Z$ Wend
4 c& c3 m& u" Q; W/ Y, B这是我的报告( l# r- ^ D. Q; @9 y
*** AutoMod 11.1 ***
' d0 [& j o+ K6 I" ~. SModel q& m/ g' U6 q$ ]4 P) B2 ^' A
Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00' r9 B# x1 N. I7 m
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec
. k* f6 n4 y: l7 SStatistics for Process System "q" {1 y- a2 U x. ]: Y
Process Statistics
7 h' L" U& V( ], M3 iName Total Cur Average Capacity Max Min Util Av_Time Av_Wait4 I8 ^$ R" B) r9 X
========================================================================================
* p& S! g4 Z% \5 Z8 AP_in 222 1 0.32 -- 2 0 -- 126.04 --
- n5 f8 C% b" I9 h! n+ n6 ]P_in1 212 210 102.38 -- 210 0 -- 41725.92 --
2 W, e% }& R0 P- j4 p: VP_in3 0 0 0.00 -- 0 0 -- 0.00 --' O& A Z( _7 k& [/ [
P_in4 0 0 0.00 -- 0 0 -- 0.00 -- {. ^7 }! E, v; V' i! d( f
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --0 l, E* J8 v# x$ a
Process Traffic Limit Statistics: I5 w8 n3 q T( ?$ }) L I
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
2 m# F! o7 J4 |2 z========================================================================================# d; j9 E3 \) p, Z5 k) ^
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --
& c0 p( D: H( A* C X! t$ R$ i0 AP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --. W2 j5 I6 n8 s! f/ [8 z
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
9 k* T: K: f. w7 D0 T8 TP_in4 0 0 0.00 Infinite 0 0 -- 0.00 --( _0 {6 k1 }0 ]6 \6 ]4 S
P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --* N- z- n" g5 [' V( _
Queue Statistics
( b* ^8 A4 E; ~2 {Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait; Y! \& a, m e& X. B0 x
========================================================================================) h: X7 B! D' V+ q
Space 223 0 0.00 Infinite 1 0 -- 0.00 --
4 H4 |+ ~8 O' ~$ A) T# `Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --0 i5 N* e& s2 d: B+ g" w
Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
/ c1 U0 I/ S7 u: WQ_m2 72 0 0.40 Infinite 2 0 -- 485.61 --+ D0 L- M- z5 \4 V; e
Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --- D6 d) ~/ b1 ~# }
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --
1 O% d& D P1 X4 ?5 BQ_1 1 0 0.00 1 1 0 0.003 277.31 0.001 l& V. j: [- C9 p( u
Order List Statistics: T; H& Q) v. p$ ^' @) m" i
Name Total Cur Average Max Min Av_Time Tot_Back_Ordered
# c5 G1 ^* J$ _================================================================================
' S2 r0 x5 Y$ e! h7 M4 v. QOL_1 139 139 67.23 139 0 41789.43 1
+ K9 M6 z9 f; G; sOL_2 71 71 34.26 71 0 41693.20 13 b- Y7 ~6 w. D8 j/ Z
Resource Statistics
! n9 z5 `$ A# s$ q; TName Total Cur Average Capacity Max Min Util Av_Time Av_Wait State $ @, _9 q! }' ], Z+ Z
====================================================================================================8 m9 c* K! U* G1 c2 \
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ----
$ o; G, U: D" L4 i& n! ]- s+ n" Q2 a8 vM2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- + v/ T* a9 ?+ u# g9 B
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ---- * e# r$ P* L1 o1 }+ F! K
oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- 6 D* e7 k+ g* U/ a- v c! m% P
Random Number Streams
( X* G" ]4 B% k2 [Name Total : B/ }" Y7 ~7 H; {9 S* t( ?
============================& |. W' T5 i; E9 j; N r
stream0 455/ m9 S1 p& A I A3 C' G
stream_M1_1 04 x' _# c# O3 W2 J, }5 a, c
stream_M2_1 0
7 J. e3 |* V7 H% p& ?$ cstream_Massm_1 0
4 a4 r( m- b" w: V0 Z1 ^stream_oper_1 0
7 _6 x) u1 y! E) I" z3 q2 }stream_load1_1 184/ y ^" k3 A, {# d; Z
stream_load2_1 76( T; N9 [: G7 N5 q4 ?$ c
stream_dummy_1 0
+ A6 V& L/ Z- w, w4 T
, l9 o$ Y$ r7 e) j' b7 D; k( E请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
