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本帖最后由 soso001 于 2014-12-17 14:53 编辑 8 T9 z6 L1 S9 {) b& x8 }1 V5 O% S2 m. y
: _( L; Y: W; U! m {' E( h/ E不好意思,打错了个字母,呵呵呵!
4 m- B6 T$ {1 H大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
?0 \- y9 v, j$ V$ c' F e“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!5 `% X+ o$ `7 S" }
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j,k,nstep,c, scheduleteps,mincomptime:integer;
2 q! l: D9 h9 `7 V; ]6 d3 [ M:string;
% R9 L; h/ K$ @% y- y3 j% y selecTab:table[integer,integer,integer,string];
6 v6 c2 K; G( O" m; g& V5 l4 `do
3 A$ o7 L* u- _ initorders;
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. m1 t4 U$ y6 m0 s& j& a% F scheduledorders.delete;2 Z6 l; l) Z4 E- t r) Q
seletTab.create;
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orders.initialize({2,1}..{2,*},0);
/ m, l* z2 E* y7 y* ] S/ @: m* v orders.initialize({4,1}..{4,*},0);
8 k8 r8 E4 i2 S' C7 E6 | for j:=1 to numorders loop) d: ? D; q6 J1 r' f
orders[5,j]:=orders[1,j][2,1];. S8 ~2 ]1 h9 z' j. T4 p+ ?
next;
* G4 |1 u: S+ Q+ U occres.initialize({1,1}..{1,*},0);
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--XUNHUAN- K4 e$ {5 c+ |2 `
for scheduledsteps:=1 to numsteps loop --" Y5 P6 |- l* U3 s7 w" R! `
selectab.delete;; F G4 ?% `- N- e: D
k:=1;+ x/ ]2 n4 Y) E+ [
for j:=1 to numorders loop
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nstep:=orders[2,j]+1;0 \1 n1 A; i, A. V) g% F3 r3 _+ h
if nstep<=orders[3,j] then
' X+ l; c/ n5 h0 T4 `! B selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
0 D- G7 R K* [7 W, v8 R& A k:=k+1;1 E- A3 s) y7 A
+ Q$ r6 v+ ~0 c. Q* } end;
# _/ J, \& ]2 D3 [ next;
8 C3 B2 A" ?1 m2 m% s! ` mincomptime:=selecttab.min({3,1}..{3,*});
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from j:=1 until j>selectab.ydim loop
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3 _6 T& G3 }: \8 s if selectab[2,j]<mincomptime then
) Q) c+ b, @ Y. i9 V5 G j:=j+1;, T7 I, T: ]( u; E$ I$ c9 w5 ?
else6 @9 h( R" I( \" a* h2 z6 I3 J
selecttab.cutrow(j);% b" B6 p2 f- u+ i! j2 s2 l
end;
! g+ C8 v, C' u- C1 V0 e end;
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j:=selectionrule(selecttab);. f9 t) d, c5 v4 o
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nstep;+orders[2.j]+1;
1 { Q a, q, k& A orders[2,j]:=nstep;
$ u P7 T" ^! z m:=orders[1,j][1,nstep];! i7 Z7 q0 n2 L/ o4 B' M; H4 l& V
c:=orders[5,j]
( X; U1 R+ ~' K7 ^5 ~6 P occres[1,m]:=c;
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--jieguo:start,end,res,job,step' _/ R' l1 j) J% m3 q$ w
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
" Q6 B& z- d0 M9 `/ W for k:=1 to numorders loop4 r/ q I8 A; b
nstep:=orders[2,k]+1;! O! D2 ^ c6 r3 y4 f$ a: f. H
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m/ J V! z) r( T
--
, q$ _$ M8 T" ]& {. v then
: J3 t- r1 v& ?! J* ~. o5 r orders[4,k]:=max(c,orders[4,k]);
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orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
1 A1 z5 y6 f8 |4 l7 w6 @6 ` s4 | --
8 X, V% a) F( n, ?1 ^- w. B6 d end;+ M7 @8 x+ ` `9 v$ v
next;3 z, j) ` k7 u7 R; P, X
nstep:=orders[2,j]+1:* M4 I. I% O' u) E# O
if nstep<=orders[3,j]
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then
/ i9 Q; b0 U0 B orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);+ _1 d4 S& P5 B; \& b& N4 k
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];) T. a8 }* I# [ _4 P0 l$ Q! e) D
end;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
* ]3 G% A& G# A( I% } mygantt;3 L9 r, V6 M0 s2 A' c2 w9 h
ens;
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