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发表于 2010-5-11 13:19:52
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用list吧
; y" b. W# f5 ^4 S9 l: n- i3 ~$ N" opatches-own [wealth rank]5 E- }4 ?9 ~# `8 h K, V
to setup- b4 z+ x* m" i+ i& u. N
ca) i/ a( s% o3 z) `/ P+ o% ?3 y
ask patches [set wealth random 100 set pcolor green ]
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to go
. K: t2 S) g& X6 p! a! o( D# y) B. m let mylist1 []+ i2 {- w" H/ E1 ^: ^& G) K' a" F
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
1 y; n- C3 ~! V, g# ]6 A let mylist2 []
" u6 A: M& P% Q3 A: v# g set mylist2 n-values count patches [? + 1]
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: [$ h" f& r6 q* ?6 F ( foreach mylist1 mylist2
% {5 n) o3 k: P/ s9 R; ^$ d1 p [
$ G0 w- }/ X- _5 C G* Y ask ?1[ set rank ?2]
# |& {* V1 H3 f. v1 B show [rank] of ?1
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let mylist3 []
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# j& B6 z' k% X& Z$ {+ e. P set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches1 e+ H6 \3 h: s6 e/ L( I
show count patches
p l2 b" W5 T3 s show mylist1
- Z# `% q: V3 ^ show mylist3
( x* I3 B6 u. \6 h$ D4 Q1 Nend
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+ Y& c: e4 ]! h2 [! \) H4 d这时的mylist1 和mylist3 应该是一样的 |
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