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本帖最后由 soso001 于 2014-12-17 14:53 编辑 0 v* p8 Q1 l& @% y0 W5 p
' O6 @) g/ M, q0 @不好意思,打错了个字母,呵呵呵!: M) ~$ \% G3 I: @4 w& o: ~
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
! w& F8 i) d# [“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!, `9 L4 o6 k2 P5 L; B
is
% t. L \) j* T0 q" e5 A q j,k,nstep,c, scheduleteps,mincomptime:integer;
( F0 _4 A0 C. y: d3 ] M:string;
. J: }" i, S- ?8 @7 y9 F* w9 J8 E selecTab:table[integer,integer,integer,string];! |; Q* i& J3 ~4 m" m9 h. G
do
1 n& Y( x2 P2 W3 {0 _# f/ r initorders;9 x: A/ q/ S$ K6 p, n. V7 u/ l
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scheduledorders.delete;+ p9 X- l# L) G; T6 r
seletTab.create;* `; R, L, }: J1 C3 X H6 q
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orders.initialize({2,1}..{2,*},0);( A; j" K2 X# B. H, A( ?
orders.initialize({4,1}..{4,*},0);% k- Q! ]: ^& @( {$ M$ x$ t# q% [9 V
for j:=1 to numorders loop7 b4 j5 U( [) {- {2 ?) J
orders[5,j]:=orders[1,j][2,1];* Q! K* H9 k/ I, D! u# {: R* K7 y
next; C X; w4 I c( ?- |1 H
occres.initialize({1,1}..{1,*},0);
5 _2 T; A. Y: u/ W% w
3 W' {" W7 U' x. u3 T, X --XUNHUAN
+ B% i `3 p9 I2 W% I' `& Z. ] for scheduledsteps:=1 to numsteps loop --
5 R4 I. x/ E7 c& W# E selectab.delete;
1 M+ v) C; J4 b E7 Q5 A k:=1;
8 I0 K/ n- } k for j:=1 to numorders loop
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nstep:=orders[2,j]+1;
" [. u$ o1 V! | if nstep<=orders[3,j] then/ I8 ^. ?: B; l0 k/ l3 x( J: ?
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];$ C z, m P8 {1 Q# L$ E
k:=k+1;2 n& a/ @/ j9 o2 T
" ^1 n3 f4 K- B, W" o2 w end;
7 {9 E$ e' \7 z* {* q. D) D9 O9 Y next;1 k6 N; m3 s6 t. H. b: p" W
mincomptime:=selecttab.min({3,1}..{3,*});
% L/ V/ ~2 T/ k; |- H ?* L' F `7 e
from j:=1 until j>selectab.ydim loop# Q0 f6 @6 O3 y, M) X
( \1 B) `6 O3 y if selectab[2,j]<mincomptime then) o# S9 r+ S7 Z, o
j:=j+1;
/ n6 u" f# C7 d5 U else
4 ?) \( Y7 m; g' D- S' D, e selecttab.cutrow(j);
" {+ Q5 E" L0 R; R& Q end;6 s5 `+ s. ~) s0 M% T
end;
% t& H$ X* D* w( m' o
& |) i/ r( b3 S1 r j:=selectionrule(selecttab);
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5 z5 F, a0 L3 a a nstep;+orders[2.j]+1;
0 ]) T5 |; |5 @+ M, Q orders[2,j]:=nstep;% s8 B# G% ^2 K
m:=orders[1,j][1,nstep];
+ l0 h2 T( j) Q* v9 |* |( A5 { c:=orders[5,j]
" T) }1 U" v6 @. [6 z6 N( x8 Y occres[1,m]:=c;; N ]# o" i5 y: f! Q
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--jieguo:start,end,res,job,step
" y+ M. ~& W7 L- l! P/ q) X1 f0 p scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
& `5 Y! \5 }) z: W for k:=1 to numorders loop
% N5 \, ?4 o F8 l" M% C nstep:=orders[2,k]+1;6 ]$ G' L6 k- M3 Z* \0 _* O
' h( v8 R3 I# m8 L( t! _( f( v if nstep<=orders[3,k] and orders[1,k][1,nstep]=m8 M3 @* U+ S7 R6 o# A/ l' j3 D
--6 n8 S9 V! V, r7 W+ `9 [7 p3 Z
then& [& v$ |7 E( }4 |
orders[4,k]:=max(c,orders[4,k]);
9 O! W+ o0 Z" C, h# `4 D --
: [+ t- l* Z1 b# G) z8 u! h orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];" O5 c8 G* u# U1 [- R: i
--$ p$ {: _7 I, W E& U8 l: e9 f9 u$ b
end;$ }1 b0 |4 |) z$ W* @+ X
next;, y' l! E* b" |# _
nstep:=orders[2,j]+1:* j; i! Y9 q# o: i4 M- M; p
if nstep<=orders[3,j]0 Z. H1 i! {$ l
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then
1 D7 d5 _' l% F orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
% q6 E3 S. p6 C orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
. j+ r' ^- ^( X+ x end;5 V2 n# i3 i( ~# j; T
next;
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7 o% W+ |5 }: L) {% C- C2 `7 ]% I print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
/ E: G& G( P7 m, N: d mygantt;
_% J7 }$ Z, \' |, _( f. j( w/ v ens;# I4 C$ M' P | j0 \# W
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