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发表于 2010-5-11 13:19:52
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用list吧
% s! M" h6 J' B& Qpatches-own [wealth rank]
3 t( U/ G. ~4 o. Fto setup
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ask patches [set wealth random 100 set pcolor green ]' c5 X$ y' E7 U6 S4 a" y
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to go
% X$ L0 r, F8 V& w. l2 a" A let mylist1 []
+ x8 M: P% `9 \/ Q# l set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
" O. m, Q5 B: a3 g' w& ~ let mylist2 []# X6 {5 f0 b/ E# ~- K; M
set mylist2 n-values count patches [? + 1]+ M' t- @6 A/ y" p
. p% Z7 D+ o% D5 D8 `9 z4 y ( foreach mylist1 mylist2
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ask ?1[ set rank ?2]) |9 l) L. w- s" Q0 c0 f2 Z
show [rank] of ?1
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let mylist3 []& y% n Y- N. c9 B
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
7 X+ L! p5 ^* p4 C$ a* ^$ z show count patches! d4 n s' Z' m7 [
show mylist1 2 j1 ]* E) ?2 N( k: D4 \7 a
show mylist3
$ C) O4 r# s, y- W' gend
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+ U& I8 A, {5 I1 O3 J4 z这时的mylist1 和mylist3 应该是一样的 |
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