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楼主 |
发表于 2008-4-19 16:11:18
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好像可以了
to go2 R' t/ w; U2 Y/ z) [
set t t + 1- _% X/ U$ K' ~* u- _; D: E; w" B
grow2 W, P; p& g3 C: [5 s) |
update-list-of-m5 q& H. X( |1 S4 z; V& T/ a
do-plots& J( P9 u; r5 v9 u8 t3 C; y6 M% J
tick ) X( R$ n! ^4 x
ifelse t > 8+ ^* y! R: p3 L1 d9 Z
[if abs( mean (list (item 0 list-of-m) (item 1 list-of-m) (item 2 list-of-m)) - mean (list (item 3 list-of-m) (item 4 list-of-m) (item 5 list-of-m)))< 0.01 and0 L1 u4 `* n7 |% z9 {
abs( mean (list (item 3 list-of-m) (item 4 list-of-m) (item 5 list-of-m)) - mean (list (item 6 list-of-m) (item 7 list-of-m) (item 8 list-of-m)))< 0.01 and
. c# g3 t2 f# P+ ]2 t' t* @' a- q abs( mean (list (item 0 list-of-m) (item 1 list-of-m) (item 2 list-of-m)) - mean (list (item 6 list-of-m) (item 7 list-of-m) (item 8 list-of-m)))< 0.01
" x, ~- Q$ P* o, ~! ^ [stop]]
7 k& @' V; Q: ~ [ ]
- T. K$ z) H7 Iend
3 F: g( n, \( R各位大虾帮忙看看,这样好像可以了。以前用while之所以不行,是不是因为如果报告为true,那么就会反复运行后面的命令导致死循环啊?
, k' Y& j- _2 k7 K% T还有就是[ ]是不是意味着不执行任何操作,返回set t t + 1,然后再grow,再 update-list-of-m,再 do-plots,再 tick ..........这样一直按这种顺序循环直到停止。
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3 a! u4 U# v" }6 u n; N! l& e[ 本帖最后由 wjcpcahu 于 2008-4-19 16:19 编辑 ] |
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