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楼主 |
发表于 2008-4-19 16:11:18
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好像可以了
to go
+ n' Z, N( o0 A. R set t t + 1+ T+ Y' l! l* ~0 @* `
grow
* c! V9 U0 H5 C f: p0 Q7 m5 e1 U update-list-of-m
/ z% ^9 r* p* t do-plots( T+ Z, G. q6 s
tick
" R2 a2 f* L/ ^+ a2 ? ifelse t > 8 D; y$ V$ h: P# o
[if abs( mean (list (item 0 list-of-m) (item 1 list-of-m) (item 2 list-of-m)) - mean (list (item 3 list-of-m) (item 4 list-of-m) (item 5 list-of-m)))< 0.01 and8 z3 r, d4 s3 S, R* I
abs( mean (list (item 3 list-of-m) (item 4 list-of-m) (item 5 list-of-m)) - mean (list (item 6 list-of-m) (item 7 list-of-m) (item 8 list-of-m)))< 0.01 and
; n% [8 D+ J) q abs( mean (list (item 0 list-of-m) (item 1 list-of-m) (item 2 list-of-m)) - mean (list (item 6 list-of-m) (item 7 list-of-m) (item 8 list-of-m)))< 0.01 5 m2 L' q: ^0 M5 f7 u3 w
[stop]]+ T& E+ C `3 K( h8 _# l" a
[ ]
: w y# \# N! ~ bend$ ?( d; N1 c8 {% c" j) ?
各位大虾帮忙看看,这样好像可以了。以前用while之所以不行,是不是因为如果报告为true,那么就会反复运行后面的命令导致死循环啊?
* G' j- ^6 C/ E) H还有就是[ ]是不是意味着不执行任何操作,返回set t t + 1,然后再grow,再 update-list-of-m,再 do-plots,再 tick ..........这样一直按这种顺序循环直到停止。3 q i& B% ]$ T7 \! N j, {
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[ 本帖最后由 wjcpcahu 于 2008-4-19 16:19 编辑 ] |
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