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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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不好意思,打错了个字母,呵呵呵!3 ]& F7 G1 ]. @, j9 k
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示$ S0 g' b: }7 o% s- N3 l- p2 I/ q9 H
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!6 m. D+ W& M: n( W( L) U
is
: |2 _3 x' ?: e7 E6 b j,k,nstep,c, scheduleteps,mincomptime:integer;6 {1 p5 h1 N' Z6 V% }
M:string;1 W- k* f# J0 b& X: ^6 ^' T
selecTab:table[integer,integer,integer,string];
0 [; Z% f" R7 t4 T" S" {do
( ?0 Q& s& I+ F. v* n initorders;
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scheduledorders.delete;
; `* ?- V/ a: B1 i seletTab.create;) | l. e5 J, j1 ~* w
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orders.initialize({2,1}..{2,*},0);. x0 o- `% N8 W: _
orders.initialize({4,1}..{4,*},0);
# N; K g z3 u( f: `- m& I1 E for j:=1 to numorders loop
1 R1 D4 ?3 M1 f8 u G orders[5,j]:=orders[1,j][2,1];
* J3 N8 ^$ {0 m5 U; t/ h' q% ? next;
/ Q9 E3 ~0 v" N! ?$ c& `' V occres.initialize({1,1}..{1,*},0);
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9 w6 t3 l+ z- n" [ --XUNHUAN4 d$ T- G! L _2 N) p# \
for scheduledsteps:=1 to numsteps loop --
2 H% o' g" m Z selectab.delete;5 h1 E( H9 ^0 B) ~4 N, z
k:=1;" p T K) X: Z5 G, B
for j:=1 to numorders loop
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nstep:=orders[2,j]+1;
+ Q! y7 d. g+ L if nstep<=orders[3,j] then
8 C' p5 B. F4 `* t0 n4 _( o: {3 F selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
/ K/ m$ i# f" b! u1 V: r f k:=k+1;
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+ c% ]" q" M" L, e end;1 P" z4 b5 W" ?- ~
next;
7 x/ d; o. H5 O mincomptime:=selecttab.min({3,1}..{3,*});
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5 F4 v- s: X$ C3 |; j! U from j:=1 until j>selectab.ydim loop
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% G# O# H9 P F/ C! D if selectab[2,j]<mincomptime then! {7 u! z3 e4 y" O- z/ H
j:=j+1;
/ R4 P+ e# J: P7 ^ L3 J; E else
8 A5 O+ X7 z; B$ U* ]$ L$ J1 f selecttab.cutrow(j);' U) F6 y0 }" u8 t
end;
7 W3 F1 }+ A/ ~1 {: C end;
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& Z( ?4 B: [: }/ M8 s j:=selectionrule(selecttab);; S7 G) i, G l$ `& F9 k. r
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nstep;+orders[2.j]+1;
3 ~$ D' ~7 i! v Q orders[2,j]:=nstep;
0 h( H) w' ]4 t& T( @! K8 I6 F; | m:=orders[1,j][1,nstep];$ s2 O4 Z b, W6 Z9 y/ P- r
c:=orders[5,j]0 X, @& W% U/ \$ `+ H3 r \
occres[1,m]:=c;
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--jieguo:start,end,res,job,step
% _8 K/ x; { {1 A; i scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);8 Z; P F- ~6 e' Y
for k:=1 to numorders loop6 X3 e. U% g) N
nstep:=orders[2,k]+1;
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m4 l2 W; g5 p- v
--
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orders[4,k]:=max(c,orders[4,k]);. l: `! e4 @: K/ D3 z$ m
--3 m8 A! o6 j3 N- M. o/ ~1 S
orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
' s5 o+ I1 h& W/ a, i: g3 j2 k --
5 L8 G6 D( T" h7 K' c" @! g end;
/ m$ h8 u5 A# h7 [2 B0 K7 | next;/ c' L7 @$ {# R
nstep:=orders[2,j]+1:
, N6 Y# n& G( Z) A+ x2 j6 [ if nstep<=orders[3,j]
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- T4 h- r% C- `' _, b then
+ }6 G/ ?0 C4 _3 Q; B5 }7 k! q orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);3 l4 a1 f1 O$ P1 o. i
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
9 b# b1 u+ B/ o( Y end;5 c& ?4 u, A w7 a2 n& U
next;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
: E' O9 c) z" Y5 v4 G! L mygantt;
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