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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:
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6 g8 ^3 |3 s# ` public Object buildActions () {7 i9 H. P: \$ a% l7 `5 U8 W
    super.buildActions();
9 U2 ?1 m* `$ j6 J2 z& N( |   
2 ?2 `$ R! G) f, t( E* k    // Create the list of simulation actions. We put these in% E" z; `% t% Q: }9 g( |
    // an action group, because we want these actions to be; Y' _4 _+ h) l* q9 W$ Q
    // executed in a specific order, but these steps should
: [; r( L) K" x8 U    // take no (simulated) time. The M(foo) means "The message# j3 L3 Q- b( h# b: ]" p5 V
    // called <foo>". You can send a message To a particular! j  I1 d0 o# P1 ^5 k$ X- ?5 \! V
    // object, or ForEach object in a collection.
) F) |& ]1 b1 s        
3 d. h2 {  \% ]( p/ W& d7 u) a    // Note we update the heatspace in two phases: first run9 g( A' }) Y" `1 m" ^; C" y* ^* E
    // diffusion, then run "updateWorld" to actually enact the
1 s" `6 @7 d1 K' `* o+ M* E    // changes the heatbugs have made. The ordering here is& z( M- [5 I0 W; N5 S- E# M$ P
    // significant!; b4 x8 {; R1 M9 N9 F
        7 C4 v. S: O9 h! Y9 b2 M) D, m- ~5 S
    // Note also, that with the additional& k' v+ W5 W2 U
    // `randomizeHeatbugUpdateOrder' Boolean flag we can2 L6 M! @* a: P0 p: {% z0 S9 y! j" h1 L
    // randomize the order in which the bugs actually run" R7 H& q0 y: t! ^" D
    // their step rule.  This has the effect of removing any9 C4 j$ G% A, I2 W
    // systematic bias in the iteration throught the heatbug" H& V, Z" u) n7 Y% r& h+ _
    // list from timestep to timestep
0 V# b, S  }5 C$ f% E+ F8 F( g2 V        
; ~$ @' _5 G: `3 ]# s3 u& T) ?; m    // By default, all `createActionForEach' modelActions have; c# q; G1 @, V4 e$ x; Z7 W* _0 h
    // a default order of `Sequential', which means that the6 m+ i' r. x! o' p" ~( d9 _  V6 V
    // order of iteration through the `heatbugList' will be0 O2 {8 z* \% }  v) x1 x# o% V6 X# M# W
    // identical (assuming the list order is not changed
: h0 r0 b3 t, R' Z    // indirectly by some other process).4 i5 b' _$ e$ o
    % ]1 x, b. D' |: K8 B$ ^3 D
    modelActions = new ActionGroupImpl (getZone ());0 a% W5 r" v3 E9 j  V/ T$ L% y
5 V( C0 E& V/ O7 X# H5 x: |
    try {6 F# H; \# A' {4 ]1 \! i! T
      modelActions.createActionTo$message' K  j/ g( r' p
        (heat, new Selector (heat.getClass (), "stepRule", false));) h$ G* W. J2 P/ }! p
    } catch (Exception e) {
; o; X) h3 m- \0 A      System.err.println ("Exception stepRule: " + e.getMessage ());
# Q- K$ f9 [" v' k2 e    }
& d: k; ~4 I- [% T! Q9 m4 |) [3 _4 i- c2 v5 T
    try {
1 d3 {: }; W5 d; A/ v2 C      Heatbug proto = (Heatbug) heatbugList.get (0);) g; q9 X3 g) J
      Selector sel =
- G7 t  ?! M  O. B3 G        new Selector (proto.getClass (), "heatbugStep", false);9 I- ?4 h5 _% _! |1 {
      actionForEach =
( ?0 _8 E" R. c        modelActions.createFActionForEachHomogeneous$call
* w& ^9 z* q5 W. ~  a& A( \& u) Q        (heatbugList,
+ N' f4 V$ `0 R% d. r; u; I9 r/ ?         new FCallImpl (this, proto, sel,
# W. j6 i, R; C3 d                        new FArgumentsImpl (this, sel)));
) Y) [/ q" r+ a" S2 Z# w" I1 I* e: [    } catch (Exception e) {  r, P1 d# K9 |9 U1 a
      e.printStackTrace (System.err);
' B# a% ]" n# u" J! ~    }% X* {5 u4 Q% J- q0 `7 U+ q* E, S
    / x" ~) ^  j& [* _
    syncUpdateOrder ();
3 X$ X- t7 x: X/ M. k9 K1 \( K4 |) @+ i! H, n6 P
    try {3 D' S7 M9 H  M2 t% b, u( f: U
      modelActions.createActionTo$message ( f% O. B; p/ o2 m
        (heat, new Selector (heat.getClass (), "updateLattice", false));
* `  D% n) {, r- {' r4 ]% H+ U    } catch (Exception e) {
% x* w4 R/ j2 o      System.err.println("Exception updateLattice: " + e.getMessage ());7 i# y* N3 f: D% E, ~8 n& \
    }8 ~. q  R$ h! j% {4 k7 P
        $ P$ z+ E0 Q" Z# l9 o
    // Then we create a schedule that executes the
% b- P( p& Y2 i4 C8 d    // modelActions. modelActions is an ActionGroup, by itself it& i, {' p7 T' ]( {2 m6 e& G
    // has no notion of time. In order to have it executed in" r6 y5 d% X+ l0 d" M2 o
    // time, we create a Schedule that says to use the( T1 w" U0 A5 \
    // modelActions ActionGroup at particular times.  This' g  o- j7 h4 R1 n9 L
    // schedule has a repeat interval of 1, it will loop every* H# k/ ^, a% f0 b' h8 i; j* u- D
    // time step.  The action is executed at time 0 relative to6 q" g8 G7 }0 s
    // the beginning of the loop.
* k# P" P) b& p: \1 ^+ {
( v5 s3 I/ E# k# ?# ~# j    // This is a simple schedule, with only one action that is3 A" p* i7 Q$ Z
    // just repeated every time. See jmousetrap for more
; I, E' w# ~4 ]    // complicated schedules.
' {5 Q2 N, M" y, t# S; ?2 r  
: ?7 P8 Q" m! T, E6 I+ B6 I    modelSchedule = new ScheduleImpl (getZone (), 1);
2 X, s: \- o+ v5 ^6 M1 f    modelSchedule.at$createAction (0, modelActions);( b$ x/ K1 K8 C* J8 H
        
. W  O' w3 S$ K    return this;) a/ Y1 T9 [" A  W- N8 k
  }
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