6 p# z, J, T- s' A valueStr = SysAllocString((WCHAR *) L"1232"); ! u! L" T, d; g$ P1 {. K p( S# F VariantInit(&pokeVariant[0]); , s% G( {# N* o+ w6 L6 F
pokeVariant[0].vt = VT_BSTR; |4 E6 d" c! R& @5 r- S
pokeVariant[0].bstrVal = valueStr;* _ z( e' _8 V" B6 [) [9 N
0 b: `1 \# R( @5 S, J5 P itemStr = SysAllocString((WCHAR *) L"global0:#0:0:0:0:0"); 0 z; a1 X I7 Q. p4 I+ _+ Z VariantInit(&pokeVariant[1]); 0 h! }- F4 c/ Y# B2 d' h* X
pokeVariant[1].vt = VT_BSTR;: R& S3 e9 V" }7 x3 Z
pokeVariant[1].bstrVal = itemStr; 8 m/ d7 H# y$ ~6 J& C9 G& X! `/ a8 X- z% M, J' U, l
topicStr = SysAllocString((WCHAR *) L"system"); m7 s+ k+ E+ l+ g" P$ D( n5 F
VariantInit(&pokeVariant[2]); ' v# d8 z, d! b3 n0 o9 Z
pokeVariant[2].vt = VT_BSTR;( I% f! l% O& C* Y, F# z6 R* R
pokeVariant[2].bstrVal = topicStr;- Z; x( G" M5 {
- ^% Y. ]1 c# \+ F/ Y// Set the DISPPARAMS structure that holds the variant.& p9 j. h3 B% E! c0 R! n
8 `0 t$ A) y; r! [0 b) f4 y
dp.rgvarg = pokeVariant;- V5 K8 o R+ E* j
dp.cArgs = 3;3 ^7 o/ t: m& v
dp.rgdispidNamedArgs = NULL;, }1 X* `# v6 g5 p2 \" Y
dp.cNamedArgs = 0;" P+ U2 m1 k7 M F4 w1 H
/ J: o' w, h$ o// Call IDispatch::Invoke() & o! y/ r0 V0 O0 S5 W 8 s0 z7 m/ g7 v% }& s hr = m_pDisp->Invoke( - E$ m8 k3 A1 `. V pokeID,) ~8 Z, l1 d. i6 d3 B) n/ C
IID_NULL,+ i3 f2 U3 X$ h/ @9 L' p, r
LOCALE_SYSTEM_DEFAULT, 1 E3 b9 P j- v+ D DISPATCH_METHOD, " q( Y2 D5 _8 F# q3 }, o5 P3 e &dp,* ^9 I7 O' R! S. X6 ~
NULL,+ E- Y: S4 B* ^+ Z* g2 T5 N# y
&ei, 2 `% `. B! U5 f( m" q! G/ u* y &uiErr); . t5 X% A- e0 A: d* _ 9 W5 V/ `2 d4 g2 } SysFreeString(topicStr); 3 c. V1 S+ h9 b( M) \! r& e$ F SysFreeString(itemStr);, {! A; V) G/ A- i0 X& g2 |
SysFreeString(valueStr);" H" y+ [0 Y5 E2 @% ~1 q' y% l Y9 c( A
- i* I+ Y+ r1 e. t9 G, y+ j7 a
现在这个程序可以实现将1232这个数据发送到extend,extend有一个对话框弹出并出现1232这个数据,不知道这个对话框为什么会弹出并显示这个数据???3 t5 h1 _$ Y. }% ^7 C Z( C" K
此外我希望将这个数据赋给extend程序里面的一个变量,请问如何实现????# A) f4 d9 I+ h- ?# Q- f5 z! O) a
3 t. Q+ ]( a+ ^7 s* W" h
) o# H- D! [' t4 U0 J V
2.这是request的程序; s1 [% f1 @1 ~3 H) ?7 K& {: ~
// Request a value from Extend: X) D1 P1 ]5 c/ {& w- B
// 5 Y% d0 {2 v X2 r$ r) v// Initialize the variant that will hold the BSTR. Set the variant's ) l6 P! o- {% k! J% f# T e2 L// type flag to indicate the fact that this variant holds a BSTR. Place the4 k I$ ?' e5 X9 S5 _+ a! Y
// BSTR into the variant structure. 0 ]# \2 i ~6 u! _0 d* _7 m6 e! s& y, Y. E6 x
requestVariant = (VARIANTARG *)malloc(sizeof(VARIANTARG) *2); % j Z2 r6 B/ ^- o0 z3 G7 o8 f " ^6 d9 P, F: E3 ~, O itemStr = SysAllocString((WCHAR *) L"global0:#0:0:0:0:0");0 z8 f8 g# w1 S
VariantInit(&requestVariant[0]); 0 s2 E( A6 E: H% F requestVariant[0].vt = VT_BSTR;) a8 j {2 `( Q. X# T& ?' ~
requestVariant[0].bstrVal = itemStr; ) e. P9 b' O- ?% L1 }0 b+ ^9 B, p( w2 A% C, }
topicStr = SysAllocString((WCHAR *) L"system");' ^ B' U8 ]; q
VariantInit(&requestVariant[1]); 4 S2 H4 w$ L$ t& c- \0 g
requestVariant[1].vt = VT_BSTR; # y" b( A$ H2 L6 y. ?6 f9 n$ M requestVariant[1].bstrVal = topicStr; % H" _9 O+ R- y9 Z4 W7 Y. B$ f' a, R2 }( H. N& l9 i/ z
// Set the DISPPARAMS structure that holds the variant. ; e. _% {. I1 f# l( _7 J, _/ [( p 5 g9 t+ U# j; }& V dp2.rgvarg = requestVariant; 9 \ G+ j8 f& S! _" v! A& K2 r" Q dp2.cArgs = 2;9 ?; ^4 e7 y3 J! K
dp2.rgdispidNamedArgs = NULL; : [+ j! Z1 G) p4 w$ @6 R dp2.cNamedArgs = 0; " ^0 c* {0 t1 l2 F) y0 y# o+ M: X+ t8 Z/ |* ^8 \* b, s
var.vt = VT_EMPTY;: H" x5 J! K8 U; R$ P" K
- `) ^8 y. b2 j( ^& S( ]// Call IDispatch::Invoke(): Q& W# a" o: h( \5 e; p4 M; e1 G: o
! x4 N4 r3 D# H/ R: b+ K; e hr = m_pDisp->Invoke( / l% ~$ ]4 { l9 @8 c' _* R requestID,; B6 d' Q# M6 E$ g8 ^
IID_NULL,( k. B3 l' c3 d+ M/ p6 E0 y
LOCALE_SYSTEM_DEFAULT,4 K, {( g0 A2 t1 a& }( |
DISPATCH_METHOD,% w6 A% _ u3 A ]$ u2 _) ^
&dp2,% v8 d/ ]/ w( Z. x7 Z0 [+ V
&var, 6 f4 d& i* l1 p# v$ Q1 G &ei, 9 U% |1 e7 k( n' Z9 j+ W &uiErr); 2 q; n7 I& L$ A1 N! M5 o# F 7 V7 e7 g, g( K% P7 T: i SysFreeString(topicStr); : y0 @* H$ X8 ^ T SysFreeString(itemStr);- ^; C' j7 a$ X: D: j
请问该程序是获得extend里面的哪个值?7 K1 l8 X+ c% B& |$ b
如果我希望获得extend程序里面的某个变量的数值,那个c++程序应该如何实现????