+ n- |6 {$ P) ~0 W" K, {5 [! H2 A2.这是request的程序( q$ |/ @+ Q$ S1 Q1 T+ ]4 x) M
// Request a value from Extend2 y+ `, k: G3 E: ^/ O
//1 D- p* ]" ^/ l
// Initialize the variant that will hold the BSTR. Set the variant's+ n! G, N+ U5 p$ A( A
// type flag to indicate the fact that this variant holds a BSTR. Place the& T |& m9 V& y! Q/ g( y" O" u
// BSTR into the variant structure.* n8 ]4 H# T# O6 Q$ ^3 z
* ^: K: w* a! C a) R requestVariant = (VARIANTARG *)malloc(sizeof(VARIANTARG) *2); 7 g# E! R9 V0 W1 C- M 2 _. U" p ^9 t6 |3 `5 r+ A
itemStr = SysAllocString((WCHAR *) L"global0:#0:0:0:0:0");2 k: l9 R8 U4 ]! q& J
VariantInit(&requestVariant[0]); , A- w) U5 e. M; `' d1 z requestVariant[0].vt = VT_BSTR;- F0 T, t4 b( U: h& p
requestVariant[0].bstrVal = itemStr;5 W; s3 D; S; M) o
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topicStr = SysAllocString((WCHAR *) L"system"); 7 N. O+ Y$ k; A% G' X VariantInit(&requestVariant[1]); ) V6 P3 Z0 A( v# l9 k' P
requestVariant[1].vt = VT_BSTR; ' T9 B2 i& I2 C- ]# W5 S requestVariant[1].bstrVal = topicStr; + }) ]3 C, U' l" K3 S5 A, e 8 K! r6 f# O8 a3 o5 g0 v// Set the DISPPARAMS structure that holds the variant. - x7 F0 E ~5 Y1 K) G* N+ K# U3 C0 f4 T- F- z8 Z. c# _! q
dp2.rgvarg = requestVariant;9 x6 O. m" h$ z
dp2.cArgs = 2;* ^1 \% z2 i# ~/ ^5 M+ l3 {4 L
dp2.rgdispidNamedArgs = NULL;" Y" x$ p/ f7 f( {
dp2.cNamedArgs = 0; & b+ Y# X4 r$ T" ~( w5 B$ f3 o5 c! C( M
var.vt = VT_EMPTY; . n V' \8 @ p9 j" A% S) e; I * l; R4 l" |" ~& O, |2 I7 O/ D) g// Call IDispatch::Invoke()2 a3 F }! `$ |& Z* n- H
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hr = m_pDisp->Invoke(- v% A1 h5 h/ s0 c' F
requestID,; _$ Q" ?" @* ]. e
IID_NULL,: G* p' N1 E0 p: @; z0 K
LOCALE_SYSTEM_DEFAULT, ! w* ~* }' l) j DISPATCH_METHOD,; G) Q$ e' z G0 L2 B9 ? e" @
&dp2,% R: d. {( n; b
&var, + u2 |( J3 I1 c" s% K5 T &ei,! H* f% z: V! M
&uiErr); ~7 }& ^9 J3 W # D' M- p5 K* \/ P3 V3 q8 I& K SysFreeString(topicStr);% v4 ~* L* W4 {7 a" l
SysFreeString(itemStr); 0 [; e" T4 F+ ~2 K4 H1 }5 n$ ]请问该程序是获得extend里面的哪个值? . Z( g0 M; h: t4 A$ ?如果我希望获得extend程序里面的某个变量的数值,那个c++程序应该如何实现????