编程遇到困难 请帮助

ding1617

to meet-wolf;; wolf procedure
  if count wolves-here >  0           
  [let otherwolf one-of other wolves-here                     
2 R8 q2 ^2 v0 i    if abs ([k1] of self - [k1] of otherwolf ) > value-k1
( d3 R/ r! g! {# g( D   ]
   [ set  [k1] of self [k1] of self + [k1] of otherwolf
   ]
     end
8 R6 d$ h, |1 F& s3 v显示otherwolf没有被定义，请各路大神帮忙调整通顺

SsendasX

应该是other wolf，，，吧