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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 3 N3 v. L$ A5 j* N. X* y
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我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：; e% Q n1 Z8 X( z8 d1 a1 A4 z+ a8 G
begin P_in arriving
7 W7 \' J8 w6 Y5 G5 }$ H3 j+ k move into Q_in+ l* Z0 |) k! H% k
use oper for 2 min: ^6 H8 h5 {3 W" u
send to oneof(0.95:P_in1,0.05:die)# D# h2 W9 [* ~% G$ w& j
end( s W$ m& k! \, e' B# w. s' B) k
begin P_in1 arriving& i. S' T1 B6 Q' o- ]3 E6 \
if load type = load1 then
s9 G. P, h# v+ K& F begin; F9 E2 k7 g* O$ o( j% b5 `) d0 H0 G
move into Q_m1
5 |# W& x* X1 e2 O% Z9 F' g2 Q use M1 for u 5,1 min+ |+ F% H" K7 V5 Q2 Z
move into Q_out1; }' F0 s4 k& h- ^0 Z
wait to be ordered on orderlist OL_1
6 u! D8 w4 i- W+ W end2 t3 ~# ?* t |8 r) ^5 c2 ~
if load type = load2 then
! o I/ O/ k4 w; y2 C5 M begin' R: Z0 J) t2 P; m+ a
move into Q_m2
6 g q+ ?$ V0 _; z7 C2 l use M2 for n 8,1 min8 [* L3 Y' ^; A
move into Q_out2
* y* s4 L/ O9 i wait to be ordered on orderlist OL_2. B5 k) m7 n. f% W
end
$ B. M' i3 A% ]end
! o0 \* d/ I9 [: ~begin P_dunmy arriving
" r' C2 M- v; X' y set i = 1
. J5 r9 B" T6 E6 w: ~( W while i > 0 do
3 N% X/ h9 k; h6 J3 @ begin 0 p, x" G( S. d4 U7 Z4 V8 X3 Z
order 1 loads from OL_1 to die* b4 M, [, d9 |) K: @3 h5 g
in case order not filled backorder on OL_1
. k4 b1 `# Y6 Q3 | order 1 loads from OL_2 to continue, v+ ]9 L: x& c6 f q
in case order not filled backorder on OL_2( W+ [; w+ |+ e
move into Q_11 p# }6 Z7 ^8 [" A. E) z
use Massm for n 5,1 min) v. w- x6 j5 B/ l
send to die
8 D& `; I" ~& g+ `" k end B% e, N. l. _8 A! U( j
end
" G5 ?$ _4 f; q4 l$ M* S: H这是我的报告8 U2 ~% m5 ?' e# n; }& M: F
*** AutoMod 11.1 ***
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Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00
9 m0 U, b3 W; }8 R, }8 iCPU time: Absolute: 42.859 sec, Relative: 42.859 sec
2 X( f8 l( D1 n$ tStatistics for Process System "q"
7 P8 H8 }0 Y; wProcess Statistics( X* M. n' t: q6 |# u% ~( X/ Y
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
( c( Y; N0 M8 }- V; j========================================================================================4 V- o! b( I- N& U6 V: n) |
P_in 222 1 0.32 -- 2 0 -- 126.04 --4 P. s4 W: H9 m; j
P_in1 212 210 102.38 -- 210 0 -- 41725.92 --
" C( i1 d# s( OP_in3 0 0 0.00 -- 0 0 -- 0.00 --7 e/ o# j8 F: O8 L' b5 _- @
P_in4 0 0 0.00 -- 0 0 -- 0.00 --
+ ]* E. {. C9 F3 x4 J0 R' yP_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
; g6 g( O" r9 t0 ?' }, CProcess Traffic Limit Statistics3 C6 _9 P/ Q( N8 e" |: j4 n+ X
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
' w3 `4 v" L; e========================================================================================# t, G% R0 G' N% J
P_in 222 1 0.32 Infinite 2 0 -- 126.04 -- u2 r9 D @6 @
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --
2 |- }( b+ i6 G1 r9 N" qP_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
8 Z- x* K& X/ A; L, b1 p) x3 I5 a. TP_in4 0 0 0.00 Infinite 0 0 -- 0.00 --5 g7 }$ \' ?! Z; @2 g
P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
) n* g( L3 O5 k$ lQueue Statistics
4 b7 K( n9 ~% c& C3 xName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
, S! ^$ p4 [, s- r========================================================================================
" ^+ G1 A( z3 ], w1 j* {Space 223 0 0.00 Infinite 1 0 -- 0.00 --
! A2 a! p2 R KQ_in 222 1 0.32 Infinite 2 0 -- 126.04 --
0 A2 }( x" u, q5 y9 tQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --! R$ W6 J" I% h9 M2 s) }" I
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
) s0 q4 @2 R, d1 r" A9 J. uQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --- @: ~& K0 o/ ?- u' |
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --3 V0 {2 q4 m2 m
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00+ Y/ Z" Z) d) S' u$ ] i j6 L
Order List Statistics
+ D4 q0 G, P4 J: k0 ^) j, \Name Total Cur Average Max Min Av_Time Tot_Back_Ordered
$ v* h; T. E+ ?" h5 O4 ^+ M================================================================================% a7 j3 Q% `( Z" X. W1 B: N2 u% n
OL_1 139 139 67.23 139 0 41789.43 1
& {- j1 l3 d6 l3 g" z" _7 C5 c9 E" WOL_2 71 71 34.26 71 0 41693.20 1
( [6 Y7 T% ~; _$ aResource Statistics' I# S6 A9 [& z! \" `5 B1 A3 |4 y) j
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
' h' B V! N0 k: _; U6 w====================================================================================================
) H4 ~! D; n* hM1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- 9 e, p1 R! _- v( F+ t& t5 f5 ~
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- 0 l m0 I/ t1 H3 j
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
, U2 b, j. I! C& h/ uoper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- . a( T- q {$ K" ~/ N
Random Number Streams; x) X& Q" Y ]- q
Name Total " M1 D: z9 ^( y
============================
) ]( x' O3 F/ s) dstream0 455
. R) Q& g0 V0 P0 U1 y5 dstream_M1_1 0
9 b# D/ o5 d# H# y3 p& }* Y0 C8 \- m1 Zstream_M2_1 0' J+ a J, I: q0 h9 p
stream_Massm_1 0* m: @$ b' s0 Z1 D$ o+ h$ N
stream_oper_1 0! M3 u" q5 `( H# s; b$ U8 G1 v$ ?
stream_load1_1 184
. j7 @1 n. }/ l5 [stream_load2_1 760 `5 t1 o6 Z% n, x/ y
stream_dummy_1 0 F' [2 G5 s' m% Y4 V1 F
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请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
