|
本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 : p9 w# ]" y9 A/ W
. a, f1 O4 G* q! U) {8 M
我今天遇到一个问题,请问你知道如何把来自两种不同的load1和load2在一个机器上加工,合成一个load,该如何使用order命令?我每次运行的时候,给出的报告里面资源机器Massm没有load经过?以下是我的程序:
/ K, W6 H1 d8 [3 x/ Q/ _begin P_in arriving3 E: H- J. O. W, T9 Q6 D; `7 w
move into Q_in
. K1 M! U5 |9 f9 D g use oper for 2 min! P/ L. F% d+ X" ~9 I
send to oneof(0.95:P_in1,0.05:die)3 V$ e/ h1 @3 F% T; T; m0 P) ~
end
8 u. [- Q0 Y+ y7 k( Rbegin P_in1 arriving
- z) U+ E1 {% B6 j& k if load type = load1 then% O, \) M- c4 A- d; i* W
begin
* s: G( j% y% E move into Q_m1. Y' S d+ C; u. _6 h
use M1 for u 5,1 min
; k# t3 d0 T' r( L( e- _ move into Q_out1. e/ \0 W1 V8 A+ U" D1 f
wait to be ordered on orderlist OL_12 [2 y/ [% `- O& N$ b* W
end
0 B) N# w" c3 c3 T9 g5 Y if load type = load2 then) l1 W/ Q. ` P. N# }8 k
begin
! E; G m" O$ i% G move into Q_m2
5 @( Q; W, k, r! { use M2 for n 8,1 min
( g( z0 b+ E; B" C+ h( m2 T6 u# Q move into Q_out21 m% |/ W5 }# t3 T
wait to be ordered on orderlist OL_2
( q9 s! o) Y8 E, N" z. W end6 k: t5 `* ^+ Y
end. O# }% x9 r4 t. \7 n* u, ~' g
begin P_dunmy arriving
. ~) _4 y+ I% B$ C- C set i = 1) U( C* ?6 h+ y
while i > 0 do; k/ M: \# M& `: e% a3 m
begin
& [4 x5 X: S! U9 ^ order 1 loads from OL_1 to die" S* B! K; E2 z
in case order not filled backorder on OL_1
' ]1 V9 i( T+ `0 f6 Y6 U8 { order 1 loads from OL_2 to continue
' t* s" A( \3 O1 ~# s# ~ in case order not filled backorder on OL_2' I" @% Z& p# j/ P& l/ V& j8 _
move into Q_16 w4 v0 h4 t6 L
use Massm for n 5,1 min8 d5 T" k/ g% X
send to die* s% T* Z1 P# o1 t6 m3 Y7 b; G
end
. b0 |" N1 u% Q+ K+ h. Lend
# n# M/ ]0 R( K" S5 \这是我的报告6 l5 ^: ?7 e; F3 U( m: u: `1 H
*** AutoMod 11.1 ***
- Q; h9 `- `6 `Model q
) d' V3 J! G0 a, WStatistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00! T) i b6 r+ i1 n
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec) A+ R0 Z: J) _$ l8 Q# H' l4 ^
Statistics for Process System "q"
) r# E' I5 O. D& x" J$ e qProcess Statistics
" N% I7 a/ G' P' a. UName Total Cur Average Capacity Max Min Util Av_Time Av_Wait0 }( u: j7 _; N9 L4 ~9 ~
========================================================================================
6 F) i! D" K% w) B4 `4 j2 ^P_in 222 1 0.32 -- 2 0 -- 126.04 --
1 I6 y) a# P5 S5 L% m; NP_in1 212 210 102.38 -- 210 0 -- 41725.92 --5 Q1 z# g j9 g4 |8 R
P_in3 0 0 0.00 -- 0 0 -- 0.00 --
6 L; A% X: A1 o8 X6 {" sP_in4 0 0 0.00 -- 0 0 -- 0.00 --& R E* |% N6 A6 C2 a6 B9 A
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
! P5 K6 k& w4 b! V' L4 [* T' ?% @Process Traffic Limit Statistics8 e( \; Q8 G. p8 A
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
; D; v7 n7 V6 j========================================================================================) ?$ S* E/ ]( v
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --8 q7 u/ ]0 P- K1 j
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --
* n# ^$ ^8 } W/ _4 I/ hP_in3 0 0 0.00 Infinite 0 0 -- 0.00 --& v6 V" M, w! j2 r P- W
P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --9 {4 a @1 z9 X! H
P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --- t2 u9 b( U4 R1 _
Queue Statistics
0 T$ Z0 R3 ?) i( rName Total Cur Average Capacity Max Min Util Av_Time Av_Wait7 M/ Z3 H2 Y! H: ~
========================================================================================0 t8 p! @5 d: N" @+ R
Space 223 0 0.00 Infinite 1 0 -- 0.00 --
, z/ h& M! H" S- w7 IQ_in 222 1 0.32 Infinite 2 0 -- 126.04 --4 f1 @$ ^# a8 \/ I% u8 g6 X1 k3 t
Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
3 G4 b* X9 k8 a$ E, ~Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --# l0 ^5 V% ?2 C3 K
Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
0 T- K/ V3 s! tQ_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --& B/ f+ ~; ^8 b5 U4 Z
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00
. ~6 @; S* k9 vOrder List Statistics
& ]! M! {4 h- r2 X. o2 M: MName Total Cur Average Max Min Av_Time Tot_Back_Ordered
7 b. a. P# |' @" t4 q% w- w================================================================================
; L3 u" n: v* k8 s: t# ?OL_1 139 139 67.23 139 0 41789.43 14 b# m% Z% u: |: t8 ]
OL_2 71 71 34.26 71 0 41693.20 15 w* r4 y6 h* Y
Resource Statistics- ?& V4 i( e; t) B
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State 2 t- B5 P7 i W$ j$ }0 ]5 q9 e2 A
====================================================================================================- _# y" H" F* d y4 p
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- $ B- C& p5 \1 ]& r- K, a& I
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- ) \6 e) I9 R. l' b Q; @
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
( h, x0 I* N5 W% l6 _# Poper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
{7 s' u& J6 \* g$ X1 GRandom Number Streams
) H# ?( h; }4 ]Name Total , }) I- d7 M) _/ p# S
============================; }; Y5 e8 T9 S% q1 J
stream0 455
( P6 i, w. L. l, ~; ^% ostream_M1_1 0
3 S+ Y2 q# I$ C" D9 ~& cstream_M2_1 0! o* r- h; b& w
stream_Massm_1 0
! a1 f' p8 E% [, y; @+ e( wstream_oper_1 0
4 j1 E: f2 C$ Mstream_load1_1 184& W" a; U6 p z
stream_load2_1 76: r. l# K6 j% ^: c* F# V+ Y- N9 b1 ~
stream_dummy_1 0! [) _1 J! S Z: b# `9 V6 H
1 Y8 `. q8 b g
请问我的错误在那里?我用的版本是11.1的学生版 |
本帖子中包含更多资源
您需要 登录 才可以下载或查看,没有帐号?注册
x
|