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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 9 Z9 A" [; h3 C0 n4 N7 j k
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我今天遇到一个问题,请问你知道如何把来自两种不同的load1和load2在一个机器上加工,合成一个load,该如何使用order命令?我每次运行的时候,给出的报告里面资源机器Massm没有load经过?以下是我的程序:
8 X4 `6 e0 G! _begin P_in arriving* s1 O+ D& F0 w$ T( X; M
move into Q_in/ u' I1 U/ l- p, X" w" B
use oper for 2 min
: G/ w+ K+ K, `' Z. [' r, T send to oneof(0.95:P_in1,0.05:die)' _; T+ Y% O, H: D. j f
end
& I; ?6 V9 r' n d3 D$ g, l( P( s6 s) Ubegin P_in1 arriving+ Y8 V$ l9 x$ I( W
if load type = load1 then
^6 R i* M& s begin
2 \0 w& F6 _6 w+ b; J move into Q_m1
; g8 x y, X" y& n! d use M1 for u 5,1 min
) B; |, h( j0 k# B move into Q_out1
- }0 j, ?7 o& O" W3 p7 l) i wait to be ordered on orderlist OL_1; J' N; K" u. \7 Q
end4 _$ I9 g/ ]: y
if load type = load2 then
* C1 t1 `) G L, ?' R begin8 C* d6 d# T, M* {# }' K" U0 Z) u, _
move into Q_m2% m$ J! ~, k$ p1 Z' {
use M2 for n 8,1 min
" M) S; a5 K. _" w move into Q_out29 l; r! c% _& A# b
wait to be ordered on orderlist OL_27 C. `% _ e I5 r
end
' f5 t$ p- K0 X: qend" f, F( s- l( j. f, n) k0 \
begin P_dunmy arriving% I9 i' ]! c* B
set i = 1
. Y- s. J: J- I2 K+ C* I6 o* R/ B while i > 0 do4 f' L) d4 }& T
begin s$ L2 E" b( z7 Q. W
order 1 loads from OL_1 to die5 c# i4 d7 t0 q; Z5 b
in case order not filled backorder on OL_1
+ n3 ~0 }! F: n/ g) Y- R order 1 loads from OL_2 to continue$ W. w( U" r! p' A3 r3 \
in case order not filled backorder on OL_2
- k$ u: A* Y- P. M move into Q_1" Y W0 m: Y5 w8 G
use Massm for n 5,1 min
1 c2 ]( x) S3 X send to die6 ~5 V. I8 z4 l: n! g7 r- J
end
s( d. O8 [; J' j: Send
2 E/ h9 H- O( H这是我的报告' E; M6 A2 @! u: h4 a
*** AutoMod 11.1 ***, ?7 {* c2 H) ~. H6 X' A) d" G
Model q
6 Y$ O1 x( Z. J( Q0 fStatistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00
8 m! A$ j3 h& @- P8 VCPU time: Absolute: 42.859 sec, Relative: 42.859 sec9 h6 i* w; h: s! N
Statistics for Process System "q"
/ h" o; \" \6 h! NProcess Statistics5 S4 R \# w) `7 J
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait- u6 \% Q( }- O) T7 D2 X( H
========================================================================================
0 _7 ?) A7 L) {2 i: XP_in 222 1 0.32 -- 2 0 -- 126.04 --/ H* C8 l3 S8 s7 k: W) f6 M1 q
P_in1 212 210 102.38 -- 210 0 -- 41725.92 --. @% J7 O, ]: M5 ]$ b! E
P_in3 0 0 0.00 -- 0 0 -- 0.00 --" H o. n# ^1 u8 d8 F
P_in4 0 0 0.00 -- 0 0 -- 0.00 --3 E8 r! E) _: p6 U5 _) R! O8 r0 |/ C
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
0 V6 W2 ^1 i/ Z wProcess Traffic Limit Statistics) K2 b) n# A C- O
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait! x* j; F; U2 @! l' Q: p
========================================================================================
3 B4 c( ^+ Q; E7 VP_in 222 1 0.32 Infinite 2 0 -- 126.04 --
5 l. {+ z( z }. ], L! QP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --
4 v0 O0 {6 v& ]" i& X$ YP_in3 0 0 0.00 Infinite 0 0 -- 0.00 --8 {/ G4 v8 g0 [7 J( S! `6 n; |
P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
/ N; w" g# d- s7 y. [' D1 r/ @P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
@. G9 w& c, h6 ^5 i8 N3 LQueue Statistics
8 Z/ [: p* s( T0 yName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
2 R1 C6 a& O8 x, t, z========================================================================================
$ H: |/ `- ~3 f- \ t, _Space 223 0 0.00 Infinite 1 0 -- 0.00 --8 X% S* N4 G9 v! f0 p
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --5 d) b& e: g' a. n& g) i4 W7 z
Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --" Z/ M( j5 C2 A8 g
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --$ X" O( G1 n$ E I5 Q. n1 f# @
Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --/ w/ a; z/ |9 @6 ~
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --1 S8 J- Y. G8 t: U: _
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00" @$ L9 K0 u4 N: C% ?: R
Order List Statistics6 Q0 h1 Q. d. ? c* y0 ?: x. c
Name Total Cur Average Max Min Av_Time Tot_Back_Ordered
( a2 {6 v& p- U$ {: q================================================================================9 e( s$ _6 P( D* N; u7 Q% t0 i; w
OL_1 139 139 67.23 139 0 41789.43 1
, ~2 r. o5 \, o1 G3 H3 h y7 gOL_2 71 71 34.26 71 0 41693.20 14 l& K2 @( D! [# E* r. _
Resource Statistics
/ w; j$ j' H% c, r1 kName Total Cur Average Capacity Max Min Util Av_Time Av_Wait State 4 v6 Z8 G$ Y, N9 A
====================================================================================================
- e4 A$ a/ I/ }; G% |# SM1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- * o9 Q+ f- b+ d8 J1 t/ D
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ----
7 L# `5 {2 B* |8 Y. FMassm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
1 L$ m" [, f! g6 ]! roper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- 9 `6 l1 Q7 o+ C$ r! w. i; K+ W1 l
Random Number Streams- ]; E! F1 w6 X; s% u8 n
Name Total
% b- B1 H: g0 d; p: }============================! m6 V- h( e& E! N
stream0 455: Q5 s7 E" t+ }
stream_M1_1 0
9 x6 I" x6 U1 F) K3 Nstream_M2_1 0. s; c5 S2 o7 Y1 Z- X. c! x
stream_Massm_1 0
) S" Z) H& N$ Gstream_oper_1 0 W2 ~9 |7 f7 E/ U
stream_load1_1 184
; ^4 A2 n6 D$ m+ @/ F# _0 ^stream_load2_1 76" c/ H+ `# P8 ?$ A
stream_dummy_1 0
1 L7 @, T! r# L9 J# D- m. C
3 G9 D1 b% }# c' L+ @1 S# [2 u请问我的错误在那里?我用的版本是11.1的学生版 |
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