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楼主 |
发表于 2008-4-19 16:11:18
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好像可以了
to go
7 K% v: l" O0 S2 b set t t + 1
4 a% O" C9 q" [$ l4 z# G! F6 f grow+ G. \( _2 k; c& ]: ^1 v
update-list-of-m$ u# V" A) l- F1 _
do-plots
( S- L) ?0 G9 o3 h3 r% ?6 {# U2 Y tick
# ?0 _# W4 n# U0 v& z9 b3 L& ^) l ifelse t > 87 N/ c7 a. _$ i$ V. g# P+ ~/ U8 Z5 p, w
[if abs( mean (list (item 0 list-of-m) (item 1 list-of-m) (item 2 list-of-m)) - mean (list (item 3 list-of-m) (item 4 list-of-m) (item 5 list-of-m)))< 0.01 and. ^. U/ K2 f: l+ @5 b7 ?% P( f$ L
abs( mean (list (item 3 list-of-m) (item 4 list-of-m) (item 5 list-of-m)) - mean (list (item 6 list-of-m) (item 7 list-of-m) (item 8 list-of-m)))< 0.01 and- h/ n- W0 J2 R+ @
abs( mean (list (item 0 list-of-m) (item 1 list-of-m) (item 2 list-of-m)) - mean (list (item 6 list-of-m) (item 7 list-of-m) (item 8 list-of-m)))< 0.01 . Z2 S% j5 ^, z0 C$ z# n
[stop]]; h3 V" D* L& G1 r$ }5 ~& u8 z
[ ]
: o8 u* Z, ?3 U( V3 s8 _; I, zend
% O( q: P2 `, U" P/ {各位大虾帮忙看看,这样好像可以了。以前用while之所以不行,是不是因为如果报告为true,那么就会反复运行后面的命令导致死循环啊?
3 f1 z. r% i; R5 L( J, u9 K还有就是[ ]是不是意味着不执行任何操作,返回set t t + 1,然后再grow,再 update-list-of-m,再 do-plots,再 tick ..........这样一直按这种顺序循环直到停止。# d+ h( u/ E2 o* Z; G6 E
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[ 本帖最后由 wjcpcahu 于 2008-4-19 16:19 编辑 ] |
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