设为首页收藏本站

最大的系统仿真与系统优化公益交流社区

 找回密码
 注册

QQ登录

只需一步,快速开始

查看: 7738|回复: 0

[求助] 问jheatbugs-2001-03-28中某些代码

[复制链接]
发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:$ S2 k5 E( m+ J" b7 J

' b; H9 R7 f, ?, |  t( e9 W public Object buildActions () {
2 [1 g0 t7 ^+ Q4 x5 y! V8 y7 p8 ]    super.buildActions();
9 \1 }1 S3 Z) V* @9 y6 R/ \- N    4 r# a7 k4 W1 I: X% L$ F
    // Create the list of simulation actions. We put these in
( |) a0 I1 i! I- K    // an action group, because we want these actions to be6 [  R, o) J1 f, {  T
    // executed in a specific order, but these steps should
4 R& `) w2 _/ O6 ?$ a    // take no (simulated) time. The M(foo) means "The message: s* ^. \) v( W# l, E
    // called <foo>". You can send a message To a particular8 R% b1 y; u" U1 F3 L4 K
    // object, or ForEach object in a collection.
8 h8 F4 M, T0 k0 J/ }7 n        
& q- E- E- j7 a' v    // Note we update the heatspace in two phases: first run8 q  ~& _2 Q, f( V2 F3 O+ i, I
    // diffusion, then run "updateWorld" to actually enact the  G5 W, w" Q; {7 I! N
    // changes the heatbugs have made. The ordering here is
- K# O' L5 J8 I5 M    // significant!, `3 J) [9 u4 Y& l
        
" A8 J& @: x: x! F  \    // Note also, that with the additional! ?1 @( o) H2 `& q" [+ n/ D# r  A
    // `randomizeHeatbugUpdateOrder' Boolean flag we can
" ~3 p* }4 m4 z- f1 K* p  w    // randomize the order in which the bugs actually run' z  @& S6 Z' j, {) |* U
    // their step rule.  This has the effect of removing any# H4 o7 T& p" X) c7 v7 j
    // systematic bias in the iteration throught the heatbug
" r$ U# T( w$ H* D4 |3 `2 Q    // list from timestep to timestep
( T- D" K4 j6 N: e1 ~* n$ A        
, p& F9 i5 J- {7 }    // By default, all `createActionForEach' modelActions have% o9 w7 |0 C' I( x; ]- N
    // a default order of `Sequential', which means that the; V3 F, H( [6 p) ^1 V$ p
    // order of iteration through the `heatbugList' will be7 |% j, S9 k6 x& A
    // identical (assuming the list order is not changed
5 v; o/ s  e2 _  Q! P    // indirectly by some other process).
1 k  i& A: _2 P1 ^+ _8 O! |- L   
) F& i* S6 ~' v/ f' T. U    modelActions = new ActionGroupImpl (getZone ());2 G/ F: [- i& T2 G
/ ^9 t/ O. H& d  X3 }
    try {( C7 ~1 O  e/ ]5 L* L* v3 `
      modelActions.createActionTo$message% ]. E, B! e: V- e) L( j
        (heat, new Selector (heat.getClass (), "stepRule", false));% W0 E2 e7 M: G) j6 t- g
    } catch (Exception e) {
  D2 h1 p: l3 ?) a8 \, f      System.err.println ("Exception stepRule: " + e.getMessage ());  M1 t' l1 V+ O1 i# [
    }
4 q4 W% X- J6 R3 g: K9 r: w6 F  @  i8 V# \+ f' x* w7 {: o) ]
    try {, ]$ f3 U: H% X% _+ w; W4 _
      Heatbug proto = (Heatbug) heatbugList.get (0);
; i& P: b0 y! u: R      Selector sel =
! R: w, \7 ?2 n0 M' a/ f" O        new Selector (proto.getClass (), "heatbugStep", false);6 D  ^/ h5 z7 s
      actionForEach =% S( Q% k0 K) g
        modelActions.createFActionForEachHomogeneous$call+ K/ V0 R! u7 ^5 a" [, N+ g
        (heatbugList,
1 r4 d& _/ ?" Z         new FCallImpl (this, proto, sel,
  {3 l  q8 v# t: }                        new FArgumentsImpl (this, sel)));! T, V/ v% w# `' U
    } catch (Exception e) {. h/ W3 ]! o/ F  W  B4 U9 v" x
      e.printStackTrace (System.err);9 D* A4 l$ a7 a6 @- g, S
    }
+ r4 z1 J, O( v+ E# x   
; u5 Q9 a* @0 _; i# e    syncUpdateOrder ();9 u6 m( ~+ w4 q% C
  ?5 }3 Q3 ]  e
    try {' H( E7 W, I  j) J4 `6 O: I
      modelActions.createActionTo$message 2 R* l# q: y5 e. ^0 L9 {$ Y1 \
        (heat, new Selector (heat.getClass (), "updateLattice", false));
" w! ?4 L' x2 C; K    } catch (Exception e) {
5 E: P! ]* S9 r( N' J8 h/ V      System.err.println("Exception updateLattice: " + e.getMessage ());  x+ R) b: d9 U* V5 j8 C. c
    }
6 W1 X+ r; T; o2 o, m1 a        2 E4 A# E! A3 U0 w; a
    // Then we create a schedule that executes the
, X8 d+ j/ d8 ~* J    // modelActions. modelActions is an ActionGroup, by itself it
  M0 @9 G5 y; u' R+ x$ |    // has no notion of time. In order to have it executed in
" |6 Y% q* d5 u) Z. u    // time, we create a Schedule that says to use the  D, n8 K9 i: i$ V+ h& v2 ?; m
    // modelActions ActionGroup at particular times.  This
3 |* T6 G( k8 u8 f, Q    // schedule has a repeat interval of 1, it will loop every
; P1 I2 B4 Y6 i% Q    // time step.  The action is executed at time 0 relative to
5 A1 S7 }3 m0 u' R    // the beginning of the loop.+ ^1 \1 f4 _* t2 q6 N

; E7 [" X$ y' u0 o* {% N    // This is a simple schedule, with only one action that is2 v1 n; @$ i/ h- N3 F3 R9 q7 z
    // just repeated every time. See jmousetrap for more
( Q8 C6 n  `4 L( G* h    // complicated schedules.
/ g3 p2 B* g: V+ Q- z* _  6 z$ ]% J: R+ O& M, n; I1 C
    modelSchedule = new ScheduleImpl (getZone (), 1);7 [: b' I7 C. e
    modelSchedule.at$createAction (0, modelActions);
* R# h# h+ \2 Y7 e1 K9 {  o        
& x5 H7 O" o8 [) w6 @4 Q0 c! P3 y    return this;) N/ \! J5 d/ g
  }
您需要登录后才可以回帖 登录 | 注册

本版积分规则

QQ|Archiver|手机版|SimulWay 道于仿真   

GMT+8, 2025-11-8 03:49 , Processed in 0.018628 second(s), 11 queries .

Powered by Discuz! X3.4 Licensed

© 2001-2017 Comsenz Inc.

快速回复 返回顶部 返回列表