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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 , ~- k1 ?+ `0 J* [
7 q( L# m p6 a: }/ p我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：" R" m- Q# Y% A9 [1 U" M% S$ |$ I
begin P_in arriving
9 D( K8 q! f5 Z4 f: }6 W% L0 S6 q" z8 j move into Q_in2 t! |, C7 ?& H+ u" X j- r
use oper for 2 min
, B+ I( _& ]( Q( B2 q) e send to oneof(0.95:P_in1,0.05:die)
6 G9 W1 h7 M, }+ Z. z: q7 ^4 {end
+ [. l Z; R4 c- Jbegin P_in1 arriving/ s6 S: l/ z8 B( B7 B
if load type = load1 then
; t6 b1 o) _- i begin3 Q+ I, L& e+ W5 q. ]8 B
move into Q_m13 l8 _' ^ ^1 A9 f& X
use M1 for u 5,1 min0 @0 ~4 O! Z; {/ h1 |
move into Q_out1' m1 `4 i: F* \% {' _. w0 d
wait to be ordered on orderlist OL_1
6 s( m7 z8 a7 |5 u9 C m3 d end
& `/ {7 C3 ^+ l4 n8 T3 } if load type = load2 then
! p: f& V1 Q* H; |. L' i1 H% L( e begin
7 O* c: p$ t1 U7 J& [4 n: A1 k move into Q_m2
! w7 }, i9 C' ?* @: x use M2 for n 8,1 min
1 q% C7 a; L' r: R, T: ? move into Q_out2+ G2 d; I0 O; ?! M' y' i
wait to be ordered on orderlist OL_2
: ]% q: D+ q d: i. M: m' s# O9 s6 U end
+ @7 b. m! J7 a. |" tend
. U* I4 `! }. I; k E" P+ l6 abegin P_dunmy arriving \# x5 B F, }) b
set i = 1
/ N, C# M* I( J h while i > 0 do
& ~( a2 ^: N* n$ T( P) ? begin
3 \- q1 E( j9 | order 1 loads from OL_1 to die
, x: \2 x% q, p3 S# @ in case order not filled backorder on OL_1
0 h' q& ?6 b* Y3 t order 1 loads from OL_2 to continue
7 w3 C; N: Z) `# q" I" e in case order not filled backorder on OL_2
/ U1 w) E/ j) ]* p3 j move into Q_1
1 n5 E) V, V/ M, H use Massm for n 5,1 min+ E2 I, Q- t# B: L+ C
send to die- k9 ^" V' l4 F9 _
end
2 U3 r u8 B1 @end9 i, g! E8 [* m1 Z' T1 s. |; i
这是我的报告6 {$ ^$ L! v# v2 O( [, j
*** AutoMod 11.1 ***2 Y7 V$ {) P" G
Model q$ v% ?* g& r0 T1 ^- p
Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00+ s, ], N6 e0 H! P4 A
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec4 U. u; A" a. s! _ f( F0 n7 F
Statistics for Process System "q"6 H U. }" a' [4 X
Process Statistics
* _' d5 q% H- ]' \Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
+ r( {& @, q! B' v9 w+ h========================================================================================
% V( c8 m3 q! {P_in 222 1 0.32 -- 2 0 -- 126.04 --0 n7 s" o B& X. C
P_in1 212 210 102.38 -- 210 0 -- 41725.92 -- F3 d6 u8 A T& d: z3 A8 V" S
P_in3 0 0 0.00 -- 0 0 -- 0.00 --
9 |9 ` Q8 c9 w+ IP_in4 0 0 0.00 -- 0 0 -- 0.00 --
0 S* l3 k3 g$ r. K' _1 P. EP_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
$ a Z1 d7 l: I1 i" B% S6 c8 JProcess Traffic Limit Statistics
/ l8 Q Q: `. Z1 z$ a) O/ T2 AName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
" r$ v5 w0 \7 E- q========================================================================================
, B$ F. a$ q; U& N3 k8 z4 u1 DP_in 222 1 0.32 Infinite 2 0 -- 126.04 --
& P" V' @0 {8 q- m3 C! f* rP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --
" l' `6 }1 O! d) b( E/ y1 aP_in3 0 0 0.00 Infinite 0 0 -- 0.00 --/ l9 x9 W- ^6 e6 p
P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
# ~) Y& Q" o( i W) VP_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --7 Q. i+ v) v) c. |
Queue Statistics
) `7 C( g& [& r# xName Total Cur Average Capacity Max Min Util Av_Time Av_Wait8 x% [" t7 W* I- i8 T/ ~+ a* @; m
========================================================================================3 Q) K* I) ~: H7 b
Space 223 0 0.00 Infinite 1 0 -- 0.00 --/ a0 w# h! t' Q- n- i; e! U
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --
. _& V& c. M; C# m6 Y0 }! u4 o/ e* KQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
6 W8 v% p3 O, m2 b0 m. ~3 {Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --" }7 m f+ V3 M% g2 V& z9 E
Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
7 B* g h" ]. V, QQ_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --
% z2 h" I/ C, B" N# W; e8 iQ_1 1 0 0.00 1 1 0 0.003 277.31 0.00! O, ?* t7 K: v! I/ D% X* P, q
Order List Statistics6 D9 Z* k; q8 O# e0 V. p* t3 O' M
Name Total Cur Average Max Min Av_Time Tot_Back_Ordered
, m6 v, _/ S% U0 t1 n5 m================================================================================
% q4 @( x+ _' c0 |; fOL_1 139 139 67.23 139 0 41789.43 1
& A4 M" l) n8 [8 JOL_2 71 71 34.26 71 0 41693.20 1! T) Z, s; D" S9 H$ A
Resource Statistics/ ?/ k5 \, c/ o3 ^# h9 b5 [
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State l; J* p/ B2 q! O8 w% [
====================================================================================================
y- a1 x3 ]& o( U# GM1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- ; L7 i. F. [2 f8 o8 X* f. m
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ----
, {9 u& B$ U9 O3 nMassm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ---- 6 z n- Z5 R7 {* ]3 t7 @4 B% G& ]# O
oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- : I& F. w! o$ n
Random Number Streams. g9 k/ l$ U& i
Name Total
* w8 i* D2 o5 |1 t============================9 D+ q$ @( a- G. J5 X9 v1 v g
stream0 455
5 T V, H6 p0 _- h7 y! Istream_M1_1 0
/ Z2 Z; ~3 @4 X# o Tstream_M2_1 0; z4 D" }* ?0 {
stream_Massm_1 0
7 i! x3 ^0 ]2 Y2 ]stream_oper_1 06 b3 f" u, J7 k
stream_load1_1 184
7 F9 V* D1 ?0 o0 o1 ostream_load2_1 76
2 |7 L2 M2 [7 o2 D) \0 \) U, Pstream_dummy_1 0
6 e3 `8 C3 f: P+ b" ?5 t$ J& m: v. Y ], Q; ~$ b
请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
