本帖最后由 GJM 于 2009-12-5 21:43 编辑 & W' }4 a" L# E9 H, T" l4 @5 L
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底下是小弟做AutoMOD里面PDF练习的(Exercise 5.9)逻辑文件但问题是,程序只Run到Machine A和Machine B就没继续下去$ m8 H! _$ E% |7 p3 U8 \
5 e5 |1 B' N0 d! U" K) M: X& Y* c+ H不知道是哪里出错,另外这题和Exercise7.1的题型类似,请问若要符合Exercise7.1的题意又该如何修改呢?请各位先进指导,谢谢!& F8 U; g( `# p# Y
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begin P_something arriving
1 a( M+ ^2 S5 O; p6 P+ | move into Q_wait
. B3 a! R9 w, X6 _5 B* A9 f. M* S move into nextof(Q_mA,Q_mB,Q_mC)3 \$ J8 ]" T, L* \* v
use nextof(R_mA,R_mB,R_mC) for normal 48, 5 min8 L/ |+ F. B( L# K
send to nextof(P_mA_down,P_mB_down,P_mC_down,P_mA_clean,P_mB_clean,P_mC_clean)
% Q# N+ P9 G K6 o k- a send to die) n# o3 n( E {/ O$ |& v, t$ p! q
end
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begin P_mA_down arriving5 O$ ^+ w. A; f8 x
while 1=1 do
' O' T4 p# p( P+ D1 F begin& ^( @; q! _) b: _* j
wait for e 110 min' ~' f( B( ?0 r, g7 B
take down R_mA- p8 e. |: s( j# j9 l3 `% }7 ?$ f
wait for e 5 min2 J, i" N; A/ ^9 z( a
bring up R_mA# |. z" q# A% m, Y2 E( n4 Q4 D8 F
end
+ g" I5 q8 e- A( U* }% P* Hend
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+ ]& V1 k& i% p9 a1 i. l5 Mbegin P_mB_down arriving3 H+ T# \$ E) i# i/ p9 J+ j8 e& N
while 1=1 do" Y8 P6 V7 ]" X- p2 c
begin
: R0 h; H# z F wait for e 170 min
# _1 P: |* V1 ?, U7 X0 | take down R_mB; g; }' @% D8 E' v D; q
wait for e 10 min
0 i- O/ j9 |; g+ r% X+ x bring up R_mB
+ ?2 y3 d3 ?8 [; l) X4 b end
6 `8 M% f1 @- L. g9 y- R. E5 Jend
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% r8 R% X) u6 N) vbegin P_mC_down arriving
, L) s& t; s' N% S# x while 1=1 do
3 T& w5 N D- }. H% Y4 `" m H begin( b; l: V9 b+ G, I8 ]8 F
wait for e 230 min# ~5 O( ?6 I# m+ \0 I3 D8 k
take down R_mC) h3 |' l( f0 i E
wait for e 10 min+ W0 H' q2 n# [1 ]5 T
bring up R_mC$ E9 f' o% d! I" ]( ?3 [- y5 R
end
?! ]! y- n0 U' b+ c+ hend. R% Y) G9 G/ |, s! C7 o
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begin P_mA_clean arriving5 }+ P1 G5 L+ W" X* Y: P
while 1=1 do
x* D/ Q6 B, |! B begin
% X& K. c9 V# O/ {# t0 d) h( J wait for 90 min; d2 ?8 G2 L7 z: a1 Y
take down R_mA
2 O7 b+ |1 l+ p2 w wait for 5 min
# z& t8 z( q5 ]6 j( M7 M bring up R_mA$ L2 x9 T2 M3 v6 s" Q
end
, j' c2 u2 }0 D! Pend/ j9 j0 o2 | D" R$ u9 s
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begin P_mB_clean arriving/ O: p/ t! g( B: e4 }. r, u$ f
while 1=1 do
' m# j- M7 O, y Q m! m+ d2 U begin
3 l% W+ _4 J! f1 L wait for 90 min
2 J8 Z! n/ k8 i6 t( ]/ W' ?; n2 O take down R_mB; ~6 |9 Y6 o% `6 K6 ?
wait for 5 min
# Y M9 }( }" g$ v/ h. N! y& U bring up R_mB" u+ f8 y* K& Z) J, x% E& g# T) @
end- Q% I* g/ B0 C
end
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; w1 ?3 o: S+ L/ X1 j# j% C' y1 m9 Gbegin P_mC_clean arriving w% r! J3 w$ p# y
while 1=1 do4 S% C) h* J5 j! ^+ q
begin9 M. y5 v$ h# ?. R) f4 d4 g
wait for 90 min( E& a; L+ [' F* I) z Y. f8 S
take down R_mC' M& D: z }& M0 m
wait for 10 min
% x9 x3 ~' B( \2 Q7 {! @ bring up R_mC( c% U! c, u z8 X k
end
, X- O9 E' @/ q& d, a: U- Q: P5 o* Gend
2 q1 ]. @; W: J2 I8 W; b5 I----------------------------------------
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' G* X* U/ z3 [2 f; ]% m# W$ HExercise 5.9; C3 X* k8 W6 G; X
4 d' S; u7 C* W1 k7 D C4 k% H
. o7 p( r6 ~- B6 S3 UCreate a new model to simulate the following system:% x' x0 F, W. b3 R; B* V- c
Loads are created with an interarrival time that is exponentially
( ^$ V7 e' A- Q: gdistributed with a mean of 20 minutes. Loads wait in an infinite-
8 e2 }& u& g5 W$ T3 \capacity queue to be processed by one of three single-capacity,
! o! E. Z2 B- O; ~arrayed machines. Each machine has its own single-capacity queue
: B8 ~, M. G7 F/ fwhere loads are processed. Waiting loads move into one of the three
, ? y! e2 I8 P) E% F9 h$ v1 dqueues in round-robin order. Each machine has a normally
3 a [+ P7 l. b( D+ }, ydistributed processing time with a mean of 48 minutes and a standard : z/ L9 ^# y. I2 Z6 E
deviation of 5 minutes.$ \4 J8 \8 C% R) ]% D$ a
The three machines were purchased at different times and have
! c( k4 s P2 J) _3 I, Ndifferent failure rates. The failure and repair times are exponentially / X! R! O4 u6 t( Q7 J) y
distributed with means as shown in the following table:
1 ^/ C, @& f) R1 ?1 C$ u& LNote The solution for this assignment is required to complete : n) [* W! _! H9 f
exercise 7.1 (see “Exercise 7.1” on page263); be sure to save a copy of 6 J- Z% m! {" y! j2 b/ _
your model.
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8 K- B; o$ U5 d. t% L; I; w2 K/ A! ZMachineMean time to failMean time to repair0 \% s Z9 Z, F
A110 minutes 5 minutes
$ b3 Q! H4 E, NB 170 minutes 10 minutes2 M8 Y2 S$ Q4 c# `$ Q) G+ x+ R+ h2 J
C230 minutes 10 minutes/ x9 P- y) w* o3 m7 u' X8 N+ ?
4 `% m2 M7 S! Q( k2 i: @& PThe machines also must be cleaned according to the following
9 ]+ J) [8 ?* t- X8 f5 ^( w$ U4 lschedule. All times are constant: " r; ?1 l% i" g1 c
: y5 o; R, ?+ ?2 b2 EMachineTime between cleanings Time to clean
" f0 ~) W" U$ W5 O- \( f4 A: _' fA90 minutes 5 minutes5 S x0 `6 T# u
B 90 minutes 5 minutes
7 @* [* [9 S9 c9 ~7 g# R7 F8 IC90 minutes 10 minutes
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Place the graphics for the queues and the resources. - l- i w" \4 N0 w3 W' Q; \( v
Run the simulation for 100 days.
8 t1 C5 ~7 ?# U% j9 d! p9 JDefine all failure and cleaning times using logic (rather than resource 3 b# b6 ~6 ^. I7 A, N% ~- n/ }: p" V. p
cycles). Answer the following questions:* k0 k4 t& D* n- r+ h% W0 A5 C: x# o
a.What was the average number of loads in the waiting queue?4 z) ]: _/ q% R; }: y
b.What were the current and average number of loads in Space? ) H8 g3 i! h# N o! w9 ^
How do you explain these values?
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