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5仿真币
在使用Order List时,当一个order list满足不了order的数量,要用第二个甚至第三个order list,有一段程序,请大虾解释一下,多谢!程序如下:3 _# X, S7 r0 S8 \
begin P_Order arriving procedure, L4 g8 P, U, M2 @8 y1 a! b
set V_NumWanted to 10
( d5 F; j3 @9 @5 W$ G set V_NumOnList to OL_List1 current value) V7 C% ] j) I
order V_NumWanted loads from OL_List1 to P_NextProc
' w7 ?; Z, D8 e0 g' k, y, Y( D in case order not filled
( _& s! h( Y: D* r begin
) F! T& C: w% D& R wait for .01 sec0 w/ S1 y1 R: L" ?4 g+ P
decrement V_NumWanted by V_NumOnList - OL_List1 current value' r5 O7 p4 R/ h; g
set V_NumOnList to OL_List2 current value% ^3 S- m& T/ f
order V_NumWanted loads from OL_List2 to P_NextProc" g% o- H/ Y. q3 C7 d
in case case order not filled% K% i* W$ \8 S3 G( D# r
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7 R4 e1 m2 p( k$ Y0 X% B2 \: c( i我就是不明白上面用红绿色作标记的那句,为什么后面要加-OL_List1 current value.用前面绿色部分,即把不够的load算出来就不行了吗? |
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由于有in case order not filled这句,所以我觉得红色部分应该可以去掉。你还是自己测试一下吧,不一定要按书上说的做。
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