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5仿真币
在使用Order List时,当一个order list满足不了order的数量,要用第二个甚至第三个order list,有一段程序,请大虾解释一下,多谢!程序如下:2 L* {9 i( o( g: x
begin P_Order arriving procedure4 O, A( ~% W7 L/ P" N( ^
set V_NumWanted to 10
+ X" @ k3 p' l E/ ? set V_NumOnList to OL_List1 current value
% j e0 W; o& y3 f order V_NumWanted loads from OL_List1 to P_NextProc! E, o/ Q3 ~+ B1 J9 c
in case order not filled) y5 |4 ^, G' G/ B" e4 _1 F
begin
: V6 p s: @+ ?( V: x) { wait for .01 sec
% U: h- [" c* c: a s decrement V_NumWanted by V_NumOnList - OL_List1 current value5 s4 R& `, @, s F
set V_NumOnList to OL_List2 current value
4 k P7 y1 ^% I1 C, E2 B9 q order V_NumWanted loads from OL_List2 to P_NextProc
% Y' j& K; g* l; s) Y in case case order not filled
; l2 g u% ]* F k3 U .................................................................+ L0 z0 }: @- B& X, ]$ d, J) p
C% g' o7 D! F% d" E! u
3 X* Y. I- W( x$ n& t/ n我就是不明白上面用红绿色作标记的那句,为什么后面要加-OL_List1 current value.用前面绿色部分,即把不够的load算出来就不行了吗? |
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由于有in case order not filled这句,所以我觉得红色部分应该可以去掉。你还是自己测试一下吧,不一定要按书上说的做。
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