本帖最后由 GJM 于 2009-12-5 21:43 编辑 . m% K: v% n& Q- q) I( ~' L
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底下是小弟做AutoMOD里面PDF练习的(Exercise 5.9)逻辑文件但问题是,程序只Run到Machine A和Machine B就没继续下去 v( U& X( a3 v0 u0 O1 K/ d. b# e
Y* w, s& W$ ~0 u/ R& n% b
不知道是哪里出错,另外这题和Exercise7.1的题型类似,请问若要符合Exercise7.1的题意又该如何修改呢?请各位先进指导,谢谢!
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, k) R0 n( j- L+ {begin P_something arriving* r9 c4 h$ p) ]8 E) Y7 ]
move into Q_wait
. p, L$ k* z7 O9 F# r5 T& B move into nextof(Q_mA,Q_mB,Q_mC)* P |: v% h5 n8 O- i1 t
use nextof(R_mA,R_mB,R_mC) for normal 48, 5 min* z. M+ G! Q) U( P9 {: ~- q. P
send to nextof(P_mA_down,P_mB_down,P_mC_down,P_mA_clean,P_mB_clean,P_mC_clean)
& O# n" X( w/ P( l9 M e send to die" Q2 A# `. R6 L) Y) ?
end" h+ }' J& h( A# @1 A; }
$ L( s/ {7 Z. I. b, J, Jbegin P_mA_down arriving
1 u- j' E# j5 T; x7 p5 r. e3 @ while 1=1 do ! B: `& @, W$ I e" s$ b
begin
# L, a H5 P3 }3 M3 m$ M6 |3 K/ D# h& F wait for e 110 min
8 g1 @5 Z- p9 J2 y. }* l7 a9 m4 ~ take down R_mA& a' F, f9 F4 t2 g/ v
wait for e 5 min
# j& a4 i3 ^4 J) M) b1 W0 g- N bring up R_mA: |; j# U8 ]8 h! o
end
3 Q& u1 H* U3 i$ f) s, @. Uend W- P% Q0 J8 ~* O# b# o" q, O2 C
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begin P_mB_down arriving6 X5 U9 {$ y. R5 V
while 1=1 do$ {& U& P; @$ z' }9 X& ^
begin
+ K) R! Y/ _5 B# {6 } wait for e 170 min
& Y, }& W$ ?1 T& M7 K take down R_mB ]# h( |! |4 q8 z g
wait for e 10 min- @! I7 m k# }6 h% z) ?
bring up R_mB" Q' j& G9 J" t3 j
end5 X) |& L! }# m% \' Q1 D+ j
end* n! q1 C! i' g) `
) r6 H0 m7 H4 Y4 E7 w2 B: ]) Z7 e. E7 hbegin P_mC_down arriving' M% f# r B* X/ [' _3 w! O
while 1=1 do
3 x: R4 ^& ~2 M" B4 l/ k begin
% Y' |0 B6 r8 v wait for e 230 min
3 z2 L" X: e$ |3 I* g( L! A' s; y take down R_mC
1 |: [! l9 f, _! O1 t wait for e 10 min
9 E2 x! V! l7 n bring up R_mC' r$ V! A4 V& \# f" o
end
: l3 v9 a# q7 [8 j2 \end
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begin P_mA_clean arriving
1 n8 @' L* l/ A' s) N; d while 1=1 do
0 B; z* {& r0 [# x. B7 ]2 W begin3 B. j) _/ ~ t& _4 @
wait for 90 min
% ^4 r- m8 u8 v; r. m R6 `( A take down R_mA. c) V6 s8 b7 K0 u5 @+ x! d% L; O
wait for 5 min
/ g( \1 g d9 | bring up R_mA8 X# d0 H+ N/ H7 M9 M
end
3 H$ _) Q) h$ @& L* _' eend% U3 p( ^( ?# V& _2 H8 w" C/ k
+ [8 `3 A4 b0 F% u' G2 l: B
begin P_mB_clean arriving
; @8 K* h7 d) c8 O4 }" ^& a, G while 1=1 do
3 g4 E( d- z" {8 r! R3 g* c$ ?9 g4 j& M begin
5 Y J7 {& x4 |! p5 n6 Z wait for 90 min7 ?4 g Q3 f8 J& L6 `$ p
take down R_mB
' r/ Z4 @" j+ {- S/ a5 } wait for 5 min
6 C& h! r* o& v% Q) n bring up R_mB; }+ B( i* F% J
end* R3 O8 i" t' ~! N
end
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begin P_mC_clean arriving, ~: c* m9 L* k; k8 ?
while 1=1 do
) b* {' r6 }$ s/ C begin4 c9 f, F/ l8 p0 T' j+ Z
wait for 90 min; H5 [8 D! A. Q
take down R_mC
& y' S( m+ `8 U" W$ b+ c6 L wait for 10 min
/ ]$ }0 K( r8 D) Q bring up R_mC
# n4 z, N' S% @/ [* T8 F6 O0 g( ^ end# s' ?3 H* {; u. j
end
8 O2 m( Q- |& d; ]1 h1 d" y+ b----------------------------------------
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4 B5 F3 c" c. Y, z. G3 OExercise 5.9
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5 U2 F( K6 d: A1 P
- k, K+ q0 B3 p f+ `- w$ v9 SCreate a new model to simulate the following system:
) Z i8 T2 T9 b7 \! Y9 m" _Loads are created with an interarrival time that is exponentially ! t: S; r: O/ C
distributed with a mean of 20 minutes. Loads wait in an infinite-" F% T) ~+ N$ } O) g
capacity queue to be processed by one of three single-capacity,
3 |. T* p5 T \) I- ?' J$ O7 }arrayed machines. Each machine has its own single-capacity queue
- J" @, z% ~% o6 y0 }6 r, Q. Q& ^' \where loads are processed. Waiting loads move into one of the three
6 {& ], m: [, x) D, Jqueues in round-robin order. Each machine has a normally Q( R j: n8 p4 R1 F9 O3 A
distributed processing time with a mean of 48 minutes and a standard 2 o7 X- O2 d5 n( K; O% k+ a# z
deviation of 5 minutes.
6 t( ^' L- |2 _: r8 n8 M* aThe three machines were purchased at different times and have
$ @% A. U+ m% p% [/ Q* k2 `4 Hdifferent failure rates. The failure and repair times are exponentially
, p, P% t: B" v1 d% o2 adistributed with means as shown in the following table:
% e7 Y4 g: `! `& cNote The solution for this assignment is required to complete
7 q4 H/ X# V. c- r" a1 [5 C9 cexercise 7.1 (see “Exercise 7.1” on page263); be sure to save a copy of
" ^/ Q4 J+ o8 v' Wyour model.
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MachineMean time to failMean time to repair
' ~, v9 z$ C( x: i9 ]: HA110 minutes 5 minutes
+ {$ M$ ?2 `7 hB 170 minutes 10 minutes, W5 D. O8 U# s& u( i; B7 i
C230 minutes 10 minutes% Z! ~* _% q b! f' |/ p# a2 F/ d: _
3 R- K- n0 K/ Y7 d* TThe machines also must be cleaned according to the following
( k. j$ `; ]' }, Y* hschedule. All times are constant:
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MachineTime between cleanings Time to clean
7 \/ r* v: J7 g! A7 ?2 ?' \A90 minutes 5 minutes
! P1 B0 M d' PB 90 minutes 5 minutes
) J6 q7 x3 a6 S! X& ?! @- aC90 minutes 10 minutes
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$ O; k: S3 `( R, W+ pPlace the graphics for the queues and the resources.
4 x# D4 @# U& o. V! |1 { W5 `Run the simulation for 100 days.
6 u1 s8 p& T3 L% S1 _Define all failure and cleaning times using logic (rather than resource
1 W) [0 g y# J( d$ wcycles). Answer the following questions:* d; w0 D" @/ D
a.What was the average number of loads in the waiting queue?
9 `# b9 K) n9 \% pb.What were the current and average number of loads in Space? 3 G0 K; m# v3 [% ?
How do you explain these values? ( C( r2 x9 j& Q, b) n
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