本帖最后由 GJM 于 2009-12-5 21:43 编辑 5 _ e; G Z6 H: S
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底下是小弟做AutoMOD里面PDF练习的(Exercise 5.9)逻辑文件但问题是,程序只Run到Machine A和Machine B就没继续下去
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4 R1 }" o! ^/ V7 `不知道是哪里出错,另外这题和Exercise7.1的题型类似,请问若要符合Exercise7.1的题意又该如何修改呢?请各位先进指导,谢谢!3 m' ~0 Y8 S: [" ]$ K# {7 \6 l
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begin P_something arriving
) P6 b& z0 y6 C: E move into Q_wait6 Z2 K6 P3 b+ p5 g0 \
move into nextof(Q_mA,Q_mB,Q_mC) R! @ \3 t; [1 p
use nextof(R_mA,R_mB,R_mC) for normal 48, 5 min
0 i: c1 g2 o4 Y6 t send to nextof(P_mA_down,P_mB_down,P_mC_down,P_mA_clean,P_mB_clean,P_mC_clean)% r1 J7 z6 P+ q
send to die
! O4 h& ]4 f4 h' |+ }end! v: p3 U7 o$ Z
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begin P_mA_down arriving: \5 d, O& m! w: U* `/ b
while 1=1 do , \" m; y; |* V8 `
begin
2 Q/ @7 w4 G% U' y; L) U _& v& Y' U wait for e 110 min
( p& Y) h2 L$ A" m b4 Q' l k take down R_mA
% i, O5 @* D' U# m wait for e 5 min
3 k8 _# u4 n9 v. {' \3 O- q+ @% \) ]0 L bring up R_mA
7 J+ {+ i% s2 ]2 h( l y% C end
3 Q" s9 N0 f5 K& n/ I: B9 \end# C* _( @9 Y z4 W
) j) @" F! v8 L- Dbegin P_mB_down arriving
" d) j. r. H4 f0 p7 j! Z3 \ while 1=1 do& Y, H( b1 g9 b. y
begin% u1 c. G6 m& q- u: E' V
wait for e 170 min; R2 G3 |# `1 Y9 g6 ~: g
take down R_mB
+ t9 @- b/ k: G2 V( Q wait for e 10 min
5 k0 d# I' y8 P0 f# _ bring up R_mB/ c& j6 s: R) ?) [' p1 n9 i; `
end
* E, t. A5 a; @ U% Nend" \% X) V" b$ D$ @. Y
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begin P_mC_down arriving
/ k/ R3 T" |, M/ O* ?4 Y3 u while 1=1 do
! i2 m3 n+ H4 X) X begin
6 W- o/ k! Q' v' |( n& @ z wait for e 230 min
" {" ^1 \, u0 X; r3 w take down R_mC
( x$ k: l6 k2 ?1 i7 z$ g w wait for e 10 min
% N2 M) @3 r. ^( t bring up R_mC* n! o: k- Z& j& q( E, A" Q
end" w0 k) c, J, r* k5 [! ~
end
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begin P_mA_clean arriving
0 `, U" m- _5 O$ E* s while 1=1 do2 w ?0 v% {& I$ ~
begin. ?8 E. m S. {1 x+ ^- O2 s
wait for 90 min' |8 d/ Z Z! S1 o
take down R_mA
8 B% x( E% C5 |" f wait for 5 min
; x& K6 }- m# y3 k( E L: Z# h bring up R_mA
: K, F# X2 v9 [2 Q$ d* V# v8 Z end& g7 P+ y* h" l6 [
end
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, d" P4 s' m% x4 T$ j3 Gbegin P_mB_clean arriving6 ] k. `) b: x% f8 t2 \" ]
while 1=1 do! n6 X1 E/ O+ {0 d# l! k2 X# _
begin- k4 s' r( G3 }6 q
wait for 90 min
" w* r- @. Q; x take down R_mB, E2 x1 a( i/ Y0 Z
wait for 5 min8 F) C F7 u, ~2 k* a
bring up R_mB
( ^( Q) i5 E0 J4 A end
9 J) a8 Q3 b5 Q! _end
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0 K# `& G9 f) @. _9 W+ U) j Mbegin P_mC_clean arriving
" _ z, H2 ]1 A1 B: R8 b+ L ]/ C while 1=1 do
0 ?! ?2 g( r2 H5 r3 i* _9 W3 M begin
# [- z' v4 h/ S$ l ~+ A' l7 `% J wait for 90 min
! I8 Q9 H5 o8 s' L6 ~ take down R_mC! |" Z H( [+ n( ]* m; M1 _
wait for 10 min9 T7 P, o4 f6 l$ l% g5 |
bring up R_mC
1 V8 Q% o0 m- @# V0 s end
C5 h% T9 R3 ~8 l1 c/ ]end
: b2 U& p( p5 P----------------------------------------
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1 X" z! r& p _3 ^Exercise 5.9$ k; a7 d* x N
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' J0 I/ ~7 y' OCreate a new model to simulate the following system:9 }' }$ s' x% o& ~, [* H8 D
Loads are created with an interarrival time that is exponentially
- {9 l, O7 O% \: A' k; Xdistributed with a mean of 20 minutes. Loads wait in an infinite-; ]9 g* I/ f0 W6 p8 |
capacity queue to be processed by one of three single-capacity, . c: F2 N4 a6 ?' S7 |/ f* h- C! O
arrayed machines. Each machine has its own single-capacity queue
7 J: h0 l+ @# Uwhere loads are processed. Waiting loads move into one of the three % }( E( i, G" P2 h
queues in round-robin order. Each machine has a normally
! V% z3 V$ a9 Ddistributed processing time with a mean of 48 minutes and a standard $ o3 P* L3 r! ^* w- O S8 d3 [
deviation of 5 minutes.
7 ^2 e' w' F: z7 d0 N9 S; w5 MThe three machines were purchased at different times and have 4 ?, l/ s* K6 m% X8 ?
different failure rates. The failure and repair times are exponentially $ Y3 _1 s1 m5 c/ f- m, r+ ?
distributed with means as shown in the following table: k) r" i9 I* B. M; c
Note The solution for this assignment is required to complete
: r, |' F+ Z0 E ?( E+ \exercise 7.1 (see “Exercise 7.1” on page263); be sure to save a copy of ! p0 I9 T: N+ P W" _+ t) p
your model.
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* A- ?, N2 J" V7 mMachineMean time to failMean time to repair% ]7 U. k' K2 Q) l2 f9 C
A110 minutes 5 minutes
$ P1 A- ^% I- h* uB 170 minutes 10 minutes! b8 O2 X( I; i+ Q' m5 B( h
C230 minutes 10 minutes/ s5 }) p/ N% w# q
{5 d" v( t( o( N1 n* AThe machines also must be cleaned according to the following
4 j: e( I) T! C0 _- B5 r0 a) ^schedule. All times are constant:
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MachineTime between cleanings Time to clean
1 m# ?. Q- y; |% H" l- Q4 p* FA90 minutes 5 minutes! v+ r# R7 |- K$ w
B 90 minutes 5 minutes
4 t+ O, m) e* I2 \C90 minutes 10 minutes3 b3 O7 Z4 C2 F0 c; K
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Place the graphics for the queues and the resources.
. M) G. H/ x$ D% q! e* ORun the simulation for 100 days.
0 j) V# A6 m& o* _1 ]/ `Define all failure and cleaning times using logic (rather than resource 3 `3 t9 b* [) q
cycles). Answer the following questions:
; b* w% Y# ?5 i5 z8 ja.What was the average number of loads in the waiting queue?
* W* ~' L5 e2 a7 }2 Ib.What were the current and average number of loads in Space?
/ ^, \) s5 p$ _How do you explain these values?
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