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[求助] 问jheatbugs-2001-03-28中某些代码

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发表于 2008-5-25 02:15:22 | 显示全部楼层 |阅读模式
5仿真币
HeatbugModelSwarm中buildActions部分,3个try分别是做什么?查了下refbook-java-2.2,解释太简略,还是不懂,高手指点,谢谢!代码如下:5 {& Z& q2 Q/ ~

4 D1 T- _; e% {/ X public Object buildActions () {
# W7 F8 x3 F* B    super.buildActions();
( T0 K' h8 J$ f; x: T1 Y/ b9 Q  U% \    + n/ j6 d9 a0 H4 g7 C7 C8 q
    // Create the list of simulation actions. We put these in, b5 C4 F( d; |4 d* S+ }
    // an action group, because we want these actions to be6 D' w: D0 _, T. ?" N
    // executed in a specific order, but these steps should
4 Y- @# `& p, `    // take no (simulated) time. The M(foo) means "The message9 k+ R! a: S9 q
    // called <foo>". You can send a message To a particular
4 b' M4 K: t4 m" m- P" u    // object, or ForEach object in a collection.# f2 K" s& ~# P. M% Q
        
6 z1 G0 x$ E0 M    // Note we update the heatspace in two phases: first run
6 H# _  G) K4 q. `" ~2 t( K$ i    // diffusion, then run "updateWorld" to actually enact the
7 A( r+ ^, X: d" Z: m0 `    // changes the heatbugs have made. The ordering here is
  b( ~8 p3 ]" q' b5 b# `* q    // significant!
# L' w9 J" ^1 M" j$ R        9 |0 A- q6 K# a' W- A
    // Note also, that with the additional, U& i2 M/ p3 o' a  i. d5 Z3 }
    // `randomizeHeatbugUpdateOrder' Boolean flag we can) \- J; y' {0 l. u/ l  g2 A
    // randomize the order in which the bugs actually run
; ^+ R* g* Q1 @$ K7 C- }    // their step rule.  This has the effect of removing any
8 h6 R  g: E2 m8 m$ Y4 K    // systematic bias in the iteration throught the heatbug
, C8 F6 k6 C. G- R4 V    // list from timestep to timestep
, w2 r2 {7 }3 ~, \        / w% g1 d) B9 O' ~6 `
    // By default, all `createActionForEach' modelActions have: x. Y" ~  z7 L
    // a default order of `Sequential', which means that the
) v( U. H3 R% U  b* S/ ~" |    // order of iteration through the `heatbugList' will be
0 E* V6 x1 S! V    // identical (assuming the list order is not changed0 h0 n7 g/ C: Y! v% O; L
    // indirectly by some other process).
3 v+ N- _6 n9 u! s: u; V+ Z* V0 X* n    9 g6 y1 k. [$ m- t6 o7 N+ q
    modelActions = new ActionGroupImpl (getZone ());; p1 i9 m& W& i% i7 R$ L/ i

( {. Z' K5 |& L    try {
( {: O3 Q, F) C+ @9 ]/ @0 S/ r      modelActions.createActionTo$message
( k( i8 ?2 O3 v3 i" S1 d        (heat, new Selector (heat.getClass (), "stepRule", false));+ {$ l9 w0 D' E; [9 O
    } catch (Exception e) {7 c- L" u. ^- O; l
      System.err.println ("Exception stepRule: " + e.getMessage ());
9 ^' x6 T5 `. W% C/ j) g3 V- J8 y    }0 b' v9 T0 G! {  h
! |, s# f# D+ I
    try {8 _. n' b4 q- P$ S1 ^  ^+ n1 B
      Heatbug proto = (Heatbug) heatbugList.get (0);/ e5 h& J, U* e5 ?+ f
      Selector sel = . P) W$ T' M) g0 Q  C; q- ~
        new Selector (proto.getClass (), "heatbugStep", false);
8 b" v' J, z0 K      actionForEach =
* _0 `! O9 ?. T$ y1 ~- m        modelActions.createFActionForEachHomogeneous$call
' `) B3 B4 d% b8 j' P- ^2 W        (heatbugList,
) T1 p8 J# u  B% Y9 x$ m4 s  s         new FCallImpl (this, proto, sel,! W4 s; q0 {* z7 k5 L
                        new FArgumentsImpl (this, sel)));
3 U' k# e: F& U' W7 c$ p( O4 ?  |    } catch (Exception e) {
8 o6 q  B( K1 u2 c4 f      e.printStackTrace (System.err);  E/ q/ a6 K$ ~# {
    }4 a7 H  k1 B+ i: r# }& v) L
    9 c( ?) B1 Z2 G+ H: T, {
    syncUpdateOrder ();/ z* ^- z6 F5 B/ H; t

% g# z, a( x' e, K, L. ~    try {# G8 q9 Z/ I( [4 T( _
      modelActions.createActionTo$message 0 M) C7 {( x1 v9 u* Z8 i
        (heat, new Selector (heat.getClass (), "updateLattice", false));
4 i' z. \$ j. Q) l# b5 i! u$ g/ y: N    } catch (Exception e) {
# |5 Z4 \: d; [' J- p; [9 G& e- ]9 G      System.err.println("Exception updateLattice: " + e.getMessage ());: q# u& |: W$ K0 k* O
    }" T$ c" P. k" P. b* r
        
  E7 {8 o2 y0 }4 a! j+ t    // Then we create a schedule that executes the
+ N- i/ D+ m* W& N    // modelActions. modelActions is an ActionGroup, by itself it2 y' `( C4 c8 Z3 J5 `3 I& u9 A3 A2 {
    // has no notion of time. In order to have it executed in
/ D' m& g% t/ u" @, j, `    // time, we create a Schedule that says to use the
- u& Q% c9 R$ d2 D3 Y" ^# |    // modelActions ActionGroup at particular times.  This5 r$ q, W: d; M2 ~% a
    // schedule has a repeat interval of 1, it will loop every
7 }4 y& p* c( l9 w& Y( p    // time step.  The action is executed at time 0 relative to6 V6 x2 ?( B! f8 I1 ]; ?; `
    // the beginning of the loop.
4 |( Y" A& P/ o. D4 B0 U# A4 O% j+ B# S
    // This is a simple schedule, with only one action that is
+ ?6 Z% H7 R( s, [4 A    // just repeated every time. See jmousetrap for more1 b* c! N2 ~9 b  `+ _7 g
    // complicated schedules.
2 p! Y( ?8 J" A/ c7 H( A  
. L, a7 a" B4 E! Q8 R8 [    modelSchedule = new ScheduleImpl (getZone (), 1);* O" d# H0 {( u; D% h6 |
    modelSchedule.at$createAction (0, modelActions);
9 o% [1 O) M/ \' v7 t$ ~* f" [" m- W        
; \; Y  n5 m  f* ~4 J7 `$ Z    return this;) I! r  R7 p! G0 t( x/ w# W* L: t4 w& J
  }
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