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发表于 2010-5-11 13:19:52
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用list吧
5 @! K4 l0 B5 }0 Ppatches-own [wealth rank]
2 q* e+ m5 m8 k9 J- _to setup/ ^4 g$ K. h4 P p* r
ca# w* b' b5 _* O
ask patches [set wealth random 100 set pcolor green ]& b% m$ B/ O# l
end
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to go6 o) z! z8 ?1 r
let mylist1 []
! {. R6 M# o! L: V set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
( @ H5 I, B4 v4 w let mylist2 []) C9 C0 [$ ]* g y. a
set mylist2 n-values count patches [? + 1]
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( foreach mylist1 mylist2
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d1 R) j$ K! E! Q ask ?1[ set rank ?2]( ]2 e" u y8 ^; x
show [rank] of ?13 T! j( X& x+ g( G1 v" p
+ x$ X0 B0 R f& _) ?: \4 Z6 q% I1 p ]4 P8 z; `# w7 L. I, Q: Q! Z( W: N
)' P# X8 e t/ O+ S
let mylist3 []
: r! r! _# I, E+ ?$ w
$ |5 [* z: I* w: E* ~3 t9 _ set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches- y0 R4 F2 k9 O0 w" O0 D
show count patches# A+ v! t, |- ^. F6 B' E0 e/ [0 M
show mylist1 3 g) W* r# E3 y5 T
show mylist3
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: D% f- ^, d. r7 p+ }% j$ }
这时的mylist1 和mylist3 应该是一样的 |
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