本帖最后由 GJM 于 2009-12-5 21:43 编辑
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9 |. L1 F! I z$ l" m, M; V& s底下是小弟做AutoMOD里面PDF练习的(Exercise 5.9)逻辑文件但问题是,程序只Run到Machine A和Machine B就没继续下去
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不知道是哪里出错,另外这题和Exercise7.1的题型类似,请问若要符合Exercise7.1的题意又该如何修改呢?请各位先进指导,谢谢!
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begin P_something arriving% K8 d' Q' Q! B) d
move into Q_wait
0 G: b" \1 [$ K, k: D move into nextof(Q_mA,Q_mB,Q_mC)
5 P: U0 ]6 S& Y. n use nextof(R_mA,R_mB,R_mC) for normal 48, 5 min7 f5 K) D/ N* \& N5 ^
send to nextof(P_mA_down,P_mB_down,P_mC_down,P_mA_clean,P_mB_clean,P_mC_clean)
, ^: [7 _7 a! X8 {$ x& } send to die
; k* I0 A/ B% X: |" e& e/ ]end% ?; z+ L3 c+ N# g$ o4 K* T; J! y
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begin P_mA_down arriving7 |8 V; T+ I) u" I, `% b; I5 m
while 1=1 do - r7 L+ x. y# }
begin
' Y2 O) V$ R6 @8 t' d wait for e 110 min6 h+ \1 m1 O) @% y2 d- {
take down R_mA8 {( j2 Q1 d6 j9 K* ^
wait for e 5 min
. R5 M9 l! y+ s7 F2 e. O5 n, ? bring up R_mA
- O) S3 A' N D+ p' w$ |6 W( z8 R end
8 e5 v% G+ S1 x/ ^5 g1 j' ?0 jend
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9 L) p' i% h5 g. x% E7 {begin P_mB_down arriving# \: Q! b% h$ O, m; f& u H
while 1=1 do7 T7 U7 C3 u( L+ o+ Y
begin5 J3 j: G; W, m6 |. q6 B
wait for e 170 min6 y* Y+ M, B2 D8 x* b5 D6 @! B
take down R_mB8 T. o0 y1 k1 I! |9 S) j
wait for e 10 min) [2 M2 J8 d* P" }
bring up R_mB
% i5 J/ n6 K7 W1 i# z/ J: \" y end/ q: p# S2 B' G& _& F6 ^+ A9 h
end
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begin P_mC_down arriving
8 s; V- D+ U: a2 d' V while 1=1 do
! c0 u+ u N8 i5 ~$ u& e begin( Q2 J- E/ ]: q" Y2 y8 Y& W
wait for e 230 min
: |: S5 y' P$ u9 ?3 u take down R_mC
4 P. f* W- U5 E! N wait for e 10 min; G' V3 P. T0 h/ t A. L
bring up R_mC l5 ]1 F8 g$ ^* L. \& i# K7 _
end0 o+ h s( ?6 A) F
end
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* L; L1 `% L! wbegin P_mA_clean arriving8 X( I( I* Z' S
while 1=1 do) a8 c: `7 f6 k1 o
begin
3 J7 F0 |- A( o9 G* C R% t# O$ p1 U( x* y wait for 90 min
! W3 x; V. n9 @3 @* P3 @9 _ take down R_mA+ j' l# a3 q8 _9 A/ @
wait for 5 min
4 Z9 y& e1 L- n: n& ?9 S& ^ bring up R_mA q, w& m: z5 |) p+ U) d6 g
end
, m( X4 K/ P# N( V' `end
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6 Q! A! w9 Z' d3 |2 O) jbegin P_mB_clean arriving. `/ k1 R$ d' \/ [# k& B
while 1=1 do8 r8 |! i5 U; @% j2 L/ D
begin
1 |3 G9 L5 I, V) ]3 d$ `. | wait for 90 min9 Z' C; x$ s- L0 _2 X$ |
take down R_mB
6 o( h( f! i: j# B& M wait for 5 min5 \1 I( \' L) J
bring up R_mB
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end7 a8 K" b) `2 n4 b2 S1 k( ?
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begin P_mC_clean arriving
1 {( {/ I5 M% K/ i* L while 1=1 do
: e. k! A; o+ u, G) t7 ~ begin+ L1 x$ j0 _" v- O( R# }
wait for 90 min1 V9 N/ w2 M1 `; R5 w! r$ [, B
take down R_mC
# T) T, \/ I4 v' _9 l! e0 C wait for 10 min2 ~" n2 W& _( H8 Q( {$ c% I5 m4 W# Y; j
bring up R_mC
8 `) `" |$ c1 [2 j end
, D$ G1 _* X: D! ~9 Vend
/ j; B5 B* k3 k# B8 t3 Z----------------------------------------
7 T5 a: D G) L, X
5 A1 b& M0 K m0 wExercise 5.9! v" F/ w6 \6 o% Y8 L. o- _4 s
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+ O$ v8 o1 T# v$ q; hCreate a new model to simulate the following system:
* ]3 k( G: `: l+ H% SLoads are created with an interarrival time that is exponentially ) n W0 Z, i h7 Y4 R. I
distributed with a mean of 20 minutes. Loads wait in an infinite-
0 o( D, A% L: Rcapacity queue to be processed by one of three single-capacity,
' b8 p: [4 P; g8 N7 Warrayed machines. Each machine has its own single-capacity queue 6 O4 R4 W8 Z: n; P" B! ~7 M; t: l6 N
where loads are processed. Waiting loads move into one of the three
6 p8 X) A+ z; ]) Cqueues in round-robin order. Each machine has a normally
# o. r2 l5 O9 U6 b) ]5 x: I9 }% ~* Wdistributed processing time with a mean of 48 minutes and a standard
7 t; U, ~9 R- E, e5 N5 r- G3 Pdeviation of 5 minutes.
/ e ?8 X- H4 GThe three machines were purchased at different times and have + o3 w; z- M% s
different failure rates. The failure and repair times are exponentially 9 v' {7 D! I8 v J7 J7 D; A1 V; s
distributed with means as shown in the following table:
. D. K. _! {4 c# v i: zNote The solution for this assignment is required to complete
- r* I$ y5 d' i! {exercise 7.1 (see “Exercise 7.1” on page263); be sure to save a copy of % ?5 Z& e! \' v& R" k0 i
your model. 5 X0 @0 _6 C( H: C
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MachineMean time to failMean time to repair8 A/ o# i( ^+ r
A110 minutes 5 minutes
5 h0 @) {6 @4 T5 f7 f( }9 ~, zB 170 minutes 10 minutes
* u: x7 Z: B( m6 E# I; AC230 minutes 10 minutes c5 L: W& D, N0 @% ~
% E& s: T4 |& l- vThe machines also must be cleaned according to the following C8 e" w/ L8 I l# }+ K
schedule. All times are constant:
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( {" \! g2 z+ R' ^2 C6 CMachineTime between cleanings Time to clean
9 k7 u P/ l) V; e" cA90 minutes 5 minutes
/ e. A+ l! t- l# j1 [6 K* _B 90 minutes 5 minutes* n x- ]) q5 `# P+ J7 n# y' H8 k5 I: c
C90 minutes 10 minutes
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Place the graphics for the queues and the resources. U4 o) f) K4 b- P" ^# K
Run the simulation for 100 days.1 z7 G7 T: F9 |5 H( r+ O* }
Define all failure and cleaning times using logic (rather than resource - C% `- d8 F5 x$ [( m3 c
cycles). Answer the following questions:
& H/ J4 R! k9 \) ya.What was the average number of loads in the waiting queue?% u1 O7 v9 B: Z
b.What were the current and average number of loads in Space? 0 Z \- ~, C0 E4 N+ u/ b8 V
How do you explain these values? 3 r8 M2 U4 u3 r! _; f* X& u* E- m
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