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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 5 @- M, `# x& H& i1 w% D
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我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：8 _) t9 s) g# V3 i
begin P_in arriving
]* u- l1 f _9 m* ]! O move into Q_in
$ Q6 Q8 E# G( Z6 d' W use oper for 2 min2 J2 @) G7 A, M+ q. O& |8 {
send to oneof(0.95:P_in1,0.05:die); K( x1 g; j1 _0 I, w ~
end
0 P' b/ E. K' o% M2 abegin P_in1 arriving ~1 A9 t- f1 M: F% ~5 @8 O# _- e
if load type = load1 then$ l& O& y8 V8 v9 C$ S
begin1 t* P7 g" f& ~( Y8 t
move into Q_m1
+ l/ E i3 T. y& D use M1 for u 5,1 min
! H! g2 M6 `, @" S8 x2 U) | move into Q_out1. n5 H" V+ \* \4 D1 n+ |
wait to be ordered on orderlist OL_1" K( r, F* {7 ~4 Y! ?* ?+ o/ v
end' y: P& j# s/ h+ S+ z/ N R
if load type = load2 then$ G9 l* s( c" X6 i2 l6 U! w
begin/ l$ T/ g: }6 F. w$ B0 M/ H
move into Q_m2
- t1 \5 W$ I) P! [ use M2 for n 8,1 min
: b+ g9 T. W4 a8 r1 D: F move into Q_out2
[/ g" z( U, u* R( X+ ~ L wait to be ordered on orderlist OL_2
) L2 T) e h3 B5 j end6 w% X3 W' l! I! n
end2 b' e& B! \# t( U+ @! N; V
begin P_dunmy arriving
) T8 R+ B# I/ m q set i = 1
9 j) G$ f2 U: q6 k while i > 0 do
+ {4 D B$ u) e# H$ n; x2 `" M begin 7 ]* ^6 }! Y& ]+ c o
order 1 loads from OL_1 to die
; U3 q8 P% ~( S" g. \& {" R in case order not filled backorder on OL_1+ B8 z3 X% W' k) U2 I
order 1 loads from OL_2 to continue$ ^. u# ~9 J( x0 a0 J4 q9 S: G+ g
in case order not filled backorder on OL_2
5 `( H) k) l0 C; g5 c move into Q_1; i! I" X$ P& p5 x; p# Y
use Massm for n 5,1 min9 N- k9 Q- V7 `
send to die
4 z' @ h9 o7 A1 R. z+ P7 q6 i end
5 q( M9 y7 D" y/ W, S: _5 Eend
2 |( E, B( ^3 _' y n" J这是我的报告
9 @6 G4 |6 F3 I0 k( Q*** AutoMod 11.1 ***' L9 e. d# _7 u: e* G
Model q) D: @5 p0 @# @5 D
Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00
G- n, [8 q, u. i m& GCPU time: Absolute: 42.859 sec, Relative: 42.859 sec4 `% s Q* n" d" |1 d) P
Statistics for Process System "q"* \4 @. w0 ^. z3 ?1 M9 I5 ]
Process Statistics
2 x, p1 i9 M. V0 bName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
$ ?% @+ b8 Z, k/ u========================================================================================
/ }2 a7 u9 }7 |1 d( e) f0 e% dP_in 222 1 0.32 -- 2 0 -- 126.04 --
: q. Q' ^4 ?2 g* ?4 _P_in1 212 210 102.38 -- 210 0 -- 41725.92 --
% h7 w. I$ u: v- E, I4 N TP_in3 0 0 0.00 -- 0 0 -- 0.00 --
9 u8 a; L) }1 \& UP_in4 0 0 0.00 -- 0 0 -- 0.00 --5 U) W1 _1 ?7 n1 y' Z/ _
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
$ h9 W U: U: K; YProcess Traffic Limit Statistics
* p0 y: J% U8 \! p: y0 kName Total Cur Average Capacity Max Min Util Av_Time Av_Wait% \" m" o6 K5 R/ g
========================================================================================7 [8 j1 g1 H( \+ C/ y3 j
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --" C5 e# w( b" H4 H" a" o
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --
3 _( G# T( `# ^4 LP_in3 0 0 0.00 Infinite 0 0 -- 0.00 --- h8 x1 I' _9 w9 K; H+ o; a6 p8 r
P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --, k" g" S, K7 @1 I8 t" W
P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --. ^! U. b5 W8 M
Queue Statistics+ v% q3 }% l' J
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
& m2 B* c% f* |5 t) _' D% s========================================================================================
" f( u0 T& o5 `Space 223 0 0.00 Infinite 1 0 -- 0.00 --
$ i. {( G) `1 K1 tQ_in 222 1 0.32 Infinite 2 0 -- 126.04 --
7 w4 j; t2 G3 R; ZQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
! W1 H; Z4 s8 ^Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --* I0 c4 v7 H3 P2 k
Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --" E4 z& ^/ B1 @7 K: j3 h. I
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --+ u& F5 d5 |" [) g
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.002 D* L& }1 o w! R; n
Order List Statistics
0 [+ ]/ f/ Z" D7 ~. n& KName Total Cur Average Max Min Av_Time Tot_Back_Ordered
, k0 Z) I" J2 p% c================================================================================
`, i- S/ v: x" R4 }$ P! wOL_1 139 139 67.23 139 0 41789.43 1: R" T+ O) H* h2 Y% m0 Q2 b
OL_2 71 71 34.26 71 0 41693.20 1
2 c) X6 Q6 j' {8 m. |2 ~; G2 B- XResource Statistics
. i3 I3 P9 B3 d8 T8 {/ [) s# SName Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
' e4 k$ W# F( M$ m) d2 G$ ?====================================================================================================' ^8 ?8 |8 x& d% F( f1 p- ~
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- . A0 w7 o# D" l/ r# {1 r
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ----
. s% ?9 {! w- l5 U7 w K6 d" ^8 v4 \& BMassm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ---- 8 O& ~, m0 Z3 r1 v5 ?7 ~/ Y5 F! P! S
oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- # V' A7 R0 @# {; \" }& y% A6 {0 D i
Random Number Streams& W/ g# W4 B% T! a
Name Total
! m4 ~2 x" v2 v============================' H4 k$ @( q/ O( r9 x5 s2 T; K
stream0 455+ w) m: _) l2 r6 v0 I
stream_M1_1 09 Y& z: ~* Q3 j- G1 Q1 S* h7 k
stream_M2_1 07 z& {6 {3 x: y. G4 q5 V" z
stream_Massm_1 0
# N m) s4 \* q* l9 ]stream_oper_1 0
! ^' ^- i7 D: W* M4 }stream_load1_1 184: f7 p3 ?9 d9 }5 n* P4 Q
stream_load2_1 76& `$ i3 ?6 ?3 w$ N; f* ?
stream_dummy_1 0
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请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
