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发表于 2010-5-11 13:19:52
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用list吧; ?6 J2 O3 b( K# e* e
patches-own [wealth rank]
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ask patches [set wealth random 100 set pcolor green ], J/ |# B6 H, Q& m2 z0 |
end
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to go
. |" A$ f1 X0 c2 g: I& q- b& \1 K let mylist1 []
( H3 @- G( l7 x$ T4 L3 b- z* u+ ? set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
2 m. ~! g/ Y% T4 g let mylist2 []. a; P* U% g# X
set mylist2 n-values count patches [? + 1]
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( foreach mylist1 mylist2- I b- L2 A8 a5 d
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ask ?1[ set rank ?2]. D$ }* @9 R. \; Z0 ^
show [rank] of ?1! [/ p {' h+ v I0 {8 R: ?
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)
9 w7 o) r E$ J% N% t H let mylist3 []( z( q7 G8 \; d7 r: X
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches0 b' J# z$ Q, S& W; Y* S9 L0 O2 E( L
show count patches8 B+ Q. U) h3 ~" D0 @+ J$ G& k6 }
show mylist1 R% U: A' L" z1 H
show mylist3, h# w7 ^3 ?0 F( f0 }. o- t3 c1 A, ~
end
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+ ?( B" A! {. r# Y( a. _( ~4 C这时的mylist1 和mylist3 应该是一样的 |
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