编程遇到困难 请帮助

ding1617

to meet-wolf;; wolf procedure
  if count wolves-here >  0           
  [let otherwolf one-of other wolves-here                     
    if abs ([k1] of self - [k1] of otherwolf ) > value-k1
   ]
: y: F, _5 h1 C3 o' }8 i' a! d   [ set  [k1] of self [k1] of self + [k1] of otherwolf
; {5 p0 L9 L9 [) B. D! {   ]
& z2 H! i) b0 n& v$ b     end
显示otherwolf没有被定义，请各路大神帮忙调整通顺

SsendasX

应该是other wolf，，，吧