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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示 F' w. C8 v0 B; r9 z% n! S$ i3 f
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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j,k,nstep,c, scheduleteps,mincomptime:integer;
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selecTab:table[integer,integer,integer,string];' K$ M* s4 D# R" V, \
do, N) l2 ?! F" p& _% p" R2 h: G
initorders;. n4 L2 p& L8 f$ y- k. D! d; O
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scheduledorders.delete;; C! k0 r' L- p. P/ ^; l
seletTab.create;
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, b+ w3 x( B& E. M orders.initialize({2,1}..{2,*},0);" C# H! a0 _. e& N( g, i' L: m
orders.initialize({4,1}..{4,*},0);% Z; a2 f3 S7 [$ S0 N2 n3 p3 x
for j:=1 to numorders loop
( t& r ]6 f' @! Q orders[5,j]:=orders[1,j][2,1];
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occres.initialize({1,1}..{1,*},0);8 v' f6 C4 a- v9 B
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--XUNHUAN; O6 k/ o9 G9 _: g7 s
for scheduledsteps:=1 to numsteps loop --" ~8 S' G% S0 P/ k% w5 y6 Q
selectab.delete;
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for j:=1 to numorders loop
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2 m2 Z' B; ]% N6 P nstep:=orders[2,j]+1;
5 ~4 r3 g8 P L; b m if nstep<=orders[3,j] then
5 j$ i" h _+ a' C2 b( ] selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
% Z* j2 J5 Q& f& x k:=k+1;/ k: z+ d) c& J
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next;3 M+ C$ D- K; J7 [; ?- x
mincomptime:=selecttab.min({3,1}..{3,*});
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; Y U; \2 D6 ~3 e from j:=1 until j>selectab.ydim loop2 h+ u; x8 | b6 s2 p; k# G
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if selectab[2,j]<mincomptime then4 D1 F0 b- q+ @; F
j:=j+1;
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selecttab.cutrow(j);' a+ p9 |! B' S, D, A
end;. o+ G) u6 w: H3 ^
end;3 C% }$ C: j4 U' M0 [) f
1 D' N! p0 W* P j:=selectionrule(selecttab);
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0 p" U* e. Z% E% J nstep;+orders[2.j]+1;3 W& F2 l7 J7 [/ A
orders[2,j]:=nstep;6 R0 h9 ?; |- s* z
m:=orders[1,j][1,nstep];
: f- H* t6 Q9 t1 G c:=orders[5,j]% _' Y0 d9 m% U# C, O" o, A$ W" g
occres[1,m]:=c;
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--jieguo:start,end,res,job,step
% o5 _. `+ T& R. J t' |* S$ O scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
3 D- v Q. n6 A- R9 w for k:=1 to numorders loop
6 `" ?2 q% e! t# l# D+ u nstep:=orders[2,k]+1;
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
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then i3 ]- o6 Y5 O( Q& I& X- l5 ]
orders[4,k]:=max(c,orders[4,k]);: `8 I- B" }" n4 ~+ I7 H
--% i G( e7 B' U
orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];2 u& w8 j0 G r3 P9 M
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end;
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nstep:=orders[2,j]+1:" W5 A- E7 b8 x$ q6 S
if nstep<=orders[3,j]
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then! f$ }/ ?+ h) \5 G1 N9 \8 G
orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);6 Q2 k: D" _6 v% X0 g( H
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep]; }: m% a+ j: l6 |' e u
end;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
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ens;
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