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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 , L6 z8 L* J/ |* z! G" ^3 x
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我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：
2 N/ M( E6 ^3 V1 W0 k/ `" Hbegin P_in arriving8 e3 J3 @9 m9 R
move into Q_in
5 `- i( Q2 Q. X& A+ M: W9 Q# l9 v! S: b use oper for 2 min7 Z" S& _$ W) }3 P# Y% y; a& X
send to oneof(0.95:P_in1,0.05:die)
: U6 n( \" d7 k {% Tend
! c9 q# R+ F) F; p+ o% y1 ^2 obegin P_in1 arriving
' }- y8 Q& s' u: q4 D5 d# k5 s if load type = load1 then& Q7 i) N( x# ]
begin9 q8 u& S+ m2 G$ L8 g4 C5 H/ ]
move into Q_m14 k+ \& w: J- E
use M1 for u 5,1 min; w: m& o8 R5 e: C$ O
move into Q_out14 J8 r/ k3 j) N# e8 [
wait to be ordered on orderlist OL_1
( i7 U9 V$ @# B6 f end( u. N& i* e& a0 I! X* d
if load type = load2 then
- F& r8 _8 x% n; r. G begin
$ m: ^. ?, w* m/ } move into Q_m2! g. H! N3 z) J# K: ?. r
use M2 for n 8,1 min
! b; T. l- G% s0 Q3 I move into Q_out2
7 d) e$ u9 A: K% U% j; w& m' k1 P; y wait to be ordered on orderlist OL_29 R- a8 N4 x) Z3 G4 b) _
end
; ]5 v* @ ^- g6 A mend) A6 o, X6 g/ k3 p6 e0 T3 i
begin P_dunmy arriving7 I6 a) P/ A6 ~
set i = 1 U9 W, u- @% }$ _) m: @8 j) K
while i > 0 do' r; Z: e+ `5 e3 M5 A+ Z
begin * |: n" |8 y1 i" R. _3 j
order 1 loads from OL_1 to die
3 e, }) D P$ ^- c- p* X: Z in case order not filled backorder on OL_1) X/ c- W1 l* a, T" `, W4 N+ i
order 1 loads from OL_2 to continue
4 q% y9 f2 N0 u* z6 w5 X& Q! w in case order not filled backorder on OL_2
8 k$ s! y8 C2 ^1 Z move into Q_1; Z8 q- m" B* n0 R0 H" {( y
use Massm for n 5,1 min
8 t$ ?7 z/ W4 m! `; _: B send to die
% v. Q, W' S1 J" V* t/ T0 w2 D0 _ end. g! q: C+ Z7 D! X5 t$ |7 y
end. ]4 o8 Y& p# D* ^9 x) Q
这是我的报告
2 t3 L9 d' m* q& {*** AutoMod 11.1 ***, X) U& C; [! o/ r0 _
Model q5 k s3 X/ i1 |, p" V7 b) S7 P
Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00
j) k0 E: i9 c( ECPU time: Absolute: 42.859 sec, Relative: 42.859 sec
( O; q' [9 Q7 Q( j9 T+ X j8 DStatistics for Process System "q"
+ N, v' o0 Y( A# D/ {Process Statistics
5 ]% v; C. Q( H6 U m jName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
; M, [( ?8 [; x1 J3 E8 \========================================================================================4 z9 l$ O# ` A% W( x
P_in 222 1 0.32 -- 2 0 -- 126.04 --$ X4 _4 s6 [ X* A* d. t/ y- j# b/ F! U
P_in1 212 210 102.38 -- 210 0 -- 41725.92 --9 F( e8 B1 w; O
P_in3 0 0 0.00 -- 0 0 -- 0.00 --
) O6 g2 q6 D. fP_in4 0 0 0.00 -- 0 0 -- 0.00 --
" t/ Z5 E* \: j: f/ P9 |P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --# m5 r0 ^$ c* l* O4 t
Process Traffic Limit Statistics
8 K/ q2 j2 D0 M; e/ h) HName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
* @0 b9 C+ F3 C. S7 X6 W0 V- V( ?% L========================================================================================4 q7 ^' M8 l B r" W6 y
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --/ U5 C' p9 a' H- ?1 j4 q
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --
- g5 l& U- [ rP_in3 0 0 0.00 Infinite 0 0 -- 0.00 --7 E" z, r( P% [- A3 X$ j( U. _
P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
5 |, d" r" w' d) W2 Z6 |4 c$ jP_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
4 s: h! A# l8 W+ g9 cQueue Statistics
2 z9 g4 u! h9 B' ~: a: H. U' UName Total Cur Average Capacity Max Min Util Av_Time Av_Wait3 _& k" X7 w' ^
========================================================================================4 G" a9 {2 c3 v; |
Space 223 0 0.00 Infinite 1 0 -- 0.00 --- w# Z5 r1 M/ q% s+ I) {& Q" i- ]
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --; A1 p: M- n+ R6 p- e) K
Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
5 d7 {: M$ s2 xQ_m2 72 0 0.40 Infinite 2 0 -- 485.61 --. s6 g: E& V9 o
Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
5 y# q: {5 u3 S4 _9 X: D7 jQ_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --' B: J' X+ G$ c. b$ C2 |
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.009 B, @; G6 S' C$ K# L9 G+ k
Order List Statistics
; k+ i, M$ B( J/ q- g7 r3 J6 EName Total Cur Average Max Min Av_Time Tot_Back_Ordered1 k+ D6 ^9 P) D$ }1 f
================================================================================/ Q( x% V% {/ a' \- t; z) u
OL_1 139 139 67.23 139 0 41789.43 1, v1 L* Z2 R6 Y& T4 N
OL_2 71 71 34.26 71 0 41693.20 1- x3 }/ k1 M* d: } S+ X
Resource Statistics+ T3 `6 G, @, D) O, K: f' F, {$ D& }( S
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State ( ~* L! y7 ~ `1 u1 U$ z/ @
====================================================================================================
7 ?" E$ e% P3 @( l3 A; B7 H+ AM1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ----
1 E9 H5 `0 x1 [$ `2 s3 `M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ----
! S/ Q' v( [( y0 P. E5 b+ o$ f! `Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
" G% y5 S7 N6 `# ^( t3 B, woper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- - A. H0 N: p+ b/ k
Random Number Streams
}0 k8 ~: b* O4 q: L& r, v: vName Total
; e0 v/ k1 Z7 c/ r) ]============================* i2 x+ M# {" _) [8 V5 v3 U
stream0 455
8 b6 Y( f) f" I; O2 fstream_M1_1 0
! A1 ^4 k2 l, P. X9 U* D8 v; b) ^stream_M2_1 01 J) Q. o; D3 s1 `+ P+ ^+ s
stream_Massm_1 0
9 N2 L, i, q5 `( i( I6 x2 L$ }stream_oper_1 0
0 n" E- F/ |) |stream_load1_1 184
$ \0 ?9 n$ s3 G! a9 tstream_load2_1 76! B: T" M5 F% H) @) A
stream_dummy_1 0# J9 n2 u8 I( _2 E2 f
" s( `- m8 G- u0 Z" c请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
