我现在用c++编写了一个程序,希望能够和extend交换数据,以及自动对extend进行一些操作。我参阅了例子里的关于OLE AUTOMATION方面的c++程序,但搞得不是很懂。比如说,c++程序向extend发送一个数据:+ N' `5 } B1 r: R$ ^
Name = (WCHAR *) L"Poke";) U5 u( L1 H5 j. I
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hr = m_pDisp->GetIDsOfNames (# o4 j4 ~7 E9 e4 ]
IID_NULL, // reserved 7 ~2 M3 f- U8 f: A* i( ^ &Name, // Array of names to get IDs for" \ s; {; X( Q _
1, // # of names in the array* g1 W% ~8 B8 E' v- [% o$ ?1 x3 n3 W
LOCALE_SYSTEM_DEFAULT, // System locale 6 q' w8 a5 x4 \0 A* i# ^4 W6 T &pokeID); // Array of IDs to fill on output9 [3 i* ^; L% M1 i& F1 b
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if (hr); X1 p! `" @0 h" Q
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MessageBox ("Get Poke Unsuccessful");1 `6 B* R7 o7 f& }/ C* i# q- U$ b0 ?
return; + E$ l7 u9 h* n6 j5 m9 l } ; V; r6 T) I/ V; r* ]- C4 o% r2 M% D" s) B) x
/**************************传递数据给extend**************************************/ 5 h( r7 I' W* j- H! O" _ pokeVariant = (VARIANTARG *)malloc(sizeof(VARIANTARG) *3);/ Y, X+ f: F+ b& J2 z1 `
8 D( X& K( ^$ F' d, B valueStr = SysAllocString((WCHAR *) L"1232");1 \. V, {: D# \/ o
VariantInit(&pokeVariant[0]); ) c- {" w1 L5 E4 l1 I% V, Q pokeVariant[0].vt = VT_BSTR; + o& \1 s9 Q9 J, {9 r! }' [ pokeVariant[0].bstrVal = valueStr; - w5 W9 `4 M1 G" D5 h Z: Q " o/ B- z1 B8 a: r7 L8 k itemStr = SysAllocString((WCHAR *) L"global0:#0:0:0:0:0"); + R- s5 r8 B. R/ x! ^ VariantInit(&pokeVariant[1]); # i2 D: x! J! A( b5 K& [- A
pokeVariant[1].vt = VT_BSTR; + j+ K3 N H4 Z" v pokeVariant[1].bstrVal = itemStr;) h: f1 V/ b0 ]1 t7 X4 F
4 y. p7 a$ ` T" Z7 t4 ]6 t: I0 L topicStr = SysAllocString((WCHAR *) L"system");$ @$ l1 c: @& s2 L$ O9 O# n. H! [* E
VariantInit(&pokeVariant[2]); % U& a: k* |5 s+ O3 O& s; d1 u+ n pokeVariant[2].vt = VT_BSTR; 6 {; `7 M- L* U4 n0 b/ @9 e pokeVariant[2].bstrVal = topicStr; - S# c7 }* D. c6 J( F+ D( _' g" ]' s+ ^
// Set the DISPPARAMS structure that holds the variant. 8 w+ \0 r. n1 F. {+ I! E, ^( O% F5 C1 U( I5 }1 ~" f
dp.rgvarg = pokeVariant; : X7 {4 }7 Z% D8 m; X dp.cArgs = 3; - U) B1 i8 R% W2 _* ? dp.rgdispidNamedArgs = NULL; + G0 h! O2 ^) X dp.cNamedArgs = 0; 0 x w( ^2 b; I8 J* E3 A) d3 R0 o6 g2 d# y9 M
// Call IDispatch::Invoke()3 S+ H: v* `4 @: E
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hr = m_pDisp->Invoke( 8 n% O% k" p2 \3 D. ?. w; ?: p pokeID,- r+ v7 r# S- A9 T. L
IID_NULL, t. G9 n; A9 ?9 Y L- e5 A LOCALE_SYSTEM_DEFAULT,/ H# V: G& q# o) w1 b
DISPATCH_METHOD,4 y1 H* k h) W2 \( g
&dp, # T: h" f5 R" L& x2 Z& w& n NULL, $ u- o8 b( D/ ~( c5 I- \ &ei,* q4 G8 H% `( p p h7 W8 h5 D. Z
&uiErr); " M* w# ~- R! w) S! j! u% `# b! l h( L/ ~* ?) S: n5 y7 `3 A5 O
SysFreeString(topicStr);- t& G G/ x/ a- @6 e0 z
SysFreeString(itemStr); $ M! [2 |1 x7 m/ t/ z h6 f SysFreeString(valueStr); u; E3 p1 M, P1 `' W
5 E5 m1 A# Q3 o! g现在这个程序可以实现将1232这个数据发送到extend,extend有一个对话框弹出并出现1232这个数据,不知道这个对话框为什么会弹出并显示这个数据???5 Y# ?7 U# s1 Q
此外我希望将这个数据赋给extend程序里面的一个变量,请问如何实现????- d& J( l) Z! j. }. Z
6 h/ W) z! ]3 i % S0 \5 J; G( Z$ Z2.这是request的程序8 Z! q' F2 _# J6 |7 ^# s9 h
// Request a value from Extend) _) T& I9 J4 M- h4 `& d1 |
// : G' i% ?: e( G! Y// Initialize the variant that will hold the BSTR. Set the variant's ) h" Z% x# W, S/ o// type flag to indicate the fact that this variant holds a BSTR. Place the " N" t( k/ D5 X# g6 n' R2 \// BSTR into the variant structure.% y8 U. Q3 r' _$ \. E1 T
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requestVariant = (VARIANTARG *)malloc(sizeof(VARIANTARG) *2);' ?4 n. w1 c% p* o R4 D
2 M. H8 c6 q! Z. `6 A itemStr = SysAllocString((WCHAR *) L"global0:#0:0:0:0:0"); % U: D; z3 j: n VariantInit(&requestVariant[0]); . @5 L: z3 G. U' H& \ requestVariant[0].vt = VT_BSTR; - K1 g1 B" |1 l J8 @% [/ t0 } requestVariant[0].bstrVal = itemStr; V/ ~; @4 u1 V4 h4 D
" t7 Z* r% m8 c' {5 v% {- z topicStr = SysAllocString((WCHAR *) L"system"); 8 j( T/ O; z; y1 `: D9 V VariantInit(&requestVariant[1]); , y9 Y$ H: |0 X( K requestVariant[1].vt = VT_BSTR;- Z5 H; s0 g* r9 N' ?& H- E
requestVariant[1].bstrVal = topicStr;: I& a" d& f' D- X/ n2 G
; C$ e9 l( e' O! q4 [// Set the DISPPARAMS structure that holds the variant. # ]) P1 \2 z0 H) ~ & Q* x% \6 p+ [/ {/ Q" l: ~ dp2.rgvarg = requestVariant; r: d; n, Q" [/ |5 d dp2.cArgs = 2;" B% l4 v+ b5 K
dp2.rgdispidNamedArgs = NULL;6 l- K& F- R6 ^. y" _
dp2.cNamedArgs = 0;) o. m# B. D: n, z. ]