HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:) h' q! E3 l, q% r' y
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public Object buildActions () {
8 Q+ g8 {" s5 D$ ~2 Z7 p- N. V super.buildActions();" {8 j: \6 W! Z; p
& X7 o3 {; A& g // Create the list of simulation actions. We put these in
) X% g, h/ R6 X4 a: y // an action group, because we want these actions to be
7 G9 F- f, m2 y4 k // executed in a specific order, but these steps should
. x; @6 |/ f3 a, v$ p0 ]9 C& x // take no (simulated) time. The M(foo) means "The message2 Y2 N! I7 f9 F F
// called <foo>". You can send a message To a particular
6 m9 G2 s7 w& K6 }3 A7 \ // object, or ForEach object in a collection.
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// Note we update the heatspace in two phases: first run2 v) Z" P+ b X8 `) v8 [
// diffusion, then run "updateWorld" to actually enact the
$ B O7 C) w' m( V- ^ // changes the heatbugs have made. The ordering here is
5 K! K. y* ~, \9 N# [ // significant!
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// Note also, that with the additional
5 p+ S5 t+ Q5 [/ ~ // `randomizeHeatbugUpdateOrder' Boolean flag we can
' }0 _$ Q( V" k) k // randomize the order in which the bugs actually run+ M8 q3 o. M2 w8 L
// their step rule. This has the effect of removing any
, ~0 \$ c ~" g# n0 g# h // systematic bias in the iteration throught the heatbug
" b+ z9 t- Q* O: t8 q // list from timestep to timestep
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// By default, all `createActionForEach' modelActions have$ E0 O( @- S( [1 c8 e% V
// a default order of `Sequential', which means that the$ H/ r4 K' O2 q# N
// order of iteration through the `heatbugList' will be- }1 _. R8 S; F3 \
// identical (assuming the list order is not changed! E5 ?. f4 E2 k4 w
// indirectly by some other process).
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modelActions = new ActionGroupImpl (getZone ());
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try {
# H2 ~7 X, ~2 e3 K$ c modelActions.createActionTo$message- f' `, |6 P$ Q
(heat, new Selector (heat.getClass (), "stepRule", false));$ w/ T0 `. v3 Q$ o
} catch (Exception e) {, R1 k) Y* J; V/ [% N' G, I
System.err.println ("Exception stepRule: " + e.getMessage ());
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9 f& f* T* E/ T' T1 F try {
" s+ {6 e6 P8 F8 I& ^# K6 V n Heatbug proto = (Heatbug) heatbugList.get (0);
: G" B: C% o5 b Selector sel =
5 l. j6 {6 F1 Q/ ]: _; G new Selector (proto.getClass (), "heatbugStep", false);: R, }! }: |! e
actionForEach =
* H0 P9 b1 @+ J$ Y# h/ L modelActions.createFActionForEachHomogeneous$call8 v. S; L5 a% K0 e1 D
(heatbugList,& p! D" o: U8 s+ t2 T5 H
new FCallImpl (this, proto, sel,
& e& L' ]' Z8 B6 f' t+ x# { new FArgumentsImpl (this, sel)));/ T, o/ {5 Q, |* w% Z4 k
} catch (Exception e) {
% M. P( o! g; R8 H e.printStackTrace (System.err);. r8 h2 P2 z4 l- y1 f$ Z9 R
}
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syncUpdateOrder ();) j) G. \0 b- n& W; `8 l% Z
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modelActions.createActionTo$message 0 a0 a! ]' E3 T$ w2 O; h. m$ j( u4 \
(heat, new Selector (heat.getClass (), "updateLattice", false));& [6 t; W$ A( t8 z2 S7 q. O5 l
} catch (Exception e) { @0 u! u( P. f
System.err.println("Exception updateLattice: " + e.getMessage ());
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// Then we create a schedule that executes the i3 M3 P+ z" D
// modelActions. modelActions is an ActionGroup, by itself it. v+ ^( H8 q: H, j
// has no notion of time. In order to have it executed in; e( y# B" i5 n( t5 D+ V
// time, we create a Schedule that says to use the
5 U0 v l t `6 H$ b% l // modelActions ActionGroup at particular times. This1 M$ x3 k0 j/ ?8 V
// schedule has a repeat interval of 1, it will loop every5 U# E: q# z# ?" R
// time step. The action is executed at time 0 relative to
! Y6 p* h4 @$ ~$ t( | // the beginning of the loop.5 y% m: b+ s) i4 g) E7 c
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// This is a simple schedule, with only one action that is
% ?; e: A( e3 X7 K // just repeated every time. See jmousetrap for more
: P0 {& m2 _ w2 h. n8 i // complicated schedules.
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. H0 Y0 L) O. a" `8 _, F modelSchedule = new ScheduleImpl (getZone (), 1);9 R3 C0 s" z) ~! f. |. e5 j
modelSchedule.at$createAction (0, modelActions);
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4 r; `" c1 k) Z9 o7 ~ return this;
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