本帖最后由 GJM 于 2009-12-5 21:43 编辑 ( s+ k0 J6 D n! c3 J
4 d+ F: z" u9 ^4 ?$ S- M
底下是小弟做AutoMOD里面PDF练习的(Exercise 5.9)逻辑文件但问题是,程序只Run到Machine A和Machine B就没继续下去1 F# u; U, L( l- J/ g
; Q( Y* z7 N0 G& {& H5 d+ t
不知道是哪里出错,另外这题和Exercise7.1的题型类似,请问若要符合Exercise7.1的题意又该如何修改呢?请各位先进指导,谢谢!# q, R" U B& c# s3 t
6 W# A+ m% c/ l/ x* c( S; {( r* w
--------------------------------------------
% X9 [( g' b9 g0 Z1 ?begin P_something arriving+ n: u3 _/ ^ w4 b' L6 V2 O
move into Q_wait8 }5 u9 p/ j+ S/ _
move into nextof(Q_mA,Q_mB,Q_mC)
( t' c _* d4 H7 I+ I, g use nextof(R_mA,R_mB,R_mC) for normal 48, 5 min, D6 G3 `0 E; d
send to nextof(P_mA_down,P_mB_down,P_mC_down,P_mA_clean,P_mB_clean,P_mC_clean)
) u7 t; b" ~2 D% F send to die; c1 Z( d& W% u3 v2 q. @# @5 Z/ [4 ]
end5 ?3 s j. `5 b: Y6 o2 J
. Z! D# E) B7 k" O
begin P_mA_down arriving
7 I& p( @( r$ ]: G Y while 1=1 do / }) ]7 F \: `: U( y
begin6 Z4 K8 q+ E7 c+ E
wait for e 110 min
7 i/ C( ~: V/ E9 S6 J! ~6 g take down R_mA+ s6 n3 x. I4 e* d# H1 G/ h2 B# Y+ Y
wait for e 5 min3 g# E$ }! z* ~
bring up R_mA
4 ~* @! X# w0 \: l( e, I3 E end
2 z; G) a0 @& _; X# Yend
, E0 T' _# s0 L4 Y, C 2 K) u' e1 B5 p# |; L0 b* Y
begin P_mB_down arriving
8 Q+ g9 {4 D3 T while 1=1 do
, @7 Z. ?; t0 O) u, U7 ?5 o. f% k begin
* [) L2 k0 s6 w, l/ q4 B O wait for e 170 min4 v: O, l% J5 A0 { T9 n
take down R_mB. G" O E+ ^1 Y# ]7 m
wait for e 10 min
& ^ }( M i8 W8 X3 e0 I" Z bring up R_mB
/ ?2 E9 v" w8 X3 a7 ~$ h" `: Z end
l& }/ K( w# F- z. Jend
' _: j- v" I0 j8 l4 Q" t5 P % z. F: k9 s2 X) G9 B" P5 Z' G. M; ^
begin P_mC_down arriving
/ @; ^; N6 ]5 X! U2 p# ~* _ while 1=1 do
9 I% k! g% Q& E) O begin* w3 u5 W5 c- ~% u
wait for e 230 min8 i' n' [4 f6 g. E' j
take down R_mC
8 u& u8 r$ ^% G wait for e 10 min
# ^. m5 a+ J! _! U0 I bring up R_mC
: z" Z' \* j0 g- _0 ~ end4 v4 z# s1 B: P7 w
end
# R+ Q W8 B; d, I / z5 X$ Q; o# A) c
begin P_mA_clean arriving5 T: x8 N' n1 h7 e" L# |
while 1=1 do
9 L5 U$ ]# @- Z' I begin
( c/ ]- n1 J3 D% P! `4 W* p* p7 ] wait for 90 min
! r1 Z; Z9 H$ L, G2 S$ t% i take down R_mA
/ m& ]* P" `/ m9 w! ] wait for 5 min5 D. o! q2 R7 k3 `
bring up R_mA
# E" D K- l k1 u( w, c end
$ @1 z# l$ i6 Z2 x& Send$ Z" S$ f5 v+ F% L' T! Q9 Q, k9 g1 d
. T; F9 [4 X0 I: ~begin P_mB_clean arriving
1 o" a: ^6 Y# [3 I' \, Y; W while 1=1 do
: e+ E- M/ W: w begin8 ?/ X/ w* B7 w, V& w
wait for 90 min
( f6 ^+ ~4 _) o/ e# [5 {8 W take down R_mB
" V1 L% {7 j; ^+ L- i$ k wait for 5 min G3 [: {7 j& |' a" K
bring up R_mB$ F6 R i5 g n3 r7 q
end. v4 m( L1 w7 M$ ?
end: Q0 H6 H: n+ h6 E, E
* _9 u% Q1 V! T) N
begin P_mC_clean arriving, N$ y$ k/ b- m# E
while 1=1 do
+ U6 T" q, ]2 x& \9 O4 f begin
# P- Q+ ^, ^3 i3 H+ X5 x/ { wait for 90 min! k, [" G5 k" O
take down R_mC$ V( D; R: Z6 P% x9 r
wait for 10 min9 S7 x! @3 U2 G/ I
bring up R_mC' C2 [8 g% F j; X7 P5 |% K* K" C! q
end8 t5 A9 D7 d9 l' y' M; o& R! U0 \9 \
end) G; x: _8 P! A* E2 _* ~$ V
----------------------------------------! K& B+ x1 I9 L- p& h4 l
( z" E2 C' x2 u+ A4 {
Exercise 5.9
7 m: ?: k! p# `# K$ I* _3 N$ b T+ {- \+ t! C1 `1 `3 c$ K
0 p7 p& W% x) X7 m2 }' }
Create a new model to simulate the following system:/ `4 c6 y; \9 [& U H
Loads are created with an interarrival time that is exponentially
: [( x- `# U1 b% ~# C2 n: ?; x: Bdistributed with a mean of 20 minutes. Loads wait in an infinite-9 E1 ?+ x# M+ a$ v* F8 ?/ n
capacity queue to be processed by one of three single-capacity,
( f8 d9 n1 L, I6 J+ sarrayed machines. Each machine has its own single-capacity queue
! z' ^: f6 f$ S: o+ i! |: e E& wwhere loads are processed. Waiting loads move into one of the three 5 b. x0 P: M- |7 y. |3 D
queues in round-robin order. Each machine has a normally , }( M7 j' }9 @! s
distributed processing time with a mean of 48 minutes and a standard
# g, A; Z; e: I9 s, Odeviation of 5 minutes./ [* h0 s2 h7 X6 v4 o
The three machines were purchased at different times and have c" |' }, [ w6 P" `7 z0 C% m
different failure rates. The failure and repair times are exponentially
2 B$ b7 D* k+ Z, Y6 Q3 sdistributed with means as shown in the following table: ' E* a9 h- W' ?* \ f; Q
Note The solution for this assignment is required to complete 9 p }1 n+ l7 ?8 S
exercise 7.1 (see “Exercise 7.1” on page263); be sure to save a copy of 0 l3 @6 m5 L6 O5 j% K' N
your model. % H4 Q, _# K Y# T: N
" o# S+ T" w8 M# k) i* w. E
MachineMean time to failMean time to repair
6 M# t, `* M$ N7 p; ~0 y2 \+ w2 yA110 minutes 5 minutes3 G$ o8 h: _( h. o$ ?' S1 n! I
B 170 minutes 10 minutes
0 k1 L/ x) O) E) z$ Y, lC230 minutes 10 minutes) A# n; G% o/ Y' y5 | w
( C) l0 u; F% ]3 wThe machines also must be cleaned according to the following * V) e1 s' W4 n
schedule. All times are constant: - s! a' w6 ]6 i# e0 v
" p+ }- Q8 c& f- J9 e3 V4 s8 t; g2 e
MachineTime between cleanings Time to clean
! U# {' A3 A* W# VA90 minutes 5 minutes
6 Y8 Y8 w8 @+ o/ VB 90 minutes 5 minutes
5 n, l$ T! P0 {- F7 hC90 minutes 10 minutes( [. i) D) e$ A# c
& M q L* ~7 G/ z% c oPlace the graphics for the queues and the resources.
8 O: s! E' k6 o! L+ i/ e& v4 ?Run the simulation for 100 days.
: X! r/ T+ R Q4 z7 F( X1 W% PDefine all failure and cleaning times using logic (rather than resource
" @! }/ q/ a" m( V- E# Q( Ecycles). Answer the following questions:
9 G; ]1 B0 A, Z6 {7 a% {a.What was the average number of loads in the waiting queue?
9 B! g4 o2 i$ R5 w9 Hb.What were the current and average number of loads in Space? 3 v% V% r3 o# a4 ?+ \$ ^% a9 S% ^2 O
How do you explain these values?
: J# D! D/ ?. r+ Y) l7 Q6 S5 n7 x |