本帖最后由 GJM 于 2009-12-5 21:43 编辑 ; e$ i, z0 Z- z4 S+ w
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底下是小弟做AutoMOD里面PDF练习的(Exercise 5.9)逻辑文件但问题是,程序只Run到Machine A和Machine B就没继续下去3 M5 ?* f% F# C/ f; r( J2 I* n
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不知道是哪里出错,另外这题和Exercise7.1的题型类似,请问若要符合Exercise7.1的题意又该如何修改呢?请各位先进指导,谢谢!- y( q" B$ D( A7 x7 w$ \0 a
4 t7 m6 v& Q+ l--------------------------------------------
( z- D9 }6 Z' ]! e |begin P_something arriving: p. X1 y+ [* u M9 E8 Z
move into Q_wait/ \0 j- i3 L) }
move into nextof(Q_mA,Q_mB,Q_mC) \' f _+ \! `4 F9 }: k
use nextof(R_mA,R_mB,R_mC) for normal 48, 5 min7 t) {7 T) M. O; B: `
send to nextof(P_mA_down,P_mB_down,P_mC_down,P_mA_clean,P_mB_clean,P_mC_clean)7 L6 e3 Z) w3 w
send to die: i6 {. O1 b. B9 u% ^2 c1 \
end
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& }+ @; Y' K. J# K! e2 \begin P_mA_down arriving& `, I- }6 i* A, ?7 q, I' ~8 O
while 1=1 do
% @5 d o" }$ z" X+ n begin; c4 _6 a& o1 T- ^* f x5 i! R& c* M
wait for e 110 min
$ i, _& D L9 a( s! h4 h take down R_mA3 S) u4 Q6 n2 u( U" V
wait for e 5 min
& S d- s" r% J2 B* r- E) l bring up R_mA& _- f) E2 ~/ O6 G2 |3 i, z8 {' `7 I
end# U- ?# U' A. f/ ?) s% P
end
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begin P_mB_down arriving, {5 \& G' W* R" q
while 1=1 do
( r8 M/ v5 t3 w0 p: r begin( h& p0 y8 c* Y' r8 G
wait for e 170 min
4 L, P+ j! o( F take down R_mB
0 x+ c2 E/ K/ m) I wait for e 10 min5 |' p" h, ^5 Y
bring up R_mB) e8 O" P w6 i4 G( w& w6 U' d
end' X: W& V* w8 q3 e5 E
end' u" g' T0 q1 J: G3 c$ S& [
7 {8 F9 f; }9 G& ~# @2 qbegin P_mC_down arriving& q/ M6 z2 y) \$ R7 y/ w
while 1=1 do
: s9 \1 C4 R" i! Y$ T begin( ` ^; |1 S/ g* J: m
wait for e 230 min7 o0 \' i9 B9 p u
take down R_mC
4 R5 { J7 I# l3 C/ F0 ^$ A7 Z wait for e 10 min1 k2 C8 z$ Y' f( M+ J' @) O2 l
bring up R_mC4 N7 C" r0 E0 m! F$ ]0 _2 t
end& d* f- u7 Q6 W5 o" m% G1 Z' q
end& f1 A& Z( g0 n
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begin P_mA_clean arriving
5 o4 S* _5 \/ x/ @$ _ while 1=1 do
8 k) V, U2 {* s6 N' b7 {5 C3 W begin4 ~; J6 s5 B% @; ]
wait for 90 min
1 o0 `& b3 d; W0 }( c5 A! r" E9 w9 N take down R_mA, t8 D! a6 |" K5 ^) L; {
wait for 5 min# A8 H* ]1 x3 n! l" y, ~2 Q
bring up R_mA. ~& G4 {' M3 k i2 V5 ~! |( T- R
end3 i4 S, r& B8 X$ Q9 O
end
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6 d1 y+ e9 q6 A; B( C Nbegin P_mB_clean arriving
/ _6 a2 X( h, }, C8 t$ _! K while 1=1 do$ ^' Q+ z0 a: b$ A, i) _5 L
begin
$ h# W' G! g+ V) t9 {0 k2 o wait for 90 min
3 D6 B: j+ Y" q/ w take down R_mB% W' X; U- ]) m$ f
wait for 5 min
2 X' G+ B, J3 h bring up R_mB# Y: W' d8 }( X8 ]' ]0 R" A
end+ p9 t3 s5 \9 U5 L6 E1 c5 w
end2 \( U4 ?3 q9 e) `5 j6 W
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begin P_mC_clean arriving
( j5 o8 s, t& M" c. @5 v while 1=1 do3 k1 o! }2 F) A7 a: J. d
begin
, F% a# ~) [7 I' ^1 R$ U# n- k- U wait for 90 min
, W8 V& @1 n4 b* g O9 R* q take down R_mC
; [% t8 |1 \4 {1 J wait for 10 min
! ^; H. K/ E% u/ f' I$ s) d bring up R_mC6 X& h5 C: `- s" f9 I1 L4 v
end! v( n9 o: h: o% v
end) z* g4 R2 m* e6 k
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5 P# [# o1 S" M1 g1 fExercise 5.94 B0 g" |5 h* ^9 Y7 _% I- a; F
2 r& n: |) E: B3 q
/ w1 P8 E" r4 W k% d0 _- r9 d) p& _Create a new model to simulate the following system:6 w" r$ e6 v4 J$ e7 s# n
Loads are created with an interarrival time that is exponentially
! E/ m, v' ~9 P# h+ v) J: _! R$ ~distributed with a mean of 20 minutes. Loads wait in an infinite-
# k* q4 W4 Y; ^capacity queue to be processed by one of three single-capacity, . ^) J" f7 f! i+ z3 i+ _) {2 _
arrayed machines. Each machine has its own single-capacity queue % S9 i9 Y! K! G' I; D: ]5 K5 U
where loads are processed. Waiting loads move into one of the three $ B& b3 [4 H+ Y% J' K3 ], D/ s+ R
queues in round-robin order. Each machine has a normally 8 p$ |; Y9 l+ h
distributed processing time with a mean of 48 minutes and a standard 9 f$ }6 _0 R. q* j
deviation of 5 minutes.
4 e$ R- K1 ?# ~7 TThe three machines were purchased at different times and have
) K* H" Q8 X0 Rdifferent failure rates. The failure and repair times are exponentially * O# c: H7 c9 K; s' l7 [/ D
distributed with means as shown in the following table:
# X; Q7 S5 Z; w( _& UNote The solution for this assignment is required to complete
$ ?1 K" \; C) ?9 C" Hexercise 7.1 (see “Exercise 7.1” on page263); be sure to save a copy of M; C2 K* x6 w4 P! a0 U# k
your model.
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MachineMean time to failMean time to repair
4 E$ M* [3 Y, b2 g' rA110 minutes 5 minutes
$ |2 c: A+ C8 ]) t& sB 170 minutes 10 minutes
8 s5 S. _- `5 s5 i. B8 ^" b0 FC230 minutes 10 minutes
) E7 s9 s9 d; ]( }. i$ f% Z: p
! r# A# \# {6 g0 JThe machines also must be cleaned according to the following
1 P( a- D0 L' ]* U$ Hschedule. All times are constant: . F9 y% G' S8 X; a4 ~3 h2 C
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MachineTime between cleanings Time to clean/ e3 F8 ^6 F7 o, I9 Q+ M
A90 minutes 5 minutes- l8 C3 A1 [+ G1 S& N3 C" p9 O- O# Z
B 90 minutes 5 minutes
1 s% _3 E8 M% K* a) aC90 minutes 10 minutes/ y- v7 k. }- g1 k5 m# F( `
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Place the graphics for the queues and the resources.
% o4 O2 ^- A4 W0 YRun the simulation for 100 days.
0 u1 p" _) x6 ^, GDefine all failure and cleaning times using logic (rather than resource
: E5 L) V* [' _5 X$ G1 U. Rcycles). Answer the following questions:3 |3 u, z8 c: f9 W# _& G8 z# O
a.What was the average number of loads in the waiting queue?
) p# F7 [% K+ i" @7 b) ]) Db.What were the current and average number of loads in Space?
" ` v& V" s; B0 i w5 y/ \) WHow do you explain these values? 3 b# ]- }2 q/ h( k& E) D
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