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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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不好意思,打错了个字母,呵呵呵!# \# \( ` v# T. Z* G
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示3 G3 O h- v! l9 L* f# J5 o
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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j,k,nstep,c, scheduleteps,mincomptime:integer;3 N9 d9 P) ^/ u4 }
M:string;% }6 l' Y; |0 F& t
selecTab:table[integer,integer,integer,string];6 a! h) y H" g2 }9 C+ P/ S
do
- F) X+ e, B% A initorders;3 v C6 b' i' I* O6 S
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scheduledorders.delete; S/ Q6 E% {; B9 _" `) F8 m7 r/ E
seletTab.create;
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orders.initialize({2,1}..{2,*},0);5 j% c; k/ ^! Q. n
orders.initialize({4,1}..{4,*},0);
) y2 y$ T; R% b0 z6 o4 [$ l for j:=1 to numorders loop3 Q7 i. w7 B7 M# y0 i1 |# b
orders[5,j]:=orders[1,j][2,1];
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occres.initialize({1,1}..{1,*},0);
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; A/ [ I% S P# a( s: n. A- B3 k9 Y --XUNHUAN
0 {# u/ ^, O7 d for scheduledsteps:=1 to numsteps loop --& s* d4 N" M& a9 H' U
selectab.delete;
5 B- j* X S* a8 P+ B& \5 U k:=1;2 _+ L' F, I0 }
for j:=1 to numorders loop
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0 l' z8 T1 z+ V! K nstep:=orders[2,j]+1;
0 r! K9 [& `- e9 p, u. \& a if nstep<=orders[3,j] then
p) u5 _$ O9 Z3 { selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];# {& Y. _! f6 _+ t
k:=k+1; h) z% ? h& ?8 S* Q$ F6 i
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end;! M, p' O d8 v0 [& U% K, f& w E
next;
6 l7 a3 i' {; S1 [8 G7 Y mincomptime:=selecttab.min({3,1}..{3,*});
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) v# \7 ]4 n& Y# S from j:=1 until j>selectab.ydim loop
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! d7 f0 S( o6 ^1 \* L! W# G; S- e if selectab[2,j]<mincomptime then& B$ L# d; v9 Z6 S# J% J
j:=j+1;4 l7 r S) B D2 M7 n" x
else
. }: R3 y% D4 a0 T! J! k selecttab.cutrow(j);
* h, w* W2 Z! F6 ^2 M; {& M. P end;
6 u# b# f' [* z end;
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j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;
& l$ q9 E( U5 R0 }, [# N& G orders[2,j]:=nstep;+ c5 z2 {. m" _4 k5 U
m:=orders[1,j][1,nstep];
* p- y9 v/ \6 Q b8 } c:=orders[5,j] z) M- L, @( v( e
occres[1,m]:=c;9 |( D" _, O ?6 Z) C7 K/ Z
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--jieguo:start,end,res,job,step$ J4 d, h8 G' I( a( [' ?
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);" h( S5 ^' G; A6 \/ @
for k:=1 to numorders loop0 A9 `2 n( g; |8 X$ Z5 f
nstep:=orders[2,k]+1;
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2 d2 x6 a# M w) g* A$ F! T1 A if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
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then
7 ?' }# |, n% X" Q orders[4,k]:=max(c,orders[4,k]);, g/ l7 H8 I0 I
--
2 l$ g! B5 h6 i& b, w% ^8 e orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];) q R7 E5 _4 V
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end;7 |( l7 _; _6 u) h; z! B, n1 @) X9 F8 R
next;
) O2 \- D# V% u: w5 p% I nstep:=orders[2,j]+1:7 q! P& a" @: G7 Z0 Z+ h* ^8 x/ x
if nstep<=orders[3,j]
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; s/ f1 f' A* H9 [9 `8 p) } then
" t8 H# g2 D$ Q$ C3 Z0 R orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
: m: B8 O0 [" G; t; q7 v: M orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
' Y k) w) X/ C0 A( s end;
. I. R/ g( {1 g& `# s' c next;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});& e) z/ b: |' R( q
mygantt;; o3 m0 `* W" i# f( c
ens;
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