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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
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+ P; q" v# k1 B/ i% `我今天遇到一个问题,请问你知道如何把来自两种不同的load1和load2在一个机器上加工,合成一个load,该如何使用order命令?我每次运行的时候,给出的报告里面资源机器Massm没有load经过?以下是我的程序:6 V, M& E6 c, B. B7 ~3 C" ^
begin P_in arriving9 ?# J& t# t4 p8 X
move into Q_in; N$ m: G3 T8 S' z) v3 B& M
use oper for 2 min
/ P% y! j% ~/ F2 c send to oneof(0.95:P_in1,0.05:die)2 ?; K- f5 w" j! K e9 x
end: A& u& K5 c3 [" A6 k# Y
begin P_in1 arriving4 f3 q, _, {! ^: L; E. B
if load type = load1 then- `) U2 [ P2 K% I/ W1 C
begin' ~" e4 p7 F1 T8 y* X1 u* m
move into Q_m1- }; r. q$ q0 f$ K7 @" R
use M1 for u 5,1 min
8 M. c+ g5 a/ J1 J8 a( L move into Q_out1
* Y3 S. S9 O3 i; E( M& A( v wait to be ordered on orderlist OL_12 S0 s$ x8 J V" Q
end
" g s0 ~# p3 K if load type = load2 then C. O7 Y8 [5 a" ?& `
begin6 l6 Z# ~. M% z4 l" n- T; _
move into Q_m2: k! `! t( x4 B! s
use M2 for n 8,1 min U% X$ v) w$ L+ e9 F' A+ c8 x
move into Q_out2
' _ H, Y. h* T9 [& M wait to be ordered on orderlist OL_2
( N) i5 u8 G. \ end R* v+ V8 p) o$ ~
end" o% F/ i0 v7 c& `& N
begin P_dunmy arriving3 L8 D# F$ |( r; {2 M
set i = 1, E: T! T+ {5 ]; U
while i > 0 do
8 l. R" H/ _, T" x0 E. | begin / U# U' S0 E( o4 z5 }% p4 o& E" A y
order 1 loads from OL_1 to die
6 d- L, j \# G; X7 W3 ^+ Z* X in case order not filled backorder on OL_14 O" W A y( q/ e- w; d' w
order 1 loads from OL_2 to continue
4 H& q3 L9 u. a" G7 _ in case order not filled backorder on OL_2% U9 D0 E' {6 N7 k3 y. r
move into Q_1
6 B3 ^; _2 V- @1 _0 V4 x use Massm for n 5,1 min3 r w$ R; l/ m q
send to die
4 v* \; P+ F1 s' F0 Z* |7 u end
6 ?( @# ~5 T5 n T3 d) ]- uend7 F$ K* T& p- C/ S5 C5 J% R
这是我的报告
6 q! ?( N1 s6 I: I" L7 H*** AutoMod 11.1 ***
! T$ f& {) d4 _& e( @ hModel q* x5 z) V) q2 N; M9 E# z
Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00
0 Y* f* a; a4 \3 l" fCPU time: Absolute: 42.859 sec, Relative: 42.859 sec: W9 j7 o- | |3 T4 a: H Y
Statistics for Process System "q"
n: U2 O( R6 P+ o$ hProcess Statistics
9 j+ X! ~) R- O, m$ O0 xName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
% U4 w" @* L2 N* d========================================================================================
$ a2 m3 u+ ?6 t! ~( GP_in 222 1 0.32 -- 2 0 -- 126.04 --/ d6 l. X% F/ u' y" P/ I0 @
P_in1 212 210 102.38 -- 210 0 -- 41725.92 --2 a3 X! o# I8 N8 @4 \. ], B
P_in3 0 0 0.00 -- 0 0 -- 0.00 --" P, Q s8 q D) O0 }5 @1 M
P_in4 0 0 0.00 -- 0 0 -- 0.00 --5 p- t" y9 D* e& ^3 W
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --/ k8 w* W# L' w- U! N+ r
Process Traffic Limit Statistics
# G3 h! q' z0 SName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
; e& l `* b& y! {9 X========================================================================================- u+ J: w7 _. W0 U
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --
$ u4 E! u9 _2 F' n* d/ v4 sP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --9 h8 N( m+ q, a( O9 L5 G
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
. d9 x" s! o- y6 W6 l3 pP_in4 0 0 0.00 Infinite 0 0 -- 0.00 --6 ?" U& @2 ]# a! j( j
P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --/ g& J$ g6 i3 y& g$ F
Queue Statistics: n- T5 Q4 U) y2 o/ {6 j: h
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait" Z- L2 d9 K7 t' `$ A2 x: a
========================================================================================
# d5 i) x; _" H( {Space 223 0 0.00 Infinite 1 0 -- 0.00 --: {3 f9 E1 f; y
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --
: q8 m5 Z* G% ^' x* ~Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
1 N# [$ \: h8 c. E7 mQ_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
" V6 K8 X: t/ ^- T6 p9 N3 P# v* vQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
. O9 @( s/ j; b5 M; A9 wQ_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --
/ A) M9 G6 P6 _4 m, J" w) `Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00
0 o( v2 E" x6 M9 B' h) b AOrder List Statistics
/ `$ `# g6 P' e9 h" d) m! EName Total Cur Average Max Min Av_Time Tot_Back_Ordered
6 E3 t( j: T, J================================================================================/ n3 D8 U5 ?) J
OL_1 139 139 67.23 139 0 41789.43 1
9 w; ]9 C8 X$ s6 Y* v. T. a9 [) UOL_2 71 71 34.26 71 0 41693.20 1
1 e7 p+ s- D4 h% _Resource Statistics) `4 C) p8 M _6 S* A! J
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State 3 z8 ]' F" z+ L
====================================================================================================" A# N( _' U L: {; ^$ ?8 K5 D
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- % N& \; H- o$ ?2 V; @
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- 9 @' c" B" e( J2 _! @
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ---- 9 a) c2 ~1 s9 z8 E0 {* a* }( t
oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
4 y; }: u6 b# `- {. P. kRandom Number Streams
0 g( Z9 i/ v; |/ j. o; m1 ~Name Total
- P |7 N1 x" `; `, m* f============================: z! A8 x' o5 g# v) s5 d8 J, }7 N! {
stream0 455
* G: H4 Q5 t, t4 L9 _stream_M1_1 0& R7 r4 \7 o1 x6 r
stream_M2_1 0/ M, o# y; ^; Y1 {7 J
stream_Massm_1 0* V) e* Z$ F, n6 n: l+ Z, `8 G
stream_oper_1 0
& h; I" z' G7 _" q0 m& Jstream_load1_1 184* v9 _8 Q! ~) J& t6 E
stream_load2_1 76
! [4 n7 s _# }5 ^) }- C2 Zstream_dummy_1 0
7 V( |( @8 F8 b# {5 @" j0 u, m5 ?6 Z; V) a, l( q7 q3 }. {
请问我的错误在那里?我用的版本是11.1的学生版 |
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