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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
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3 W; _0 V8 O* ?6 K; o我今天遇到一个问题,请问你知道如何把来自两种不同的load1和load2在一个机器上加工,合成一个load,该如何使用order命令?我每次运行的时候,给出的报告里面资源机器Massm没有load经过?以下是我的程序:- P$ ]$ S' ~0 Y$ O* H+ [
begin P_in arriving
* w# W7 A2 p( ^) [$ a6 M move into Q_in+ ~5 Z/ _" g8 S2 j
use oper for 2 min
# W. C) n6 X( T( Y& d0 N. y send to oneof(0.95:P_in1,0.05:die). R& `; H4 ? z/ }* ~4 l, z, T5 F0 a
end
$ T) _5 a/ d( pbegin P_in1 arriving c; F- m" z' i! U0 a
if load type = load1 then
8 H; y/ y) ~' c4 z begin
' ^$ [3 [" T1 V8 B( H' f0 z! b move into Q_m1
$ B! ]1 R' { P1 f7 q2 d# f use M1 for u 5,1 min5 g$ [* v4 x1 [% \2 B0 Q7 Q
move into Q_out17 w/ p3 H* H7 ?; J( D0 Z% g" l2 u
wait to be ordered on orderlist OL_1- ^ c: e3 V4 d5 e
end5 L6 @) |& v1 |- N3 S U+ E
if load type = load2 then
7 [) W. \9 e! Q: ~+ s9 T begin
7 h% p% _1 ?0 v& | move into Q_m2
- V& [# |* d3 l: P use M2 for n 8,1 min$ ?% r# O1 ]+ Z9 k. {
move into Q_out2
( w+ q* T0 i( V wait to be ordered on orderlist OL_2# [1 f+ p# D9 y Q3 |8 z W
end2 Z1 r4 U( c4 h/ X+ ?3 \: H. B7 D
end
8 V2 Y9 h }1 `6 `, K, ~begin P_dunmy arriving
% Q j. ^) u0 ^ set i = 1
0 v# V) L2 u5 e while i > 0 do
; N4 T% {4 P: Z7 B8 t, ]* @7 n begin ; B+ d- ~8 u; f; j1 P' Y
order 1 loads from OL_1 to die
% H6 R& F2 v) u: z: d+ ` in case order not filled backorder on OL_1
' J# ?: x0 O3 e/ T- F order 1 loads from OL_2 to continue' [* U4 v0 P6 P) y2 q& ^/ L/ e
in case order not filled backorder on OL_2# ^8 a. W! q9 h! D) f( s
move into Q_1
1 X) T* m* d, _5 ?+ [( L4 Z use Massm for n 5,1 min
$ U2 P5 [8 h/ Z! r% `% k send to die
% @6 l" A1 {' O' k" ~0 W end
1 w" C/ k" x) G1 ^# e6 \: qend0 M; X' D2 O k' K- j
这是我的报告7 g$ v* ?# J6 e, W4 F! L
*** AutoMod 11.1 ***
X* w4 b' E2 p/ v7 ^( FModel q4 {$ d" J X6 n3 P) S) J
Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00
" u/ k+ m+ K7 Y* d2 oCPU time: Absolute: 42.859 sec, Relative: 42.859 sec
7 B- _+ @( |; N% SStatistics for Process System "q"
; E9 I. s, }4 |* l; D" hProcess Statistics6 F P, Y$ U4 y4 i; ?
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
7 e. k; [ [; b" A- R========================================================================================
. y1 S& R s$ Z: gP_in 222 1 0.32 -- 2 0 -- 126.04 --
0 i2 v1 B9 z9 G+ D9 wP_in1 212 210 102.38 -- 210 0 -- 41725.92 --. ?! [0 c4 s; y7 S( R) Y$ z
P_in3 0 0 0.00 -- 0 0 -- 0.00 --( u u$ H: @- j' H f) y2 M: ]
P_in4 0 0 0.00 -- 0 0 -- 0.00 -- k9 T/ H3 v- |9 e& G7 Z! E, y) \4 R
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
( N( N6 n9 u# v/ Z, M, MProcess Traffic Limit Statistics2 L* _9 Y5 j4 ~; m$ j i
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait4 j# _0 ~9 E: b1 x9 [) A* W, c
========================================================================================- R1 |+ p. b Y" b4 o+ |% x
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --- T+ E" s; Z u2 P5 E2 k
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --
( l) F R" Y9 D7 l. yP_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
% m! {7 W- ^9 g3 ]P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
( w! `2 k" [* ]: ~2 D7 \P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --' u/ v1 p7 ]5 v( O
Queue Statistics% {& s( D! Q/ G4 [
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait }, U- w1 t, v3 H$ q) w
========================================================================================
, ~: m8 K3 M" _ e) y+ eSpace 223 0 0.00 Infinite 1 0 -- 0.00 --" Q- `5 d( S: o8 G1 s
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --, k' x7 I4 U: a* u+ E+ k9 [
Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
1 E4 Y# h; K6 HQ_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
: v; a, _$ i7 h! n* L, zQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
$ N* G3 c9 c8 B nQ_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --- _" O$ j) \8 o. n7 `
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00+ o- g6 q9 U" @. Q' |7 ^
Order List Statistics
+ s0 ~2 R" m W) y% uName Total Cur Average Max Min Av_Time Tot_Back_Ordered
0 [+ d* K4 K$ Q! t; f================================================================================
- D5 r$ C. j' w2 BOL_1 139 139 67.23 139 0 41789.43 18 A. U7 p7 f9 U1 i
OL_2 71 71 34.26 71 0 41693.20 1% i" |% }3 k$ Q4 p
Resource Statistics! `6 D. f- w; H4 _+ g
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
% H3 u1 s2 L! w: q====================================================================================================9 P7 v) d; D7 i: j9 h5 k. p) k
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ----
2 v- o: f! l7 A0 Q3 tM2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- / g! N( q' ] I
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ---- $ M3 ]% h+ F/ n6 ^
oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- + E) U' v6 _8 D1 w6 _3 T3 ]
Random Number Streams* [. R0 |8 c( t1 e/ {" i7 k
Name Total 4 j: T4 V9 I- d. a8 v9 K
============================
- E' k& }* M" A- u4 Nstream0 455
% K9 S+ l& Y% V$ Estream_M1_1 04 }7 K: x! t% K0 s$ E
stream_M2_1 0
. u- U% J9 `1 l. r" n* Sstream_Massm_1 0( W4 t. i0 J: v3 k" ~
stream_oper_1 00 \2 L5 {5 b+ T1 x5 _/ {
stream_load1_1 184
: I9 W1 d3 @, D5 Pstream_load2_1 76
; F" E; d0 L% ]0 m2 D: R( |2 N/ Wstream_dummy_1 02 m. f2 U P3 n) C. Q6 `$ v
: H# Y7 V1 k/ r9 d4 c9 W6 |- |6 M% i
请问我的错误在那里?我用的版本是11.1的学生版 |
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