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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 ; K& u( L# H+ A* T$ l
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我今天遇到一个问题,请问你知道如何把来自两种不同的load1和load2在一个机器上加工,合成一个load,该如何使用order命令?我每次运行的时候,给出的报告里面资源机器Massm没有load经过?以下是我的程序:* h* c9 C# g7 k* Z/ i3 c
begin P_in arriving
% h n) k; p3 J0 H; t) Q move into Q_in
- o* r% c' D2 Y' O use oper for 2 min b& q% E. l) n8 R" A' X
send to oneof(0.95:P_in1,0.05:die)
3 [8 Z8 `5 M0 |end
6 z1 l0 _1 A, u- P9 W: R+ wbegin P_in1 arriving+ a" d. `( K( W. ~7 G3 j
if load type = load1 then
4 f4 L5 h( n1 w8 Q0 s begin
% F( p4 ~* k* z; l% z move into Q_m1
j3 c2 A+ a: k, }9 t7 c+ q use M1 for u 5,1 min1 ^: e, q6 E9 H7 T2 b
move into Q_out1
* W D1 N+ B8 K% Z8 N wait to be ordered on orderlist OL_1
, `: N T% A0 f end$ R3 Z' ]/ o2 o& r+ F6 Y1 X
if load type = load2 then9 z3 H% j, C9 u3 s- x8 G
begin0 W0 s& b8 Q0 y; r/ o8 g
move into Q_m2
* o9 J4 C- u5 Y% d( A use M2 for n 8,1 min# x" n; z. J) m+ @2 F
move into Q_out2& f" `/ F) A/ W& U' ~& Y- B7 l
wait to be ordered on orderlist OL_2
0 S0 Y4 D @( k end$ y6 f/ ^5 c, V, M
end% V" g9 u5 b" M2 ]" r- u2 n
begin P_dunmy arriving+ l( \' R( r7 Z5 K, m9 Z: V
set i = 13 o2 D+ E0 h2 n: Y
while i > 0 do6 T5 w9 m8 z' I7 z7 q
begin
1 q; D7 S7 i2 h& ^& |3 u: K order 1 loads from OL_1 to die
) f% d" j' _4 a$ N in case order not filled backorder on OL_12 C. M% a1 H& o z' f0 E6 c& r
order 1 loads from OL_2 to continue
2 J5 E1 @6 F* i3 l4 h# z( L in case order not filled backorder on OL_2
" Z X; g# u; o% Y b2 Y# \6 n move into Q_1
0 Z; g2 j* ?( e0 M- U! L# G/ b: s use Massm for n 5,1 min
1 y# d1 U; P' y. p) y send to die
5 j2 I' l8 f- E) M% D; L* Y% B; _ end
- h; h! H4 p1 Z% x' A1 j3 }end
' o' }3 l1 S0 r/ \# u这是我的报告
0 c: n) {, s8 C: M) c*** AutoMod 11.1 ***
/ I. ?% Q- `8 D1 E+ IModel q
# d3 [1 |2 y% \9 CStatistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00' M) ]6 v+ s, g' V5 `& w- z( D# ]
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec, P3 l6 ?/ |8 X3 d- w
Statistics for Process System "q"2 Q( S" q+ h3 A6 y8 a7 i8 O
Process Statistics8 x! @! \1 u/ F' X
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait3 V9 |. w+ p: |, y" X7 D
========================================================================================
3 y8 f1 e* b+ iP_in 222 1 0.32 -- 2 0 -- 126.04 --
; T* V- } {7 OP_in1 212 210 102.38 -- 210 0 -- 41725.92 --
" H$ u0 R8 D6 A4 _( ?! W0 }4 @P_in3 0 0 0.00 -- 0 0 -- 0.00 --
; d/ Z5 V/ }3 M7 G1 K+ `P_in4 0 0 0.00 -- 0 0 -- 0.00 --
6 D5 m) G9 Y2 j4 y# m% X( TP_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
) q1 P: ]! s: f$ C9 X N- fProcess Traffic Limit Statistics4 i0 j, P& c& K5 T( T
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
6 z" f' w! A9 l& N========================================================================================
2 l7 N1 @2 O* [P_in 222 1 0.32 Infinite 2 0 -- 126.04 --
z, A1 B F- Z, KP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --5 o* G: l. v4 I; j
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --7 x' f% ~& ~1 B! L3 y z8 v
P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
' W" G. Y. Z* y' J" c" ^P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
- {' ?4 R$ z6 l2 k& GQueue Statistics
+ K' B2 k2 J+ E! {$ c! sName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
4 U8 e: e/ I$ x' W5 m========================================================================================/ `/ X) K8 j; v! E* D& u: G' z
Space 223 0 0.00 Infinite 1 0 -- 0.00 --
; |/ _3 W. g2 O* ^4 i1 gQ_in 222 1 0.32 Infinite 2 0 -- 126.04 --
6 J8 |$ {! G6 O' QQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --9 E: c+ {$ Z+ }( `* i0 N
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --) K2 s: z3 g% p
Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --8 U! i* ~5 ~. A+ K) N, v+ y) R5 N5 W
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --8 ^- x1 t7 R! f$ x- U" ^/ `1 j" n. u D
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00
w3 b" i, \+ F# j2 \* cOrder List Statistics
* v* R) K7 U1 A" ^, rName Total Cur Average Max Min Av_Time Tot_Back_Ordered% d7 B# c& h% W9 a6 j, J( I8 N
================================================================================" b, \8 W7 F& o+ a/ a
OL_1 139 139 67.23 139 0 41789.43 1+ z, S! i: G( `: Y
OL_2 71 71 34.26 71 0 41693.20 1) V- s; c* u9 B( k2 r+ x3 k
Resource Statistics
( O5 m: O5 Z* U y, NName Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
9 c- I) ~% W- j4 y5 b8 }====================================================================================================
) l6 K! A6 j, D+ g2 c; l4 {M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ----
% h4 K4 A1 [; I$ qM2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ----
; P" o# a7 z8 z4 J7 j% HMassm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ---- ( f! Z# }( h7 g- Y& u% F h+ N6 F
oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
/ A( P1 n) q3 N# Q# \1 iRandom Number Streams& s" M# `, N5 }* P" i
Name Total & W# e2 ^. n& j( B2 u
============================
7 ^. ^$ x$ l8 R% Lstream0 455
, a V% W C: ?2 @+ T. lstream_M1_1 00 ^- f% j. H1 B! r
stream_M2_1 03 N) k( O5 @6 z9 K4 \. T* X
stream_Massm_1 0
. u6 d* D: ^0 K: Zstream_oper_1 01 [$ H) V) [! k& o, e8 E
stream_load1_1 184; I& w% M; ?" q) m) r1 Q+ N6 {6 O# X
stream_load2_1 76
5 _1 B1 g0 k' G8 R Q: ]4 v! Z# Wstream_dummy_1 0; M5 g# E. u3 u
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请问我的错误在那里?我用的版本是11.1的学生版 |
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