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楼主 |
发表于 2008-4-19 16:11:18
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好像可以了
to go
1 s: B; z i4 |. {1 E, l7 c- q, [7 o set t t + 1
( ^4 j. R1 k* B7 t/ G! w grow
9 c, b7 G; H) J9 d! v# K update-list-of-m
' E9 v, @! M1 {! M do-plots
+ p0 R1 R& X. x. Z: f* D tick $ {- {2 a7 J* Q6 Q: g8 [
ifelse t > 8+ L- o+ e! M4 L; C
[if abs( mean (list (item 0 list-of-m) (item 1 list-of-m) (item 2 list-of-m)) - mean (list (item 3 list-of-m) (item 4 list-of-m) (item 5 list-of-m)))< 0.01 and
& @" Y" @: \2 z( e( b4 u abs( mean (list (item 3 list-of-m) (item 4 list-of-m) (item 5 list-of-m)) - mean (list (item 6 list-of-m) (item 7 list-of-m) (item 8 list-of-m)))< 0.01 and
0 w, q. `! |& t+ \- u abs( mean (list (item 0 list-of-m) (item 1 list-of-m) (item 2 list-of-m)) - mean (list (item 6 list-of-m) (item 7 list-of-m) (item 8 list-of-m)))< 0.01
9 S8 O+ X2 U8 \2 B x v C [stop]]
" ?& s' ~8 A8 f! b, O [ ]
# L4 a' q7 ?- kend
5 N% f" P1 t6 y* Z5 x各位大虾帮忙看看,这样好像可以了。以前用while之所以不行,是不是因为如果报告为true,那么就会反复运行后面的命令导致死循环啊?
: B: w3 a7 N" v- d还有就是[ ]是不是意味着不执行任何操作,返回set t t + 1,然后再grow,再 update-list-of-m,再 do-plots,再 tick ..........这样一直按这种顺序循环直到停止。% ]$ Z0 {5 V; V8 }7 E, ^8 t( S9 C
: z7 s& f5 h$ g0 r- R7 K# Y. O
[ 本帖最后由 wjcpcahu 于 2008-4-19 16:19 编辑 ] |
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