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本帖最后由 soso001 于 2014-12-17 14:53 编辑 " g1 U; f: W2 I0 i
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不好意思,打错了个字母,呵呵呵!
# |0 {: L" B6 r3 @7 ~7 v, x: _大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
. R, N* Z2 a3 p“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!' E& c7 k% R( z! F: l9 ^
is
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M:string;" I6 [7 r: y4 Z/ W/ y
selecTab:table[integer,integer,integer,string];) c8 W; T, G. `: h
do) R. h2 } X) d% \/ O% b
initorders;# f; ?$ N* C" _/ e7 U9 @
3 {5 d- B1 K) N: o scheduledorders.delete;
1 U' R' G/ S; @0 x9 t1 I seletTab.create;& ?9 i3 v' Q% b, S U0 f& F9 D
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orders.initialize({2,1}..{2,*},0);2 r$ |% X' t8 I1 T, Z
orders.initialize({4,1}..{4,*},0);; u; E9 ]* _% n( Z& }$ L
for j:=1 to numorders loop
# f4 W! [. c! g+ C orders[5,j]:=orders[1,j][2,1];- H$ {# ?1 Y* X& u0 S/ ~$ f
next;+ N( D+ L8 c9 _
occres.initialize({1,1}..{1,*},0);5 z/ ^- D4 ?3 N* ]' |& Q$ q
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--XUNHUAN' L7 Q0 f- I9 z7 h7 M7 y( h
for scheduledsteps:=1 to numsteps loop --- r8 E8 X1 q' |: j) y; ^# u: a
selectab.delete;' ?6 k5 S9 S- H; d% T, X- i1 h
k:=1;% P) R5 n% P. n' |6 c. i
for j:=1 to numorders loop
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. U! Z. b7 x- ]* k! n nstep:=orders[2,j]+1;; s7 T6 ?. t1 r* @! p; D
if nstep<=orders[3,j] then( d/ N* l* z# b- ]
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
2 m9 ^, i& _6 g7 T9 P k:=k+1;
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/ b3 }+ B/ c# [1 O- V) X) S6 Z end;
0 ~8 B q5 _1 M' {, ^8 p" q next;
& n5 V* U9 x! \8 x0 ?# J' S mincomptime:=selecttab.min({3,1}..{3,*});8 v# Z* q2 U. w+ ?2 w
8 X: @% V' Q. c* ? from j:=1 until j>selectab.ydim loop
+ E5 s+ b, L$ V# t, Q4 L5 b
$ V$ X: u' Y: a; `# \: d0 c if selectab[2,j]<mincomptime then
' |2 v' V; {" l& X& _3 S j:=j+1;
' ^ y! ?) b2 b+ p6 \% h else- ^2 e+ z4 h6 E9 t
selecttab.cutrow(j);; q2 y5 G$ _; }
end;
; J3 P/ n0 x; X8 j# K( b end;
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j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;" N6 u- s$ {! ~" w' M
orders[2,j]:=nstep;
" Q1 U% \8 @: H; |$ ~ m:=orders[1,j][1,nstep];5 S3 i: d5 U/ ^/ x
c:=orders[5,j]
. L# F) U2 T$ Q5 Q! i- W, ` occres[1,m]:=c;8 V+ t6 t" M2 k$ M: C
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--jieguo:start,end,res,job,step/ Y# @5 B' p* m. [
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);2 @; \/ \# O7 ?0 c0 [0 X% B
for k:=1 to numorders loop; w3 B" \7 S/ @9 c) y
nstep:=orders[2,k]+1;
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
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then
+ V5 J. |$ g8 K( X* W5 r/ p: x. q orders[4,k]:=max(c,orders[4,k]);
9 E5 q0 b) x: M4 z) D# u$ o' z --3 G+ p0 G( }1 } Y w. }8 C
orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
5 n ]3 `9 ]4 F1 n* c --
6 d" N' M4 I' {3 O7 g end;
4 M+ }' u: ]8 E% \* m G next;/ S8 b% e: U- a4 I* j
nstep:=orders[2,j]+1: R8 p3 I6 h' M( W$ G1 m: d
if nstep<=orders[3,j]! Z- {( S2 L8 ^0 B
# p+ U& L! D+ p4 I then
* \8 l* W3 _0 ~. n9 @+ G! F orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
4 z3 l7 U$ o' v9 I( @5 K/ K orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];) m7 |0 j) j |# e" j
end;
3 i. p | D! e next;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});: v6 n* B1 G4 \% `" |
mygantt;# d# u) R n! I$ Z; P" Y+ ]* e
ens;& D& U4 b0 u m! ~ \
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