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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 * Z7 I$ Q, E- i, F# H
8 R- o8 W. B* g @# J1 f我今天遇到一个问题,请问你知道如何把来自两种不同的load1和load2在一个机器上加工,合成一个load,该如何使用order命令?我每次运行的时候,给出的报告里面资源机器Massm没有load经过?以下是我的程序:
3 J- `3 @5 u# N9 h8 \7 [ }) Tbegin P_in arriving* a2 b4 K5 h# V* g
move into Q_in2 u5 x" \' s0 z/ N
use oper for 2 min0 F1 `1 {; S; h0 A4 E3 y
send to oneof(0.95:P_in1,0.05:die)6 ?; k/ N2 g1 _' M( g9 h' u
end$ d/ l4 y7 W, n% Z$ N
begin P_in1 arriving* S7 o9 S3 p" B1 J* l
if load type = load1 then J6 M+ d! a4 F1 D4 ^# E
begin
5 q$ j" A, ?" { move into Q_m1
& \+ o: h: k( s6 T! j8 u) a8 p use M1 for u 5,1 min
D1 X/ ^$ [+ y move into Q_out1
3 k; P0 y N; K( C wait to be ordered on orderlist OL_1
! U3 [2 L# Q/ j4 o" \3 u end
3 O3 b# J6 U5 }2 Z* |- I2 n5 t0 B if load type = load2 then1 G8 P8 G( B+ ]9 g( r( P
begin4 n9 {& }( I. n; l
move into Q_m2" x5 |! N/ M \0 O
use M2 for n 8,1 min
. A! j9 n- S9 I0 I: {- U k2 c, w( r+ D move into Q_out2& Y$ b2 J* Y! S5 H
wait to be ordered on orderlist OL_2& s* i* o% G+ w/ U
end
" Z) m: q1 X( L2 Qend
4 }4 n* H& B+ v9 a$ v- Gbegin P_dunmy arriving I7 b2 A8 x3 X p5 ?+ B) Q
set i = 1
) ^, p& R6 G9 ?% A while i > 0 do0 ?3 F$ ]! F$ A! C9 x$ w
begin 3 _0 p( Y- v7 u9 Y
order 1 loads from OL_1 to die# t, R$ \( H; o- T: R
in case order not filled backorder on OL_1: [* ^7 A! ~; N* j: w
order 1 loads from OL_2 to continue
) d# j- x7 L2 o6 l8 r in case order not filled backorder on OL_2
6 D% |5 [* |; H3 |! ^, z1 g2 L move into Q_19 ^ Z* j2 o4 t' x5 [$ G
use Massm for n 5,1 min
( B/ |4 b6 u# K- L0 _/ q) f: v send to die6 t. _$ ]( |* m. @1 X+ [
end
8 f! C" U0 b" w0 ^end
+ c2 j' ^6 n" ?& W这是我的报告( L( m2 c% ^' J1 b3 j) E
*** AutoMod 11.1 ***
7 w: }( O: @6 u6 k& KModel q
4 R- ?! W6 y: l( ~Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.002 d6 q& j8 F* B) r. E& N7 y
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec
1 `% B- R5 K# \ N1 S5 WStatistics for Process System "q"
0 k) k. F6 J& E0 H6 V2 ^Process Statistics/ u, t3 | @" o2 U8 ?" S' k1 k
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
* N, [0 {6 m! o- E========================================================================================1 I) `2 M* ~4 Q0 G/ m( b. v
P_in 222 1 0.32 -- 2 0 -- 126.04 --
; Y6 J0 i4 b4 `4 {3 Y( U4 ^P_in1 212 210 102.38 -- 210 0 -- 41725.92 --4 ^: @. E5 R- B( Q0 q6 }7 Y2 y
P_in3 0 0 0.00 -- 0 0 -- 0.00 --+ e+ C4 @! ]; C9 }
P_in4 0 0 0.00 -- 0 0 -- 0.00 --, C t! b& j& h' x6 r
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --4 u: N) h8 X2 x$ i5 t7 ]8 c( }& O
Process Traffic Limit Statistics
2 H5 K- |7 S6 z( @0 h5 ?Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait5 a$ o1 a6 J7 Y. y; X
========================================================================================7 \/ U5 }5 d j R; y8 G0 R1 A: d
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --
6 t5 u9 C' z5 u1 g5 SP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --
0 c2 a: o1 D" k4 |8 ZP_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
+ E# K4 T; Z2 c- g& ]' xP_in4 0 0 0.00 Infinite 0 0 -- 0.00 --- e4 R l8 q$ T9 o l2 E u, J6 S
P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
" r8 c& f6 h# U! Z) k9 ?4 iQueue Statistics2 @- D% }0 t9 l& M
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait' X, G" g! H& j: W( x
========================================================================================: d. [. | ^6 ~
Space 223 0 0.00 Infinite 1 0 -- 0.00 --& U/ \4 N' Y$ N/ I/ V G N
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --
6 Z- P# `$ v7 w8 Y" l bQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
4 V& ?) W4 Y% n2 AQ_m2 72 0 0.40 Infinite 2 0 -- 485.61 --& S" X" [" {. G: g1 K B# F: b
Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --/ f- Z5 Q1 Q7 x( D
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --! _" y8 z. T- W t& O/ k, C3 f4 Y- @
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00
W! z5 `9 b3 M5 q& kOrder List Statistics
: E1 ]+ R. V! fName Total Cur Average Max Min Av_Time Tot_Back_Ordered1 m# F' p+ x# P2 j8 ~7 V
================================================================================' T4 N/ }/ |5 t/ S% _! N; B+ k: ]% I
OL_1 139 139 67.23 139 0 41789.43 1
% C3 B* @5 s$ pOL_2 71 71 34.26 71 0 41693.20 13 s" q1 A/ H6 U8 ?# U
Resource Statistics( h6 F! E/ p/ M0 w" e4 s$ L
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
8 a' J) x# _! p; W" p0 G" J* n====================================================================================================1 M: R6 c+ h' r) Z7 n
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- * _1 b4 c2 h. A l5 Z8 l
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- ; \9 a; r4 i% ]# M) W
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
0 K- }7 g6 m5 P; B; _oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
7 P" ^$ R1 J1 b4 IRandom Number Streams) C' j0 L* J! X1 E0 E
Name Total
4 r# i) ?( p- M* }5 |" p============================/ R+ U. z5 y9 i4 g' ~ J% ?6 z
stream0 455
2 J7 W+ k* j: l6 }) k# Z( Pstream_M1_1 04 n) b- _- Y: t1 `; R: z" h
stream_M2_1 0
! E+ y# ^2 l& sstream_Massm_1 0
1 y' _5 F- b3 I7 }4 Astream_oper_1 0( p3 x1 q: r$ d" W v, w! T
stream_load1_1 184
6 i, y3 b& c' t- g% estream_load2_1 76' i! Y5 L: P+ P. w0 u% f& B
stream_dummy_1 0
6 a4 F u$ m7 [) M5 H. A/ O. s4 E+ r# Q( h Q. Q
请问我的错误在那里?我用的版本是11.1的学生版 |
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